Intermolecular Forces — Print · Grade 11 Science
Chapter: States of Matter & GasesIntermolecular Forces
Learning goals
- I can identify the intermolecular forces present in a substance: London dispersion, dipole-dipole, and hydrogen bonding.
- I can use the relative strength of intermolecular forces to compare boiling points, melting points, and related properties.
Readings for this unit
Before this unit
Polarity and temporary/induced dipoles.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
What holds a nonpolar molecular liquid together?
Illustrative evidence case. A selected nonpolar substance condenses even though its isolated molecules have no permanent net dipole.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
What holds a nonpolar molecular liquid together?
Your first model
Draw a possible fluctuating electron distribution and distinguish it from ionic charge.
Build the language from the idea
- intermolecular forces (IMFs)
- The attractions between separate molecules, as opposed to the much stronger bonds within a molecule.
- London dispersion forces
- Weak attractions present in ALL molecules, caused by fleeting, temporary dipoles from shifting electrons; stronger in larger molecules with more electrons.
- dipole-dipole forces
- Attractions between the permanently positive end of one polar molecule and the negative end of another.
- hydrogen bonding
- An especially strong dipole-dipole attraction that forms when hydrogen is bonded to N, O, or F and is drawn to a lone pair on the N, O, or F of a neighboring molecule.
- polarity
- An uneven sharing of electrons that leaves a molecule with a positive end and a negative end (a dipole).
- polarizability
- How easily a molecule's electron cloud can be distorted; larger, electron-rich clouds are more polarizable and give stronger dispersion forces.
There are two very different kinds of 'sticking together' in chemistry, and confusing them causes no end of trouble. Inside a molecule, atoms are held by strong chemical bonds — the covalent bonds that make an H₂O molecule, for instance. Between one molecule and its neighbors act much weaker attractions called intermolecular forces (IMFs). Weak though they are, IMFs are the quiet decision-makers of the physical world: they determine whether a substance is a gas, liquid, or solid at room temperature, how high its boiling and melting points are, how thick and syrupy it is, and how strong its surface tension is. When a pot of water boils, it is these IMFs breaking apart — not the sturdy O–H bonds, which survive untouched.
A molecular interaction present even without permanent polarity is London dispersion forces, and here is their surprising feature — all molecular species can exhibit dispersion, including nonpolar molecules without a permanent net dipole. At any instant the electrons in a molecule can slosh slightly to one side, creating a fleeting, temporary dipole that induces a matching dipole in a neighbor, and for a moment they attract. The more electrons a molecule has, and the larger and more polarizable its electron cloud, the stronger these forces grow. That single trend explains why, going down the halogen column, F₂ and Cl₂ are gases, Br₂ is a liquid, and I₂ is a solid at room temperature: same type of force, steadily more of it.
Dipole-dipole forces appear in polar molecules, which carry a permanent positive end and a permanent negative end because their electrons are shared unevenly. These molecules line up so that opposite ends attract, through electric charge-distribution interactions, and for molecules of similar size these contributions add to dispersion; their relative importance depends on the species and orientation. It is why a polar molecule generally boils at a higher temperature than a nonpolar molecule of comparable mass — there is an extra electrical grip to overcome before the molecules can fly apart into a gas.
The standout of the three is hydrogen bonding, a particularly important interaction with a specific donor/acceptor context in common introductory examples. For the usual school N/O/F examples, a hydrogen atom must be bonded directly to one of the three most electronegative atoms — nitrogen, oxygen, or fluorine — and that hydrogen must then be attracted to a lone pair on the N, O, or F of another molecule. When those conditions are met, the attraction is remarkably strong for an IMF. This is the secret behind water's strange and life-giving behavior: an unusually high boiling point for such a small molecule, a solid form (ice) that floats because hydrogen bonds hold the molecules in an open, lower-density lattice, and a surface tension strong enough for insects to walk on.
Property comparisons should combine dispersion, permanent polarity, hydrogen-bond context, size, shape and phase. A simple hydrogen-bonding > dipole > dispersion slogan does not rank every real pair: accumulated dispersion can be substantial, and crystal packing strongly affects melting. Stronger relevant attraction often raises the energy needed for molecular separation in a matched comparison, but a single category label cannot set every boiling point, viscosity or solubility.
