Solving Inequalities — Challenge

Solve them exactly like equations — with one extra rule that catches almost everyone.

What these problems cover

These questions use 6 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.

Problem 1

What is the greatest integer x for which x+5<12?

  1. 5
  2. 6
  3. 7
  4. 8
  5. 17
Worked answer

6

Subtract 5 from both sides: x < 7.

The inequality is strict, so 7 itself is not allowed and the greatest integer below it is 6.

Problem 2

Which of these values of x satisfies -3x>12?

  1. -5
  2. -4
  3. 0
  4. 4
  5. 5
Worked answer

-5

Divide both sides by -3. Dividing an inequality by a negative number reverses it, giving x < -4.

Of the options only -5 is less than -4.

Check directly: -3(-5) = 15, and 15 > 12.

Problem 3

What is the greatest integer x for which 2x≤ 10?

  1. 2
  2. 4
  3. 5
  4. 6
  5. 20
Worked answer

5

Divide both sides by 2: x≤ 5.

Here the inequality allows equality, so 5 itself is permitted and is the greatest such integer.

Problem 4

What is the least integer x for which 4x-3≥ 9?

  1. 1
  2. 2
  3. 3
  4. 4
  5. 12
Worked answer

3

Add 3 to both sides: 4x≥ 12.

Divide by 4: x≥ 3. Equality is allowed, so the least such integer is 3.

Problem 5

What is the least integer x for which x-4>1?

  1. 3
  2. 4
  3. 5
  4. 6
  5. 9
Worked answer

6

Add 4 to both sides: x > 5.

The inequality is strict, so 5 does not count and the least integer above it is 6.

Problem 6

What is the least integer x for which 5-2x<1?

  1. 1
  2. 2
  3. 3
  4. 4
  5. 6
Worked answer

3

Subtract 5 from both sides: -2x < -4.

Divide by -2 and reverse the inequality: x > 2.

The least integer greater than 2 is 3. Check: 5-2(3) = -1, which is less than 1.

Problem 7

How many integers x satisfy -3≤ x<4?

  1. 6
  2. 7
  3. 8
  4. 9
  5. 10
Worked answer

7

The left end is included and the right end is not, so the integers are -3,-2,-1,0,1,2,3.

Counting them gives 7 integers. Including 4 by mistake would give 8.

Problem 8

What is the greatest integer x for which 3(x+2)≤ 18?

  1. 2
  2. 3
  3. 4
  4. 5
  5. 6
Worked answer

4

Divide both sides by 3: x+2≤ 6.

Subtract 2: x≤ 4, so the greatest such integer is 4.

Problem 9

A van may carry at most 900 kilograms. It already carries 340 kilograms of equipment. What is the greatest number of 35-kilogram boxes it can also carry?

  1. 14
  2. 15
  3. 16
  4. 17
  5. 18
Worked answer

16

If n is the number of boxes then 340+35n≤ 900.

Subtract 340: 35n≤ 560, so n≤ 16.

Sixteen boxes weigh 560 kilograms and bring the total to exactly 900, so 16 is allowed and 17 is not.

Problem 10

How many integers x satisfy -2<x+3≤ 5?

  1. 5
  2. 6
  3. 7
  4. 8
  5. 9
Worked answer

7

Subtract 3 from all three parts: -5 < x≤ 2.

The left end is excluded and the right end included, so the integers are -4,-3,-2,-1,0,1,2.

That is 7 integers.

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