Properties of Matter — Print · Physical Science: Matter, Forces & Energy, Grade 8

Use particle models, measurements, and material properties to explain and compare the matter around us.

Printable chapter lessons and review.

Atomic Structure

Learning goals

Readings for this unit

Before this unit

Count positive and negative charges; distinguish an object from the particles making it.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in atomic structure?

Illustrative evidence case. Two supplied particle records contain A: 8 protons, 8 neutrons, 8 electrons; B: 8 protons, 10 neutrons, 10 electrons. Neither record is a microscope image.

One atom: charge and particle countsOne atom: charge and particle counts8 protons8 neutronselectron-cloud regionOxygen-16 recordProtons: 8 → atomic number 8Neutrons: 8 → mass number 16Electrons: 8 → net charge 0Cloud is not a circular orbit.Illustrative model • use the labels and stated assumptions
This oxygen-16 counting model locates protons and neutrons in a nucleus and assigns electrons to a cloud region. It is not to scale: the relative sizes and distances, as well as electron behavior, are omitted. The numbers describe one neutral isotope, not every oxygen particle.

Notice and wonder

If only electrons rise to 10, what entries change? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Compare element identity, mass number and charge. Explain what changed and what stayed the same; name one limitation of a particle drawing. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

atom
The smallest unit of an element that still has the properties of that element.
proton
A positively charged particle found in the nucleus.
neutron
A particle with no charge (neutral) found in the nucleus, alongside the protons.
electron
A negatively charged particle that moves around the nucleus in an electron cloud.
nucleus
The dense, positively charged center of an atom, containing the protons and neutrons.
atomic number
The number of protons in an atom; it identifies which element the atom is.
mass number
The total number of protons plus neutrons in an atom's nucleus.
isotope
An atom of an element distinguished by neutron count; isotopes share proton count.
ion
An atom or group of atoms with net electric charge because positive and negative charges do not balance.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

All ordinary materials, including the air around us, are made of atoms or groups of atoms. An atom is a constituent of an element. Its nucleus, the very small central region, contains positively charged protons and, for most isotopes, electrically neutral neutrons. Negatively charged electrons are described by a surrounding electron cloud. Charge is a property associated with electric interactions; a proton’s positive charge and an electron’s negative charge have equal magnitudes. A neutron has no net electric charge. Hydrogen-1 is a useful exception with one proton and no neutron.

The nucleus contains nearly all the atom’s mass and is much smaller than the atom’s overall extent. A simplified stadium comparison illustrates a size difference but is not a photograph. Electrons are not tiny planets following visible circular tracks, and atoms are not literally hard empty containers. An electron-cloud model describes where an electron may be detected; a classroom dot drawing is mainly a counting aid.

One atom: charge and particle countsOne atom: charge and particle counts8 protons8 neutronselectron-cloud regionOxygen-16 recordProtons: 8 → atomic number 8Neutrons: 8 → mass number 16Electrons: 8 → net charge 0Cloud is not a circular orbit.Illustrative model • use the labels and stated assumptions
This oxygen-16 counting model locates protons and neutrons in a nucleus and assigns electrons to a cloud region. It is not to scale: the relative sizes and distances, as well as electron behavior, are omitted. The numbers describe one neutral isotope, not every oxygen particle.

What makes an atom a specific element — carbon, oxygen, gold — is simply the number of protons it holds. That count is the atomic number, and it never changes for a given element: every atom with 6 protons is carbon, and anything with 8 protons is oxygen, no exceptions. Change the number of protons and you literally change what element you have. In a neutral atom, the number of electrons exactly matches the number of protons, so the positive and negative charges cancel out and the atom carries no overall charge.

The mass number counts the protons and neutrons together, since those two supply essentially all of an atom's mass. Once you know the atomic number and the mass number, you can work out all three particle counts for a neutral atom: the protons equal the atomic number, the electrons also equal the atomic number, and the neutrons are simply whatever is left over — mass number − atomic number.

Neutrons are the one particle that can vary without changing the element itself. Every carbon atom has 6 protons, but one might carry 6 neutrons and another 8 — these different versions of an element are called isotopes. Getting comfortable with counting protons, neutrons, and electrons is the foundation for almost everything else in chemistry, from understanding why each element sits where it does on the periodic table to predicting how atoms will bond and react.

Isotopes change neutron count; ions change electron countIsotopes change neutron count; ions change electron countC-126 p⁺ · 6 n · 6 e⁻C-146 p⁺ · 8 n · 6 e⁻Same element; different isotopesMass numbers: 6 + 6 = 12 and 6 + 8 = 14Gaining an electron changes charge; ordinary chemistry keeps the nuclei.
Both shown carbon atoms have six protons and six electrons. Their neutron counts differ, so their mass numbers are 12 and 14. An ion instead differs in electron count. This counting model distinguishes an isotope from a charged atom and is not a drawing of literal electron paths or relative nuclear sizes.

Atomic number counts protons. A neutral atom has the same number of electrons as protons, so its charges cancel. If it gains an electron it becomes a negative ion; gaining an electron does not change its element.

Mass number counts protons plus neutrons in one atom. Atoms of the same element can have different neutron counts: these are isotopes. The decimal mass on a periodic table is an average for a mixture of isotopes, not a count of particles in one atom.

A model drawing is useful for counting particles, but its circles are not actual paths followed by electrons. Label the nucleus and electron cloud, and explain what the model leaves out. Use proton count first when identifying an unknown atom.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Use a model at an invisible scale

An atom has a very small nucleus containing protons and neutrons, surrounded by an electron cloud. The cloud describes where electrons are likely to be found; electrons are not tiny planets following the circles on a classroom drawing. A model helps us discuss something too small to see with an ordinary microscope.

One atom: charge and particle countsOne atom: charge and particle counts8 protons8 neutronselectron-cloud regionOxygen-16 recordProtons: 8 → atomic number 8Neutrons: 8 → mass number 16Electrons: 8 → net charge 0Cloud is not a circular orbit.Illustrative model • use the labels and stated assumptions
This oxygen-16 counting model locates protons and neutrons in a nucleus and assigns electrons to a cloud region. It is not to scale: the relative sizes and distances, as well as electron behavior, are omitted. The numbers describe one neutral isotope, not every oxygen particle.

Read the visual model

What useful information can a bead model show, and what does it leave out?

Visual reasoning — after your attempt

It can show particle counts, locations, and charges. It does not accurately show relative sizes, distances, electron behavior, or literal particle colors.

Draw a nucleus and label the three particle types and charges. A large circle around it is a counting aid, not a photograph. Real atoms do not have the colors used in a bead model, and particle sizes and distances are usually not drawn to scale.