Comparing real substances shows the idea in action. At ordinary atmospheric pressure, water (H₂O) boils near 100°C while methane (CH₄), of nearly identical mass, boils at −161°C — because water hydrogen-bonds and methane has only weak dispersion forces. Even two molecules with the *same* formula can differ dramatically: ethanol (C₂H₅OH) has an O–H group and boils at 78°C, while dimethyl ether (CH₃OCH₃), the same atoms rearranged with no O–H, lacks an O–H donor and boils near −24°C at ordinary atmospheric pressure; its oxygen can still accept suitable hydrogen-bond interactions. Reading boiling points like this makes IMFs a detective's tool. And it closes the loop with the rest of this unit: intermolecular forces are exactly the attractions an 'ideal' gas is assumed to lack, which is why gases with weak IMFs behave most ideally and why real-gas phase behavior depends on temperature, pressure and interactions; above the critical temperature, compression alone does not cross an ordinary liquid–gas coexistence boundary.
Model check: Hydrogen bonding is not simply every bond containing H; ordinary boiling does not break covalent molecules apart. All particles have dispersion attractions; larger polarizable electron clouds can produce substantial attraction.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Separate internal bonds from intermolecular attractions
An intramolecular bond connects atoms within a molecule, while intermolecular forces act between molecules. Boiling a molecular liquid generally overcomes enough between-molecule attraction to form vapor without breaking every internal covalent bond. A dotted line often marks an intermolecular interaction, but its meaning must be stated in a caption. Chemical decomposition at high temperature is a different process that can occur under other conditions. Keep species identity and the physical transition separate before explaining the energy required.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Does boiling pure molecular water normally turn each H₂O molecule into H and O atoms?
Visual reasoning — after your attempt
No. Vaporization changes the arrangement and interactions between water molecules; splitting their covalent bonds is a different chemical process.
Intermolecular forces act between molecules, while covalent bonds hold atoms within many molecules. Melting or boiling a molecular substance commonly changes intermolecular organization without decomposing the molecules. Ionic and network solids require different structural accounts, so not every solid can be described with isolated-molecule attractions.
Boiling liquid ethanol normally retains ethanol molecules. Breaking its C–O or C–C bonds would be a chemical process.
Pause and explain
Which interactions mainly change during ordinary molecular boiling?
Check your reasoning after answering
Intermolecular attractions and organization change; the molecules’ internal covalent connectivity usually remains intact.
Part 2 · Include dispersion in every molecular comparison
London dispersion arises from correlated fluctuations in electron distributions and is present in molecular substances, including nonpolar ones. Polarizability describes how readily a distribution is distorted; size and electron structure influence it. Molecular shape also affects how neighboring structures approach. Permanent dipole interactions can add to dispersion rather than replace it. A larger molar mass often accompanies stronger dispersion in a matched family, but mass alone is not the mechanism or a universal boiling-point rule.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why can a nonpolar molecular liquid still have a boiling point above absolute zero?
Visual reasoning — after your attempt
Its molecules still attract through dispersion; lack of a permanent net dipole does not eliminate intermolecular interactions.
London dispersion arises from fluctuating electron distributions and exists in all atoms and molecules. Larger polarizability and suitable contact surfaces can strengthen it. Nonpolar does not mean no attractions, and a large nonpolar molecule can boil higher than a small polar molecule.
Compare related molecules using size and shape as well as permanent dipoles. One polarity label cannot replace a complete interaction comparison.
Pause and explain
Why do nonpolar substances still condense?
Check your reasoning after answering
They experience dispersion attractions. Permanent dipoles are not required for intermolecular attraction or condensed phases.
Part 3 · Identify hydrogen-bonding partners correctly
In common introductory examples, hydrogen bonding involves a hydrogen covalently attached to N, O or F interacting with a suitable neighboring electron-rich region. Water can supply O–H donors and oxygen acceptor sites. A molecule containing any hydrogen atom is not automatically a hydrogen-bond donor, and some molecules accept without donating. Hydrogen bonding is an intermolecular interaction here, distinct from the O–H covalent bond inside water; geometry and chemical context affect its strength.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why does simply finding H atoms in CH₄ not establish the same hydrogen-bond donor pattern as water?
Visual reasoning — after your attempt
Methane’s hydrogens are bonded to carbon, not the strongly polar N–H, O–H or F–H donor pattern used in this introductory comparison.
