Intermolecular Forces — Practice · Grade 11 Science
Chapter: States of Matter & GasesWhat this practice covers
By the end of Intermolecular Forces you should be able to:
- I can identify the intermolecular forces present in a substance: London dispersion, dipole-dipole, and hydrogen bonding.
- I can use the relative strength of intermolecular forces to compare boiling points, melting points, and related properties.
10 questions, multiple choice and written answer, each with a worked explanation.
Vocabulary used: intermolecular forces (IMFs), London dispersion forces, dipole-dipole forces, hydrogen bonding, polarity, polarizability.
Problem 1
- London dispersion forces
- dipole-dipole forces
- hydrogen bonding
- ionic bonding
Answer and explanation
London dispersion forces
London dispersion forces arise from temporary dipoles and act in every molecule, even nonpolar ones.
Problem 2
- another hydrogen
- nitrogen, oxygen, or fluorine
- carbon
- any metal
Answer and explanation
nitrogen, oxygen, or fluorine
Hydrogen bonding requires H bonded to a highly electronegative N, O, or F atom.
Problem 3
- Cl₂
- CH₄
- H₂O
- CO₂
Answer and explanation
H₂O
Water has H bonded to O, so it can hydrogen-bond; the others lack H attached to N, O, or F.
Problem 4
- weaker dispersion forces
- no intermolecular forces at all
- hydrogen bonding
- stronger dispersion forces and a higher boiling point
Answer and explanation
stronger dispersion forces and a higher boiling point
A larger, more polarizable electron cloud produces stronger London dispersion forces, which raises the boiling point.
Problem 5
Answer and explanation
Water molecules hydrogen-bond to one another (H attached to O is attracted to the O of neighbors), a strong intermolecular force, so a great deal of energy is needed to separate them into a gas. Methane is nonpolar with only weak London dispersion forces, so its molecules pull apart at a very low temperature.
Problem 6
- Ne < Kr < Xe
- Xe < Kr < Ne
- Kr < Ne < Xe
- they all boil at the same temperature
Answer and explanation
Ne < Kr < Xe
Dispersion forces increase with size and number of electrons (Ne < Kr < Xe), so boiling point rises in the same order.
Problem 7
Hints
Molecular size and shape can change the result; do not use one factor as a universal ranking.
Answer and explanation
Temporary and induced charge fluctuations produce London dispersion forces.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
No. Size and polarizability strengthen dispersion; compare the complete set of interactions.
Problem 9
Answer and explanation
Methane’s hydrogens are bonded to carbon, not the strongly polar N–H, O–H or F–H donor pattern used in this introductory comparison.
In common introductory examples, hydrogen bonding involves a hydrogen covalently attached to N, O or F interacting with a suitable neighboring electron-rich region. Water can supply O–H donors and oxygen acceptor sites. A molecule containing any hydrogen atom is not automatically a hydrogen-bond donor, and some molecules accept without donating. Hydrogen bonding is an intermolecular interaction here, distinct from the O–H covalent bond inside water; geometry and chemical context affect its strength.
Methane’s hydrogens are bonded to carbon, not the strongly polar N–H, O–H or F–H donor pattern used in this introductory comparison.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
Nonpolar molecules still experience dispersion attractions between molecules. Ordinary vaporization of a stable molecular substance mainly changes intermolecular arrangement/interactions, while breaking its internal covalent bonds is a chemical change requiring a different account.
Nonpolar molecules still experience dispersion attractions between molecules. Ordinary vaporization of a stable molecular substance mainly changes intermolecular arrangement/interactions, while breaking its internal covalent bonds is a chemical change requiring a different account.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.