OpenSciEd diagram linking a solid bath bomb and water before mixing to gas bubbles and liquid after mixing, with empty magnification circles for the learner’s particle model.
This OpenSciEd diagram connects visible substances and bubbles with magnified spaces for a particle model. The circles are places to represent an explanation, not photographs of atoms. Use it to distinguish what can be observed from what a particle model proposes; the bath-bomb reaction is explained later in the chemistry chapter. Bath-bomb matter model at visible and particle scales · OpenSciEd · 7.1 Chemical Reactions & Matter, Lesson 1, source, CC BY 4.0. Figure excerpt rendered from the PDF and resized for the web.

Pause and explain

What useful information can a bead model show, and what does it leave out?

Check your reasoning after answering

It can show particle counts, locations, and charges. It does not accurately show relative sizes, distances, electron behavior, or literal particle colors.

Part 2 · Identify an element by its protons

The number of protons determines the element. Every oxygen atom has eight protons, regardless of how many neutrons or electrons it has. Atomic number is this proton count. A neutral atom has equal positive and negative charges because it has as many electrons as protons.

Proton count fixes element identityProton count fixes element identityC6 p⁺ · 6 n · 6 e⁻O8 p⁺ · 8 n · 8 e⁻Carbon: atomic number 6Oxygen: atomic number 8Count protons to identify the element; electron count tells net charge.
Carbon and oxygen are compared with their proton, neutron and electron counts labeled. Six protons identifies carbon; eight identifies oxygen. The cloud and nucleus sizes are deliberately schematic and electrons are not drawn on fixed planetary tracks. A neutral atom balances proton and electron counts.

Read the visual model

Read p⁺ as positively charged protons, n as neutral neutrons and e⁻ as negatively charged electrons. Element identity and net charge answer different questions. Changing only electrons cannot turn oxygen into carbon.

A particle has 8 protons, 8 neutrons and 10 electrons. Is it carbon, oxygen or a new element? Explain its charge.

Visual reasoning — after your attempt

It is oxygen, because it still has 8 protons. It has two more electrons than protons and therefore charge −2 in elementary-charge units.

For a neutral atom with six protons, six electrons cancel the six positive charges. Six protons identify carbon. Removing an electron changes its charge, but the nucleus still contains six protons, so the element is still carbon.

Pause and explain

A particle has eight protons and ten electrons. Is it oxygen, and is it neutral?

Check your reasoning after answering

It is oxygen because it has eight protons. It has two excess negative charges, so it is an ion with charge −2, not a neutral atom.

Part 3 · Count neutrons without confusing two masses

Mass number counts protons plus neutrons in one atom. Subtract atomic number from mass number to find neutrons. Isotopes of an element share proton count but differ in neutron count. The decimal atomic mass printed on a periodic table is an average for naturally occurring isotopes, rather than the particle count of one atom.

Three oxygen records compare proton, neutron, and electron counts.A · oxygen-168 protons8 neutrons8 electronsCharge 0B · oxygen-188 protons10 neutrons8 electronsCharge 0C · oxygen ion8 protons8 neutrons10 electronsCharge −2
Count model for the supplied records: all three have eight protons. A and B differ in neutrons; A and C differ in electrons. Boxes are records, not atom sizes or electron paths.

Read the visual model

How do carbon-12 and carbon-14 remain the same element?

Visual reasoning — after your attempt

Both contain six protons. Carbon-12 has six neutrons and carbon-14 has eight; the different neutron counts make them isotopes of carbon.

A carbon atom with mass number 14 has six protons and 14−6=8 neutrons. A neutral carbon-14 atom also has six electrons. Do not round a table average and assume that every atom of that element has the resulting neutron count.

Pause and explain

How do carbon-12 and carbon-14 remain the same element?

Check your reasoning after answering

Both contain six protons. Carbon-12 has six neutrons and carbon-14 has eight; the different neutron counts make them isotopes of carbon.

Part 4 · Keep element identity during ordinary changes

In ordinary chemical reactions, atoms rearrange and electrons can be shared or transferred. The nuclei keep their proton counts. This is why an oxygen atom in water and an oxygen atom in oxygen gas are still oxygen, even though the substances have different properties. Nuclear changes are a different kind of process.

Isotopes change neutron count; ions change electron countIsotopes change neutron count; ions change electron countC-126 p⁺ · 6 n · 6 e⁻C-146 p⁺ · 8 n · 6 e⁻Same element; different isotopesMass numbers: 6 + 6 = 12 and 6 + 8 = 14Gaining an electron changes charge; ordinary chemistry keeps the nuclei.
Both shown carbon atoms have six protons and six electrons. Their neutron counts differ, so their mass numbers are 12 and 14. An ion instead differs in electron count. This counting model distinguishes an isotope from a charged atom and is not a drawing of literal electron paths or relative nuclear sizes.

Read the visual model

Use the nucleus count for the element and mass number. Use proton minus electron count for net charge. Keep these accounts separate: a heavier isotope is not necessarily a more positively charged atom.

Starting from the C-12 record, what changes if it gains one electron? What changes if it instead gains two neutrons?

Visual reasoning — after your attempt

One added electron gives 7 electrons and a −1 charge while keeping carbon and mass number 12. Two added neutrons instead give carbon-14 with mass number 14 and unchanged neutral charge.

Use the same color and label for each oxygen atom when drawing a reaction. Changing an oxygen bead into a carbon bead would falsely suggest a changed nucleus. Track atom identity while allowing new groupings.

Pause and explain

Why is changing proton count a poor model of dissolving salt?

Check your reasoning after answering

Dissolving separates and disperses salt ions in water; it does not convert their nuclei into different elements. Proton counts and element identities remain unchanged.

Molecules and extended structures

A formula can name a small separate group or the ratio in a repeating structure. The same drawing rule does not describe both.

An element contains atoms with one proton-defined identity. A compound contains different elements chemically combined in a characteristic composition. A molecule is a distinct bonded group of atoms, such as one water molecule with two hydrogen atoms and one oxygen atom. A chemical bond is an interaction that holds a combination together. Drawing a line represents that connection; it is not a literal stick between colored balls. Subscripts count atoms in one represented group, while a coefficient counts whole groups.

Molecules and extended structuresMolecules and extended structuresSeparate water moleculesOHHH₂O: 2 H per 1 OExtended salt arrangement+−+−−+−++−+−Na⁺ / Cl⁻ repeat; no separate NaCl molecule.Illustrative model • read the labels and caption
The water side shows one separate molecule with a two-to-one H:O count. The salt side is a small slice of a repeating ionic arrangement with alternating charge signs. The displayed edge is not the edge of every crystal; symbols and distances are schematic, and a visible patch need not contain equal edge counts. NaCl describes the bulk ratio.

Some solids are extended structures: a connected or repeating arrangement continuing beyond the few particles drawn. Ordinary sodium chloride forms a lattice, a repeating arrangement of positive sodium ions and negative chloride ions. NaCl states a one-to-one ratio, not a separate two-atom molecule floating inside the crystal. A polymer is a material whose molecules include long chains of repeated groups. A repeating-unit drawing can show part of a chain without claiming every chain has identical length.