In common introductory molecular examples, a suitable donor has H covalently bonded to N,O,or F, and an acceptor has an available lone pair. Hydrogen bonding is an attraction involving neighboring sites, not a covalent H bond within one formula. Donor and acceptor capacity can differ.
An ether oxygen can accept hydrogen bonds from water even though the ether lacks an O–H donor. Structure matters more than merely containing H and O.
Pause and explain
Can an oxygen-containing molecule accept without donating hydrogen bonds?
Check your reasoning after answering
Yes. An available oxygen lone pair can accept, while donation requires a suitable bonded hydrogen site in the introductory model.
Part 4 · Make conditional property predictions
Boiling point, viscosity and solubility depend on collective interactions and the state being compared. Stronger attractions can raise the energy needed for molecular separation in a matched comparison, but different shapes, sizes and bonding networks complicate simple rankings. Like dissolves like is a starting heuristic, not a complete free-energy calculation. For dissolving, compare interactions disrupted and formed and the entropy contribution. Use relevant experimental data to test a prediction rather than treating one functional-group label as an exact property value.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why can counting hydrogen-bond sites alone fail to rank every pair of boiling points?
Visual reasoning — after your attempt
Other interactions, molecular size/shape, pressure and the actual structural context also affect the phase behavior.
Stronger relevant attractions often raise boiling temperature for otherwise comparable molecules. Solubility also depends on disrupting solute and solvent interactions and forming new ones, alongside entropy. Compare a stated property at stated conditions rather than treating one interaction ranking as universal.
A polar functional group can improve water interaction, but a long nonpolar chain may reduce overall water solubility. Actual measurements test the balance.
Pause and explain
Why can a polar group not guarantee high water solubility?
Check your reasoning after answering
The whole structure and balance of solute/solvent interactions matter; a large nonpolar region and other effects can outweigh one polar site.
Apply the whole unit · Compare alcohol and ether structures
Illustrative molecules: ethanol CH₃CH₂OH and dimethyl ether CH₃OCH₃ have the same formula C₂H₆O. Use their supplied connectivity and compare pure-molecule interaction types.
Your task
Identify dispersion, polar interactions, and hydrogen-bond donor/acceptor roles; predict which has stronger self hydrogen bonding, and explain why the same formula alone cannot establish identical boiling behavior.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
Both have electrons and therefore dispersion attractions.
Ethanol has O–H and oxygen lone pairs, supporting donor and acceptor roles.
Dimethyl ether has an oxygen acceptor site but no O–H donor.
Compare pure self-interactions rather than assuming water is present.
Ethanol supports stronger self hydrogen-bonding networks in this comparison and is expected to have the higher boiling temperature. Dimethyl ether can accept hydrogen bonds from suitable partners such as water but lacks its own O–H donor. Shared formula and molar mass do not establish identical structure or interactions; reference data can test the prediction.
Scientific references and source-model foundations
Parent / teacher teaching notes
Ask students to circle donor bonds and mark acceptor lone-pair sites. Separate pure-substance interactions from interactions after mixing with a solvent. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
The key idea
Dispersion, permanent-dipole interactions and suitable hydrogen-bonding contexts contribute to molecular behavior. Compare the full structure, size, shape and conditions rather than use one universal force-strength or melting-point ranking.
Worked examples
Example 1
- All three are nonpolar diatomic molecules, so their only intermolecular force is London dispersion.
- Dispersion forces grow stronger with more electrons and larger, more polarizable electron clouds; molecular size increases F₂ < Cl₂ < Br₂.
- Stronger dispersion forces mean a higher boiling point, so the order matches the size order.
Example 2 · Worked application
- Boiling requires overcoming intermolecular attractions.
- Hydrogen bonding can add relatively strong attractions in suitable molecules.
- Stronger attractions often require higher temperature for a given vapor pressure.
Molecular size and shape can change the result; do not use one factor as a universal ranking.
Example 3
- Ethanol has an O–H group, so its molecules can hydrogen-bond to one another.
- Dimethyl ether has its oxygen between two carbons (no O–H), so it cannot hydrogen-bond — only weaker dipole-dipole and dispersion forces act.
- Stronger intermolecular forces raise the boiling point, so ethanol boils higher.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: Molecular size and shape can change the result; do not use one factor as a universal ranking.
- Ordinary boiling separates molecules without generally changing their covalent identities.
