Rocks, Landscapes & Water — Chapter quiz · Earth & Space Science, Grade 9
Identify Earth materials and explain how rock, water, and surface processes shape landscapes.
Problem 1
Answer and explanation
7
Quartz is reference mineral #7 on the Mohs hardness scale.
Problem 2
- Luster
- Streak
- Specific gravity
- Crystal shape
Answer and explanation
Streak
Streak is the color of a mineral's powder, revealed by rubbing it on an unglazed porcelain plate; it's more reliable than color.
Problem 3
- Igneous, sedimentary, metamorphic
- Granite, marble, quartzite
- Mineral, crystal, sediment
- Magma, lava, ash
Answer and explanation
Igneous, sedimentary, metamorphic
The rock cycle recycles Earth's materials among igneous, sedimentary, and metamorphic rock.
Problem 4
Answer and explanation
Any rock type can transform into any other rock type depending on which process — cooling, weathering and erosion, lithification, metamorphism, or melting — acts on it next, so you can enter the loop at any rock type and it keeps going indefinitely.
Problem 5
- Metamorphism
- Lithification
- Crystallization
- Weathering
Answer and explanation
Lithification
Lithification is the combined process of compaction and cementation that turns sediment into sedimentary rock.
Problem 6
- Igneous
- Sedimentary
- Foliated metamorphic
- Non-foliated metamorphic
Answer and explanation
Sedimentary
Sedimentary rock forms from settling layers of sediment without melting, so it commonly preserves fossils.
Problem 7
- It transports sediment far from its source
- It breaks down rock in place, without moving it
- It only happens underwater
- It always involves melting rock
Answer and explanation
It breaks down rock in place, without moving it
Weathering breaks rock down where it sits; erosion is the separate process that moves the pieces away.
Problem 8
Answer and explanation
30 meters
2,000 ÷ 200 = 10 periods; 10 × 3 = 30 meters.
Problem 9
- Quartz
- Calcite
- Coal
- Halite
Answer and explanation
Coal
Coal forms from plant remains, so it is organic in origin and lacks a definite composition and crystal structure.
Problem 10
Answer and explanation
Both follow from how atoms are bonded. Where bonds are weaker along particular planes, the mineral splits there, giving cleavage in those directions. Where bonding is strong in all directions, the mineral resists scratching and ranks high in hardness. Properties that seem separate at the hand-sample scale are consequences of the same atomic arrangement.
Response criteria
- State a scientifically accurate conclusion.
- Show the data, mechanism, or calculation that supports it.
- Include units, conditions, or limits where relevant.
Problem 11
Answer and explanation
Volume is 18 mL = 18 cm³, so density is 54/18 = 3 g/cm³. Use hardness, streak, cleavage and other characteristic observations; density alone may match several candidates.
Find displaced volume: 38−20 = 18 cm³.
Calculate density: 54/18 = 3 g/cm³.
Compare several tests and uncertainty rather than naming a mineral from one value.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 12
- Melting and cooling
- Compaction and cementation
- Heat and pressure
- Weathering and erosion
Answer and explanation
Compaction and cementation
Weathering and erosion produce the sediment; compaction and cementation lithify it.
Problem 13
Answer and explanation
Rocks of different origins can be brought together by geological processes: magma can intrude into sedimentary layers and cool as igneous rock, and the heat of that intrusion can metamorphose the rock it touches. Later uplift and erosion then expose all three at one surface. The arrangement records a sequence of events rather than simultaneous formation.
Response criteria
- State a scientifically accurate conclusion.
- Show the data, mechanism, or calculation that supports it.
- Include units, conditions, or limits where relevant.
Problem 14
Answer and explanation
Cementation binds deposited grains through mineral precipitation; cooling a melt forms igneous material. Preserved grain boundaries, sedimentary textures and field relationships help test a cemented-sediment interpretation. Melting is not required for sandstone.
Cementation binds deposited grains through mineral precipitation; cooling a melt forms igneous material. Preserved grain boundaries, sedimentary textures and field relationships help test a cemented-sediment interpretation. Melting is not required for sandstone.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 15
- igneous
- sedimentary
- metamorphic
- volcanic
Answer and explanation
sedimentary
Fossils survive burial in sediment; melting or intense metamorphism would destroy them.
Problem 16
Answer and explanation
Texture records the conditions of formation. Interlocking crystals point to cooling from a melt, with large crystals meaning slow underground cooling and fine ones rapid surface cooling. Rounded, sorted grains cemented together indicate transport and deposition as sediment. Aligned or banded minerals indicate directed pressure without melting. Reading the texture therefore reconstructs the process, not just the category.
Response criteria
- State a scientifically accurate conclusion.
- Show the data, mechanism, or calculation that supports it.
- Include units, conditions, or limits where relevant.
Problem 17
Answer and explanation
No. Cooling a melt can yield an igneous crystalline rock, while solid-state recrystallization can yield a nonfoliated metamorphic rock. Mineral composition, texture details, contacts and field relationships help distinguish the histories.
No. Cooling a melt can yield an igneous crystalline rock, while solid-state recrystallization can yield a nonfoliated metamorphic rock. Mineral composition, texture details, contacts and field relationships help distinguish the histories.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 18
- Erosion, weathering, deposition
- Weathering, erosion, deposition
- Deposition, weathering, erosion
- Weathering, deposition, erosion
Answer and explanation
Weathering, erosion, deposition
Rock is broken down, the pieces are transported, then they are laid down.
Problem 19
Answer and explanation
On the ridge, gravity and running water remove weathered material as fast as it forms, so little accumulates and rock stays exposed. In the valley the gradient is gentler and material arriving from upslope is deposited rather than carried away, so soil builds up. The difference reflects the balance between the rate of weathering and the rate of removal at each site.
Response criteria
- State a scientifically accurate conclusion.
- Show the data, mechanism, or calculation that supports it.
- Include units, conditions, or limits where relevant.
Problem 20
Answer and explanation
B exports less mass (9 vs 12 g) but greater concentration (0.15 vs 0.10 g/mL). Control rain input, slope, material and collection interval, except for the planned cover change.
Calculate A: 12/120 = 0.10 g/mL.
Calculate B: 9/60 = 0.15 g/mL.
Distinguish total export from concentration and match test conditions.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 21
Answer and explanation
-15 units
150 − 110 − 55 = −15.
Problem 22
Answer and explanation
Its pores can be small or poorly connected, so permeability is low despite pore space.
Problem 23
Answer and explanation
Storage change is 100−70−45 = −15 m³ and final storage is 285 m³. Transmission also depends on connected pathways, permeability, gradients and conditions; porosity alone is a storage fraction.
Combine outputs: 70+45 = 115 m³.
Change is −15 m³; add to initial 300 m³ to get 285 m³.
Distinguish pore-space amount from connected transmission.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.