Composition and arrangement help explain why substances differ in properties. An oxygen atom in water remains oxygen, but water has properties different from oxygen gas because the combinations differ. A molecular or lattice model should name its represented substance, count or ratio, and scale limits. The few drawn particles stand for many actual particles. Ordinary chemical changes rearrange existing atoms; changing an element’s nucleus is a different process, so ordinary chemistry does not explain the creation of all elements in the universe.

Explain and apply

Draw two water molecules and a larger repeating salt patch. Compare total atom counts with a formula ratio, and explain why a two-ball salt molecule is an incomplete crystal model.

  • Distinguish molecule from extended arrangement.
  • Count water atoms correctly.
  • Explain formula ratio and a model limit.
Reasoning and marking guidance — after your attempt

Two water molecules contain four H and two O atoms. A salt patch represents part of an extended arrangement; its bulk Na:Cl ratio is one-to-one rather than a claim that the crystal is a collection of separate NaCl molecules. Retain element/ion labels and note that colors, bonding lines and distances are conventions.

Apply the whole unit · Identify three particles

Illustrative particle records: A has 8 protons, 8 neutrons, 8 electrons; B has 8 protons, 10 neutrons, 8 electrons; C has 8 protons, 8 neutrons, 10 electrons. Oxygen has atomic number 8.

Your task

Identify the element, mass number, and overall charge of each record. Draw a labeled counting model, identify an isotope pair, and explain why the drawings cannot represent true electron paths.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

All three are oxygen. A has mass number 16 and charge 0; B has mass number 18 and charge 0; C has mass number 16 and charge −2. A and B are isotopes. A and C differ in electron count. Label the nucleus and electron cloud; show counts without implying scale or circular electron trajectories.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Begin with counters and a particle-count table. Ask the learner to identify the element before calculating mass number or charge. If the learner changes element when an electron changes, revisit the proton rule with a second example. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation. The illustrated study “Molecules and extended structures” is required curriculum content. Teach it before the associated application or distribute it over the assigned unit sessions; it is not an optional enrichment. Its practice/review/quiz response provides evidence of understanding. Model/data work must not be recorded as an actual physical experiment.

The key idea

Protons and neutrons occupy the nucleus; electrons are described by an electron cloud around it. Proton count identifies the element.

Number of Neutrons

neutrons = mass number − atomic number

atomic number = number of protons = number of electrons (in a neutral atom); mass number = protons + neutrons.

Worked examples

Example 1

An atom of carbon-12 has atomic number 6 and mass number 12. Find its numbers of protons, neutrons, and electrons.
  1. Protons = atomic number = 6.
  2. Neutrons = mass number − atomic number = 12 − 6 = 6.
  3. Electrons = protons (neutral atom) = 6.
Answer: 6 protons, 6 neutrons, 6 electrons

Example 2 · Worked application

Two neutral atoms each have 7 protons. One has 7 neutrons and the other has 8. Compare their identities, masses and electron counts.
  1. Use proton count first: both have atomic number 7, which identifies nitrogen.
  2. Add protons and neutrons separately: 7+7=14 and 7+8=15.
  3. Neutrality requires 7 electrons in each atom; the extra neutron adds no charge.
Answer: They are nitrogen-14 and nitrogen-15, isotopes with 7 electrons each.
Check the reasoning

Check that changing neutron count leaves both proton count and charge unchanged.

Example 3

An atom of oxygen has atomic number 8 and mass number 16. Find its numbers of protons, neutrons, and electrons.
  1. Protons = atomic number = 8.
  2. Neutrons = mass number − atomic number = 16 − 8 = 8.
  3. Electrons = protons (neutral atom) = 8.
Answer: 8 protons, 8 neutrons, 8 electrons

Example 4

An atom has 8 protons, 9 neutrons and 10 electrons. Identify the element, mass number and charge.
  1. Atomic number 8 identifies oxygen.
  2. Mass number is 8+9=17; 8 positive and 10 negative charges give a net charge of −2.
Answer: An oxygen-17 ion with charge −2.

Example 5 · Find and fix the mistake

Context: Two neutral atoms each have 7 protons. One has 7 neutrons and the other has 8. Compare their identities, masses and electron counts. A student claims: “An atom gains an electron, so it becomes the next element on the periodic table.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Check that changing neutron count leaves both proton count and charge unchanged.
  2. Element identity depends on protons. Gaining an electron changes charge, not atomic number. The result is an ion of the same element.
Answer: Element identity depends on protons. Gaining an electron changes charge, not atomic number. The result is an ion of the same element.
Check the reasoning

Check that changing neutron count leaves both proton count and charge unchanged.

Example 6 · Interpret the visual model

Proton count fixes element identityProton count fixes element identityC6 p⁺ · 6 n · 6 e⁻O8 p⁺ · 8 n · 8 e⁻Carbon: atomic number 6Oxygen: atomic number 8Count protons to identify the element; electron count tells net charge.
Carbon and oxygen are compared with their proton, neutron and electron counts labeled. Six protons identifies carbon; eight identifies oxygen. The cloud and nucleus sizes are deliberately schematic and electrons are not drawn on fixed planetary tracks. A neutral atom balances proton and electron counts.
A particle has 8 protons, 8 neutrons and 10 electrons. Is it carbon, oxygen or a new element? Explain its charge.
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. Read p⁺ as positively charged protons, n as neutral neutrons and e⁻ as negatively charged electrons. Element identity and net charge answer different questions. Changing only electrons cannot turn oxygen into carbon.
  3. It is oxygen, because it still has 8 protons. It has two more electrons than protons and therefore charge −2 in elementary-charge units.
Answer: It is oxygen, because it still has 8 protons. It has two more electrons than protons and therefore charge −2 in elementary-charge units.
Check the reasoning

Keep the model’s stated limits explicit: Carbon and oxygen are compared with their proton, neutron and electron counts labeled. Six protons identifies carbon; eight identifies oxygen. The cloud and nucleus sizes are deliberately schematic and electrons are not drawn on fixed planetary tracks. A neutral atom balances proton and electron counts.

Avoid these mistakes

Check your understanding

An atom has 8 protons, 9 neutrons and 10 electrons. Identify the element, mass number and charge.

Discuss the answer

An oxygen-17 ion with charge −2.

Why is the periodic-table atomic mass often a decimal?

Discuss the answer

Atomic number counts protons. A neutral atom has the same number of electrons as protons, so its charges cancel. If it gains an electron it becomes a negative ion; gaining an electron does not change its element. Mass number counts protons plus neutrons in one atom. Atoms of the same element can have different neutron counts: these are isotopes. The decimal mass on a periodic table is an average for a mixture of isotopes, not a count of particles in one atom.