Molecular size and shape can change the result; do not use one factor as a universal ranking.
Example 5 · Reason from the visual model
- In common introductory examples, hydrogen bonding involves a hydrogen covalently attached to N, O or F interacting with a suitable neighboring electron-rich region. Water can supply O–H donors and oxygen acceptor sites. A molecule containing any hydrogen atom is not automatically a hydrogen-bond donor, and some molecules accept without donating. Hydrogen bonding is an intermolecular interaction here, distinct from the O–H covalent bond inside water; geometry and chemical context affect its strength.
- Methane’s hydrogens are bonded to carbon, not the strongly polar N–H, O–H or F–H donor pattern used in this introductory comparison.
Original selected water-pair interaction. The dotted line is a qualitative hydrogen-bond connection, not an extra covalent bond or measured angle.
Avoid these mistakes
- Hydrogen bonding is not simply every bond containing H; ordinary boiling does not break covalent molecules apart.
Check your understanding
Why can nonpolar molecules still condense?
Discuss the answer
All particles have dispersion attractions; larger polarizable electron clouds can produce substantial attraction.
Return to the phenomenon
Return to the initial case. What holds a nonpolar molecular liquid together? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
Correlated instantaneous and induced distortions produce dispersion attractions. Permanent polarity is not required, and the molecular structure remains distinct from the between-molecule interaction.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. What holds a nonpolar molecular liquid together? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
Correlated instantaneous and induced distortions produce dispersion attractions. Permanent polarity is not required, and the molecular structure remains distinct from the between-molecule interaction.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
A student says a nonpolar molecule has no attractions and boiling always breaks covalent bonds. Correct both claims and identify the scale of the relevant interaction.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
Nonpolar molecules still experience dispersion attractions between molecules. Ordinary vaporization of a stable molecular substance mainly changes intermolecular arrangement/interactions, while breaking its internal covalent bonds is a chemical change requiring a different account.
Words to know
- intermolecular forces (IMFs)
- The attractions between separate molecules, as opposed to the much stronger bonds within a molecule.
- London dispersion forces
- Weak attractions present in ALL molecules, caused by fleeting, temporary dipoles from shifting electrons; stronger in larger molecules with more electrons.
- dipole-dipole forces
- Attractions between the permanently positive end of one polar molecule and the negative end of another.
- hydrogen bonding
- An especially strong dipole-dipole attraction that forms when hydrogen is bonded to N, O, or F and is drawn to a lone pair on the N, O, or F of a neighboring molecule.
- polarity
- An uneven sharing of electrons that leaves a molecule with a positive end and a negative end (a dipole).
- polarizability
- How easily a molecule's electron cloud can be distorted; larger, electron-rich clouds are more polarizable and give stronger dispersion forces.
The number-one chemistry mix-up: bonds vs. attractions
When water boils away in a pot, what breaks? Not the water molecules — the sturdy O–H covalent bonds inside each H₂O survive completely intact, which is why steam is still water and not loose hydrogen and oxygen. What actually pulls apart are the far weaker intermolecular forces between separate molecules. The gap in strength is huge: a hydrogen bond is only about a twentieth as strong as the covalent bond it sits next to. Confusing the two — thinking boiling or melting breaks chemical bonds — is the single most common error in this whole unit.
Hydrogen bonds hold your DNA together
The famous double helix of DNA is zipped shut by hydrogen bonds between its base pairs: adenine grips thymine with two hydrogen bonds, and guanine grips cytosine with three. That strength is perfectly tuned — individually the bonds are weak enough that an enzyme can 'unzip' the two strands to copy them, yet collectively, over millions of base pairs, they are strong enough to keep your genetic code stable for a lifetime. The same hydrogen bonds fold proteins into the precise shapes that let them do their jobs. Life quite literally runs on intermolecular forces.
Everything strange about water traces to one force
Water breaks the rules for a molecule its size, and hydrogen bonding is behind nearly every oddity. It is why ice floats — the hydrogen bonds lock frozen water into an open, lower-density lattice, so lakes freeze from the top down and fish survive the winter beneath. It gives water an enormous capacity to soak up heat, which moderates Earth's climate, and a surface tension strong enough for a water strider to walk across a pond. That same clinginess even lets water climb the inside of the tallest trees, hauling itself up to the highest leaves.
Who discovered these invisible forces?