Return to the phenomenon

Two supplied particle records contain A: 8 protons, 8 neutrons, 8 electrons; B: 8 protons, 10 neutrons, 10 electrons. Neither record is a microscope image. Compare element identity, mass number and charge. Explain what changed and what stayed the same; name one limitation of a particle drawing. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

Both are oxygen because each has eight protons. A has mass number 16 and is neutral; B has mass number 18 and charge −2. Neutrons change isotope and electrons change charge, while proton count retains element identity. A drawing is a counting model, not a scaled photograph or a literal electron orbit.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

Two supplied particle records contain A: 8 protons, 8 neutrons, 8 electrons; B: 8 protons, 10 neutrons, 10 electrons. Neither record is a microscope image. Compare element identity, mass number and charge. Explain what changed and what stayed the same; name one limitation of a particle drawing. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

Both are oxygen because each has eight protons. A has mass number 16 and is neutral; B has mass number 18 and charge −2. Neutrons change isotope and electrons change charge, while proton count retains element identity. A drawing is a counting model, not a scaled photograph or a literal electron orbit.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

If only electrons rise to 10, what entries change? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

This oxygen-16 counting model locates protons and neutrons in a nucleus and assigns electrons to a cloud region. It is not to scale: the relative sizes and distances, as well as electron behavior, are omitted. The numbers describe one neutral isotope, not every oxygen particle.

Response guidance — discuss after your attempt

The charge becomes −2 while atomic number 8, mass number 16 and oxygen identity remain unchanged. This oxygen-16 counting model locates protons and neutrons in a nucleus and assigns electrons to a cloud region. It is not to scale: the relative sizes and distances, as well as electron behavior, are omitted. The numbers describe one neutral isotope, not every oxygen particle.

Words to know

atom
The smallest unit of an element that still has the properties of that element.
proton
A positively charged particle found in the nucleus.
neutron
A particle with no charge (neutral) found in the nucleus, alongside the protons.
electron
A negatively charged particle that moves around the nucleus in an electron cloud.
nucleus
The dense, positively charged center of an atom, containing the protons and neutrons.
atomic number
The number of protons in an atom; it identifies which element the atom is.
mass number
The total number of protons plus neutrons in an atom's nucleus.
isotope
An atom of an element distinguished by neutron count; isotopes share proton count.
ion
An atom or group of atoms with net electric charge because positive and negative charges do not balance.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

Why atoms are mostly empty space

If an atom's nucleus were the size of a marble, the nearest electrons would be about two football fields away, with nothing in between. Atoms are roughly 99.9999999% empty space. The reason solid objects still feel solid is not that atoms are packed tight — it's that the electron clouds of neighboring atoms repel each other, so your hand never actually touches the desk; the electrons push back before contact.

Isotopes: same element, different mass

Every atom of an element has the same number of protons, but the number of neutrons can vary. These variations are called isotopes. Carbon-12 and carbon-14 are both carbon (6 protons), but carbon-14 has two extra neutrons. Carbon-14 is slightly radioactive and decays at a known rate — which is exactly how scientists carbon-date fossils and ancient artifacts.

Where the mass really is

Protons and neutrons each have about the same mass, and each is roughly 1,836 times heavier than an electron. So nearly all of an atom's mass sits in the tiny nucleus, while electrons — which take up almost all the atom's volume — contribute almost none of its weight. That's why the atomic mass number counts protons + neutrons and ignores electrons.

In the real world

Doctors use isotopes — atoms of the same element with different numbers of neutrons — in medical imaging and in treating certain cancers.

Exit check

If only electrons rise to 10, what entries change? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

The charge becomes −2 while atomic number 8, mass number 16 and oxygen identity remain unchanged. This oxygen-16 counting model locates protons and neutrons in a nucleus and assigns electrons to a cloud region. It is not to scale: the relative sizes and distances, as well as electron behavior, are omitted. The numbers describe one neutral isotope, not every oxygen particle.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Physical vs. Chemical Properties

Learning goals

Readings for this unit

Before this unit

Distinguish a substance from a mixture and an observation from an explanation.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in physical vs. chemical properties?

Illustrative evidence case. A supplied record describes ice melting, iron rusting and sugar dissolving without a reaction under the stated conditions. All three look different afterward.

Two kinds of change: test identityTwo kinds of change: test identityIce → liquidH₂O beforeH₂O afterwardIron → rustIron interactsNew substancesAsk for evidenceCompare propertiesAccount for atomsIllustrative model • use the labels and stated assumptions
The two cases distinguish state change from formation of new substances. The boxes are an explanation guide, not photographs or a rule that color or bubbles alone identify a reaction. Further characteristic-property evidence is needed when identity is not supplied.

Notice and wonder

Which case changes substance identity? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Classify the changes by substance identity. Propose evidence that is stronger than appearance alone, and explain why difficulty reversing a change is not the definition. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

physical property
A characteristic you can observe or measure without changing what the substance is, like color, density, or melting point.
chemical property
A characteristic that describes how a substance reacts or changes into a different substance, like flammability or reactivity with acid.
physical change
A change in form or appearance where no new substance is created.
chemical change
A change where one or more new substances with new properties are formed.
density
A physical property found by dividing an object's mass by its volume (density = mass ÷ volume).
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

Every substance has a set of physical properties — traits you can observe or measure without turning the substance into anything new. Color, hardness, texture, melting point, boiling point, and density (mass ÷ volume) are all physical properties. You can slice a loaf of bread, bend a copper wire, melt an ice cube, or dissolve sugar in tea, and in every one of those cases the material is still fundamentally the same stuff, just in a different form. A change like that — where no new substance appears — is a physical change, and it's often reversible.

Density is worth a closer look, because it's a physical property you'll calculate often. It measures how much mass is packed into a given amount of space (density = mass ÷ volume), and it explains everyday puzzles like why a massive steel ship floats while a small pebble sinks — what matters isn't total weight but how tightly the mass is packed compared with water. A key point: density belongs to the material itself, so a tiny gold ring and a giant gold bar have exactly the same density.

A material property needs a controlled comparisonA material property needs a controlled comparisonMass (g)0153045051015Volume (cm³)One uniform material, same conditions: mass/volume = 3 g/cm³.
The illustrative samples have masses 15, 30 and 45 g at volumes 5, 10 and 15 cm³. Their mass-to-volume ratio is the same, 3 g/cm³. A larger sample has more mass without having a new density. This line models one uniform material at matched conditions; it does not identify that material by density alone.

A chemical property, by contrast, describes how a substance behaves when it reacts and turns into something different. Flammability (will it burn?), reactivity with acid (will it fizz or dissolve?), and the tendency to rust are all chemical properties. Here's the catch: you can only truly observe a chemical property by letting the substance change — you can't see that wood is flammable until some of it actually burns.