The weak attractions between molecules are named for Johannes van der Waals, the Dutch physicist who, in correcting the ideal gas law, realized real molecules must gently pull on one another — work that won him the 1910 Nobel Prize in Physics. The strongest of them, the hydrogen bond, was identified and named later, by the American chemists Wendell Latimer and Worth Rodebush in 1920, to explain water's peculiar behavior. It is a satisfying loop: the very forces that make the ideal gas law imperfect are the ones that give liquids and solids their character.
Why water beads on a waxed car but soap makes it spread
Splash water on a freshly waxed hood and it pulls itself into tight beads — the hydrogen bonds between water molecules tug inward, minimizing the surface in a display of surface tension. Add a drop of dish soap and the beads instantly collapse and spread flat. Soap molecules are surfactants, with one end that loves water and one end that flees it, so they wedge into the surface and disrupt the water's grip on itself. That same trick is how soap lifts greasy dirt: it surrounds oil droplets that plain water, held together by its own strong forces, simply cannot touch.
In the real world
Geckos climb glass using nothing but London dispersion forces: millions of microscopic hairs on their toes make so much combined contact that these individually feeble forces add up to support the animal's whole weight.
Exit check
Why can nonpolar molecules still condense?
Check your explanation after answering
All particles have dispersion attractions; larger polarizable electron clouds can produce substantial attraction.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Problem 1
- London dispersion forces
- dipole-dipole forces
- hydrogen bonding
- ionic bonding
Answer and explanation
London dispersion forces
London dispersion forces arise from temporary dipoles and act in every molecule, even nonpolar ones.
Problem 2
- another hydrogen
- nitrogen, oxygen, or fluorine
- carbon
- any metal
Answer and explanation
nitrogen, oxygen, or fluorine
Hydrogen bonding requires H bonded to a highly electronegative N, O, or F atom.
Problem 3
- Cl₂
- CH₄
- H₂O
- CO₂
Answer and explanation
H₂O
Water has H bonded to O, so it can hydrogen-bond; the others lack H attached to N, O, or F.
Problem 4
- weaker dispersion forces
- no intermolecular forces at all
- hydrogen bonding
- stronger dispersion forces and a higher boiling point
Answer and explanation
stronger dispersion forces and a higher boiling point
A larger, more polarizable electron cloud produces stronger London dispersion forces, which raises the boiling point.
Problem 5
Answer and explanation
Water molecules hydrogen-bond to one another (H attached to O is attracted to the O of neighbors), a strong intermolecular force, so a great deal of energy is needed to separate them into a gas. Methane is nonpolar with only weak London dispersion forces, so its molecules pull apart at a very low temperature.
Problem 6
- Ne < Kr < Xe
- Xe < Kr < Ne
- Kr < Ne < Xe
- they all boil at the same temperature
Answer and explanation
Ne < Kr < Xe
Dispersion forces increase with size and number of electrons (Ne < Kr < Xe), so boiling point rises in the same order.
Problem 7
Hints
Molecular size and shape can change the result; do not use one factor as a universal ranking.
Answer and explanation
Temporary and induced charge fluctuations produce London dispersion forces.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
No. Size and polarizability strengthen dispersion; compare the complete set of interactions.
Problem 9
Answer and explanation
Methane’s hydrogens are bonded to carbon, not the strongly polar N–H, O–H or F–H donor pattern used in this introductory comparison.
In common introductory examples, hydrogen bonding involves a hydrogen covalently attached to N, O or F interacting with a suitable neighboring electron-rich region. Water can supply O–H donors and oxygen acceptor sites. A molecule containing any hydrogen atom is not automatically a hydrogen-bond donor, and some molecules accept without donating. Hydrogen bonding is an intermolecular interaction here, distinct from the O–H covalent bond inside water; geometry and chemical context affect its strength.
Methane’s hydrogens are bonded to carbon, not the strongly polar N–H, O–H or F–H donor pattern used in this introductory comparison.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
Nonpolar molecules still experience dispersion attractions between molecules. Ordinary vaporization of a stable molecular substance mainly changes intermolecular arrangement/interactions, while breaking its internal covalent bonds is a chemical change requiring a different account.
Nonpolar molecules still experience dispersion attractions between molecules. Ordinary vaporization of a stable molecular substance mainly changes intermolecular arrangement/interactions, while breaking its internal covalent bonds is a chemical change requiring a different account.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.