When a substance genuinely reacts and becomes one or more new substances with new properties, that's a chemical change. Burning wood, rusting iron, and digesting your lunch are all chemical changes: the original material is gone, its atoms rearranged into different substances entirely. And unlike most physical changes, chemical changes are usually very hard to reverse — there's no simple way to un-burn a log or un-cook an egg.

So how do you tell the two apart? Ask a single question: did a genuinely new substance form? Melting butter is physical — it's still butter, just liquid, and it hardens right back if it cools. Burning that same butter is chemical — it becomes soot, smoke, and gases that will never turn back into butter. Watch out for one common trap, though: a dramatic-looking change of state, like water boiling into steam, is still only a physical change, because that steam is nothing but water in gas form.

Two kinds of change: test identityTwo kinds of change: test identityIce → liquidH₂O beforeH₂O afterwardIron → rustIron interactsNew substancesAsk for evidenceCompare propertiesAccount for atomsIllustrative model • use the labels and stated assumptions
The two cases distinguish state change from formation of new substances. The boxes are an explanation guide, not photographs or a rule that color or bubbles alone identify a reaction. Further characteristic-property evidence is needed when identity is not supplied.

A physical property can be observed without changing a substance's chemical identity. Measure melting point, density or electrical conductivity under stated conditions. Color alone rarely identifies a substance because different substances can have similar colors.

Chemical properties describe possible reactions, such as burning in oxygen or reacting with an acid. The property exists before the test, but observing it normally involves a chemical change. A chemical reaction rearranges atoms into new substances.

Separate the evidence from the conclusion. Cutting metal changes its size; rusting makes new substances. Dissolving sugar in water usually keeps the sugar molecules intact. Ask whether composition changed, rather than whether the change looks dramatic or is easy to reverse.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Separate a property from a change

A property describes how a substance behaves under stated conditions. A physical property can be measured without changing chemical identity, such as density or electrical conductivity. A change is something that happens to a sample. Cutting a copper wire changes its length, while conductivity remains a property of the copper.

Physical and chemical change comparedDid a new substance form?Physical changeice meltingsugar dissolvingmetal bendingwater boilingsame substance, different formChemical changeiron rustingwood burningacid and chalk fizzingmilk souringdifferent substance, new propertiesDissolving is physical: the sugar is still sugar and can be recovered by evaporating the water
One question settles nearly every case: is the substance afterwards the same substance? Dissolving is the one people most often misclassify, because the sugar disappears from view and is chemically unchanged.

Read the visual model

Is flammability a change or a property?

Visual reasoning — after your attempt

Flammability is a chemical property describing a tendency to burn. Actual burning is a chemical change producing new substances.

Make two notebook columns: what can be measured, and what happened. Melting point belongs in the first column; a sample melting belongs in the second. Give the temperature or other test conditions when they matter.

OpenSciEd three-panel schematic showing a fully coated mirror, a partly coated one-way mirror and glass, with layer labels and incoming light rays.
OpenSciEd compares layered materials and their light response. Reflectivity and transmission can be physical properties measured without changing chemical identity. The pictured structures differ; that alone does not establish that a reaction occurred during a test. The incoming-ray model still needs outgoing paths and a stated energy account. Mirror, one-way mirror and glass at a microscopic scale · OpenSciEd · 6.1 Light & Matter, Lesson 4, source, CC BY 4.0. Figure excerpt rendered from the PDF and resized for the web.

Pause and explain

Is flammability a change or a property?

Check your reasoning after answering

Flammability is a chemical property describing a tendency to burn. Actual burning is a chemical change producing new substances.

Part 2 · Ask whether chemical identity changed

A physical change can alter size, shape, arrangement, or state while retaining the substance. A chemical change produces substances with different chemical identities by rearranging atoms. The decision concerns composition, not whether the event looks dramatic or whether it is easy to reverse.

Two kinds of change: test identityTwo kinds of change: test identityIce → liquidH₂O beforeH₂O afterwardIron → rustIron interactsNew substancesAsk for evidenceCompare propertiesAccount for atomsIllustrative model • use the labels and stated assumptions
The two cases distinguish state change from formation of new substances. The boxes are an explanation guide, not photographs or a rule that color or bubbles alone identify a reaction. Further characteristic-property evidence is needed when identity is not supplied.

Read the visual model

Why is reversibility alone an unreliable rule?

Visual reasoning — after your attempt

Some physical changes are hard to undo, such as breaking glass, and some chemical reactions can be reversed under appropriate conditions. Chemical identity is the deciding idea.

Boiling water makes water vapor, so it is a physical change. Rusting iron produces iron-containing compounds with oxygen, so it is chemical. Breaking a glass is difficult to undo but does not, by itself, create a new substance.

Pause and explain

Why is reversibility alone an unreliable rule?

Check your reasoning after answering

Some physical changes are hard to undo, such as breaking glass, and some chemical reactions can be reversed under appropriate conditions. Chemical identity is the deciding idea.

Part 3 · Build a comparison from several measurements

One property rarely establishes identity. Different substances may share a color or approximate density. Collect a pattern of evidence using comparable conditions: appearance, density, melting behavior, or a suitable approved test. Treat a proposed identity as a claim that should agree with all relevant evidence.

A material property needs a controlled comparisonA material property needs a controlled comparisonMass (g)0153045051015Volume (cm³)One uniform material, same conditions: mass/volume = 3 g/cm³.
The illustrative samples have masses 15, 30 and 45 g at volumes 5, 10 and 15 cm³. Their mass-to-volume ratio is the same, 3 g/cm³. A larger sample has more mass without having a new density. This line models one uniform material at matched conditions; it does not identify that material by density alone.

Read the visual model

The slope of this mass-versus-volume graph is density, not speed. Both axes name measured properties. Use several properties, with conditions stated, before deciding whether a substance’s identity has changed.

For a 12 cm³ sample following this pattern, predict mass. Can that result alone identify the substance?

Visual reasoning — after your attempt

Predicted mass is 12×3 = 36 g. Density alone is insufficient because different substances can share similar values; compare additional characteristic properties.

Two white powders may look identical but behave differently in water. Describe the observations without tasting or handling unknown chemicals. A label, a known safe reference sample, and a controlled test are stronger evidence than appearance alone.

Pause and explain

Do two equal densities prove two samples are the same substance?

Check your reasoning after answering

No. Different substances can have similar densities, and measurements have uncertainty. Additional independent properties and known comparison samples are needed.

Part 4 · Describe dissolving at the particle level

When sugar dissolves, sugar molecules disperse among water molecules. The mixture looks uniform at the everyday scale, but the sugar has not simply vanished. For this familiar example, dissolving keeps the sugar molecules intact. Some substances can also react when mixed with water, so dissolving should not be treated as one universal chemical rule.

Dissolving at the particle scaleDissolving, seen as particlesBeforesugar as a solid lumpAftersugar particles spread throughNothing was destroyed and nothing new formed — the mass is unchanged
The lump has not vanished; its particles have separated and spread between the water particles. That is why dissolving is a physical change and why the mass of the solution equals the mass of what went into it.

Read the visual model

How can a clear liquid contain more than one substance?

Visual reasoning — after your attempt

Particles can be mixed too finely to distinguish by eye. A clear sugar solution contains both water molecules and dispersed sugar molecules.

A particle drawing of sugar water should show both labeled water and sugar particles. Evaporation can leave sugar behind, provided heating does not cause decomposition. Explain the chosen example rather than claiming every clear solution contains only water.

Pause and explain

How can a clear liquid contain more than one substance?

Check your reasoning after answering

Particles can be mixed too finely to distinguish by eye. A clear sugar solution contains both water molecules and dispersed sugar molecules.

Mixtures and physical separation

Sand and salt can be combined without automatically forming a new compound. A physical combination needs investigation, not a reaction claim based only on mixing.

A mixture contains substances physically combined in variable proportions. A solution is a mixture that is uniform at the visible scale because one substance is distributed among particles of another. A solute is the dissolved substance and a solvent is the dissolving medium. Salt dissolved in water remains matter even when it is not visible. A compound has a chemical composition; changing the mixture proportions is different from changing a compound’s formula.

Mixtures and physical separationMixtures and physical separationKnown combinationSand + saltVariable amountsWater and filtrationSand retainedSalt solution passesSlow evaporationSalt remainsWater goes to airIllustrative model • read the labels and caption
The separation model uses suspended-particle size and different behavior in water. It is not a drinking-water treatment claim: dissolved substances can pass a filter. The boxes show selected transfers rather than a complete apparatus or proof from appearance alone.

Separation can use differences in physical properties. A filter traps sufficiently large suspended particles but ordinarily does not remove dissolved salt. Decanting means carefully pouring off a liquid while leaving settled material. Evaporation can leave dissolved salt behind while water enters the surroundings; it does not destroy water or create new salt atoms. Separation behavior, recovered characteristic properties and mass accounting supply evidence for a physical combination.

Plan before observing: specify known substances, their amounts, the property used for separation, the recovery method and how records will be kept. Test the components and their combination with matched water amounts and stirring/settling time. A sample’s clear appearance does not establish purity or drinking safety. Incomplete recovery may reflect transfer loss or dissolved material left behind, rather than a chemical reaction. Report all recovered and unrecovered matter within the chosen boundary.

Evidence to interpret

Original componentsRecovered sand (g)Recovered salt (g)
5.0 g sand + 3.0 g salt4.82.9

Use this method safely

Adult support for material selection and spills. Use only clean known nonhazardous samples, avoid dust inhalation and keep small items from younger children. Do not taste, drink, heat or mix unknown chemicals. Use provided records when balance, filters or safe samples are unavailable.

Investigate or evaluate the supplied records

  1. Use clean approved sand and table salt, or the supplied records. Record the known components and masses.
  2. Compare each component and the mixture in equal room-temperature water volumes; record dissolving/settling observations.
  3. Filter through a suitable paper filter into a clean collection vessel and record which component remains.
  4. Leave a small labeled salt-solution sample in a safe tray to evaporate at room temperature over several days; no stove or boiling is needed.
  5. Compare recovered solids with original component records and account for incomplete recovery.
  6. Record actual measurements separately from supplied values and propose a repeated improved method.

Explain and apply

Plan and, if safe materials are available, conduct the sand/salt comparison. Use the supplied recovery record to argue whether it is consistent with a physical mixture, and explain why a mass shortfall is not automatically a reaction.

  • Specify components and a property-based method.
  • Use recovered identity and mass evidence.
  • Explain a limitation or controlled improvement.
Reasoning and marking guidance — after your attempt

The separate-component tests and recovery of sand and salt are consistent with a physical combination. The illustrative recovered masses are 4.8+2.9=7.7 g versus 8.0 g originally added, leaving 0.3 g unaccounted for in that collection. Transfer residues, remaining dissolved salt or reading uncertainty can explain a shortfall. Better rinsing, complete collection and repeated matched tests can improve the account; the data do not establish a new compound.

Apply the whole unit · Classify with evidence

Illustrative observations: ice melts into liquid water; a glass breaks into pieces; iron develops a new reddish coating after exposure to moist air; sugar dissolves and is recovered after gentle evaporation.

Your task

Classify each event and explain the chemical-identity evidence. Identify a property used in an observation and explain why a dramatic appearance or difficult reversal is not enough to classify a change.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

Melting, breaking, and the stated sugar dissolution are physical changes; rusting is chemical because new iron compounds form. State identity evidence rather than relying on size or reversibility. Color is an observed physical property, but color change alone would not establish a chemical reaction without more evidence.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Use familiar pictured events and ask for because-statements. Keep properties, observations, and conclusions in separate columns. Do not ask learners to taste samples or test unknown household chemicals. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation. The illustrated study “Mixtures and physical separation” is required curriculum content. Teach it before the associated application or distribute it over the assigned unit sessions; it is not an optional enrichment. Its practice/review/quiz response provides evidence of understanding. Model/data work must not be recorded as an actual physical experiment.

The key idea

If a new substance with new properties forms, it's a chemical change; if the same substance just looks or feels different, it's a physical change.

Density

density = mass ÷ volume

mass in grams (g); volume in cm³; density in g/cm³.

Worked examples

Example 1

Classify each as a physical or chemical change: (a) dissolving sugar in water, (b) a firework exploding.
  1. (a) Ask: is it still the same substance? Yes — evaporating the water would leave the same sugar behind, so this is a physical change.
  2. (b) Ask: did new substances form? Yes — light, heat, smoke, and new gases are produced that can't turn back into the original chemicals, so this is a chemical change.
Answer: (a) physical change (b) chemical change

Example 2 · Worked application

A sealed sugar-water sample is evaporated gently and sugar crystals remain. What does this suggest about dissolving?
  1. Separate the observations: water leaves and crystals remain.
  2. Recovery of sugar supports the claim that dissolving did not destroy its chemical identity.
  3. Appearance alone does not identify crystals conclusively; matching properties would strengthen the claim.
Answer: The observations support a physical change, with further property tests needed to confirm identity.
Check the reasoning

Ask whether a new substance was demonstrated, rather than whether the sample looked different.

Example 3

A rock has a mass of 45 g and a volume of 15 cm³. Find its density, a physical property.
  1. Density = mass ÷ volume.
  2. 45 ÷ 15 = 3.
Answer: 3 g/cm³

Example 4

A student tears paper and another burns paper. Classify each change and explain using composition.
  1. Tearing changes shape while the paper remains the same material.
  2. Burning rearranges atoms into substances such as gases and ash.
Answer: Tearing is physical; burning is chemical. New substances, rather than size alone, distinguish the changes.

Example 5 · Find and fix the mistake

Context: A sealed sugar-water sample is evaporated gently and sugar crystals remain. What does this suggest about dissolving? A student claims: “A change is chemical whenever it cannot easily be reversed.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Ask whether a new substance was demonstrated, rather than whether the sample looked different.
  2. Ease of reversal is not the definition. Shattering glass can be hard to reverse but leaves its composition unchanged.
Answer: Ease of reversal is not the definition. Shattering glass can be hard to reverse but leaves its composition unchanged.
Check the reasoning

Ask whether a new substance was demonstrated, rather than whether the sample looked different.

Example 6 · Interpret the visual model

A material property needs a controlled comparisonA material property needs a controlled comparisonMass (g)0153045051015Volume (cm³)One uniform material, same conditions: mass/volume = 3 g/cm³.
The illustrative samples have masses 15, 30 and 45 g at volumes 5, 10 and 15 cm³. Their mass-to-volume ratio is the same, 3 g/cm³. A larger sample has more mass without having a new density. This line models one uniform material at matched conditions; it does not identify that material by density alone.
For a 12 cm³ sample following this pattern, predict mass. Can that result alone identify the substance?
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. The slope of this mass-versus-volume graph is density, not speed. Both axes name measured properties. Use several properties, with conditions stated, before deciding whether a substance’s identity has changed.
  3. Predicted mass is 12×3 = 36 g. Density alone is insufficient because different substances can share similar values; compare additional characteristic properties.
Answer: Predicted mass is 12×3 = 36 g. Density alone is insufficient because different substances can share similar values; compare additional characteristic properties.
Check the reasoning

Keep the model’s stated limits explicit: The illustrative samples have masses 15, 30 and 45 g at volumes 5, 10 and 15 cm³. Their mass-to-volume ratio is the same, 3 g/cm³. A larger sample has more mass without having a new density. This line models one uniform material at matched conditions; it does not identify that material by density alone.

Avoid these mistakes

Check your understanding

A student tears paper and another burns paper. Classify each change and explain using composition.

Discuss the answer

Tearing is physical; burning is chemical. New substances, rather than size alone, distinguish the changes.

What evidence would help distinguish dissolving from a chemical reaction?

Discuss the answer

A physical property can be observed without changing a substance's chemical identity. Measure melting point, density or electrical conductivity under stated conditions. Color alone rarely identifies a substance because different substances can have similar colors. Chemical properties describe possible reactions, such as burning in oxygen or reacting with an acid. The property exists before the test, but observing it normally involves a chemical change. A chemical reaction rearranges atoms into new substances.

Return to the phenomenon

A supplied record describes ice melting, iron rusting and sugar dissolving without a reaction under the stated conditions. All three look different afterward. Classify the changes by substance identity. Propose evidence that is stronger than appearance alone, and explain why difficulty reversing a change is not the definition. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

Melting and the specified dissolution retain substance identity and are physical; rusting produces different substances and is chemical. Comparable characteristic properties or composition evidence can support a new-substance claim. Some physical changes are hard to reverse, and some reactions can be reversed, so reversibility alone does not classify them.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

A supplied record describes ice melting, iron rusting and sugar dissolving without a reaction under the stated conditions. All three look different afterward. Classify the changes by substance identity. Propose evidence that is stronger than appearance alone, and explain why difficulty reversing a change is not the definition. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

Melting and the specified dissolution retain substance identity and are physical; rusting produces different substances and is chemical. Comparable characteristic properties or composition evidence can support a new-substance claim. Some physical changes are hard to reverse, and some reactions can be reversed, so reversibility alone does not classify them.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

Which case changes substance identity? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

The two cases distinguish state change from formation of new substances. The boxes are an explanation guide, not photographs or a rule that color or bubbles alone identify a reaction. Further characteristic-property evidence is needed when identity is not supplied.

Response guidance — discuss after your attempt

Rusting forms different substances; melting retains water identity. Appearance alone cannot establish the classification. The two cases distinguish state change from formation of new substances. The boxes are an explanation guide, not photographs or a rule that color or bubbles alone identify a reaction. Further characteristic-property evidence is needed when identity is not supplied.

Words to know

physical property
A characteristic you can observe or measure without changing what the substance is, like color, density, or melting point.
chemical property
A characteristic that describes how a substance reacts or changes into a different substance, like flammability or reactivity with acid.
physical change
A change in form or appearance where no new substance is created.
chemical change
A change where one or more new substances with new properties are formed.
density
A physical property found by dividing an object's mass by its volume (density = mass ÷ volume).
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

The one-question test for a chemical change

Students mix these up constantly, so here's the key question: Is a new substance with new properties formed? If yes, it's a chemical change; if no, it's physical. Crushing chalk into powder is physical — it's still chalk. But chalk fizzing in vinegar makes a new gas (carbon dioxide) — that's chemical. Tearing paper is physical; burning it into ash and smoke is chemical.

The clues that a chemical reaction happened

You can't always see bonds breaking, but chemical changes leave fingerprints: a color change (a nail rusting), a gas (bubbles that aren't from boiling), a precipitate (a solid forming when two liquids mix), light or heat released or absorbed, and — the big one — it's hard to reverse. Any one clue is a hint; several together are strong evidence.

Why 'hard to reverse' is the giveaway

Physical changes are usually easy to undo: melt ice, then refreeze it; dissolve salt, then evaporate the water to get it back. Chemical changes are stubborn because new bonds have formed. You can't un-bake a cake or un-burn a log by cooling them, because the atoms have been rearranged into entirely new molecules. That difficulty of reversal is often the clearest sign a chemical change occurred.

The sneaky in-between: dissolving

Is dissolving sugar in water physical or chemical? It's a classic trick question — the answer is physical. The sugar molecules are still sugar; they've just spread out among the water molecules, and you can get the sugar back by evaporating the water. No new substance formed. This trips people up because it looks dramatic, but 'looks dramatic' isn't the test — 'new substance' is.

In the real world

Firefighters need to know which materials are flammable (a chemical property) so they can fight fires safely and predict how they'll spread.

Exit check

Which case changes substance identity? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

Rusting forms different substances; melting retains water identity. Appearance alone cannot establish the classification. The two cases distinguish state change from formation of new substances. The boxes are an explanation guide, not photographs or a rule that color or bubbles alone identify a reaction. Further characteristic-property evidence is needed when identity is not supplied.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Density & Floating

Learning goals

Readings for this unit

Before this unit

Divide a measured mass by a measured volume and write units.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in density & floating?

Illustrative evidence case. Illustrative block A has mass 24 g and volume 8 cm³; B has mass 48 g and volume 16 cm³. A separate hollow object has mass 48 g and enclosed volume 80 cm³.

Same density, different mass and volumeSame density, different mass and volumeA: 24 g / 8 cm³B: 48 g / 16 cm³A: 3 g/cm³B: 3 g/cm³Box sizes are schematic; use the measured volumes.Illustrative model • use the labels and stated assumptions
Doubling both mass and volume leaves their ratio unchanged. The schematic boxes are not geometrically scaled to measured volumes, so calculate from their labels. Density describes mass per volume, whereas mass alone describes the amount in each sample.

Notice and wonder

Why does B not have twice A’s density? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Calculate the three average densities and use modeled water density 1 g/cm³ to predict floating. Explain why mass alone does not rank floating behavior. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

density
Mass divided by volume.
displacement
The fluid volume moved aside by a submerged object.
average density
Total mass divided by the total volume enclosed by an object.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

Mass tells how much matter a sample contains. Volume tells how much space it occupies. Density compares them: density = mass ÷ volume. A small metal sample can be denser than a large wooden block even though the wooden block has more total mass. Include units, such as grams per cubic centimeter (g/cm³).

Same density, different mass and volumeSame density, different mass and volumeA: 24 g / 8 cm³B: 48 g / 16 cm³A: 3 g/cm³B: 3 g/cm³Box sizes are schematic; use the measured volumes.Illustrative model • use the labels and stated assumptions
Doubling both mass and volume leaves their ratio unchanged. The schematic boxes are not geometrically scaled to measured volumes, so calculate from their labels. Density describes mass per volume, whereas mass alone describes the amount in each sample.

Samples of the same uniform substance have approximately the same density at the same temperature and pressure. If one sample has twice the volume, it also has twice the mass. For an irregular solid that does not dissolve or absorb water, volume can be measured by the rise in water level when it is submerged: 1 mL is the same volume as 1 cm³.

Measure an irregular object by displacementMeasure an irregular object by displacementBefore: 40 mLAfter: 58 mLObject volume = displaced liquid volume = 58 − 40 = 18 mL.1 mL = 1 cm³; read the scale and use complete submersion.
The two graduated-cylinder records show a rise from 40 to 58 mL when an object is fully submerged without trapped bubbles or spilled liquid. Its displaced volume is 18 mL, equivalent to 18 cm³. The cylinders are schematic: use the written readings rather than measuring the artwork, and do not confuse final total volume with object volume.

An object with average density below that of its surrounding fluid can float; one with greater average density tends to sink. Average density includes enclosed air. A hollow steel ship can float even though solid steel is denser than water. The upward buoyant force balances the ship’s weight once it floats steadily.

Density compares equal volumes: a cubic centimeter of a denser material has more mass. For a regular box, find volume by multiplying length, width and height. For an irregular solid that does not dissolve, measure the rise in water level after complete immersion.

Floating depends on an object's average density compared with the fluid. A hollow steel boat can float because its enclosed air greatly increases volume without much added mass. The material's density and the whole object's average density are different quantities.

Make a fair density test with a balance, a graduated container and recorded units. Read water level at eye level, remove trapped bubbles and repeat the measurement. If densities are very close, uncertainty can prevent a confident prediction; collect better measurements instead of forcing a conclusion.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Compare equal volumes rather than total size

Mass measures the amount of matter; volume measures occupied space. Density is mass divided by volume. To compare materials fairly, imagine equal-sized portions. A large low-density block can have more total mass than a tiny high-density piece, so heavier does not always mean denser.

Same density, different mass and volumeSame density, different mass and volumeA: 24 g / 8 cm³B: 48 g / 16 cm³A: 3 g/cm³B: 3 g/cm³Box sizes are schematic; use the measured volumes.Illustrative model • use the labels and stated assumptions
Doubling both mass and volume leaves their ratio unchanged. The schematic boxes are not geometrically scaled to measured volumes, so calculate from their labels. Density describes mass per volume, whereas mass alone describes the amount in each sample.

Read the visual model

Which comparison decides density: equal masses or equal volumes?

Visual reasoning — after your attempt

Comparing the masses of equal volumes directly shows which is denser. Calculating mass divided by volume also works when the samples have different sizes.

A 20 cm³ sample of material A has mass 40 g; its density is 2 g/cm³. A 5 cm³ sample of B has mass 15 g; its density is 3 g/cm³. B is denser even though the sample of A has greater mass.

Pause and explain

Which comparison decides density: equal masses or equal volumes?

Check your reasoning after answering

Comparing the masses of equal volumes directly shows which is denser. Calculating mass divided by volume also works when the samples have different sizes.

Part 2 · Measure volume and carry the units

For a rectangular block, multiply length, width, and height using the same length unit. For a suitable irregular object, measure the increase in water level after complete immersion. This displacement method assumes the sample does not dissolve, absorb appreciable water, or trap bubbles that distort the reading.

Measure an irregular object by displacementMeasure an irregular object by displacementBefore: 40 mLAfter: 58 mLObject volume = displaced liquid volume = 58 − 40 = 18 mL.1 mL = 1 cm³; read the scale and use complete submersion.
The two graduated-cylinder records show a rise from 40 to 58 mL when an object is fully submerged without trapped bubbles or spilled liquid. Its displaced volume is 18 mL, equivalent to 18 cm³. The cylinders are schematic: use the written readings rather than measuring the artwork, and do not confuse final total volume with object volume.

Read the visual model

First find the change in liquid reading; it is the volume of the submerged object. Then combine that volume with a separately measured mass. A water displacement of 18 mL does not mean the object itself has a mass of 18 g.

If the object has mass 54 g, what density follows from these readings?

Visual reasoning — after your attempt

Volume = 58−40 = 18 cm³; density = 54/18 = 3 g/cm³, subject to the supplied complete-submersion assumptions.

A cylinder rises from 30 mL to 42 mL. The object volume is 12 mL, equivalent to 12 cm³. If mass is 24 g, density is 24/12=2 g/cm³. Use the change in reading, not the final total water volume.

Pause and explain

What error comes from using 42 mL as the object volume?

Check your reasoning after answering

It includes the original water volume. The object displaced only 12 mL; using 42 mL would underestimate its density.

Part 3 · Connect floating to the whole object

Floating depends on the average density of the whole object compared with the surrounding fluid, under the simple introductory model. Enclosed air contributes volume with little mass. A hollow boat can therefore have a lower average density than water even when its hull material is denser than water.

Three density calculations distinguish solid material from a sealed hollow object.Solid sample A54 g / 20 cm³ = 2.7Density in g/cm³Sample B16 g / 20 cm³ = 0.8Density in g/cm³Sealed hollow A54 g / 90 cm³ = 0.6Density in g/cm³Compare each whole-object average with water: 1.0 g/cm³
Supplied-data comparison. The hollow object has the same mass as sample A but a larger sealed outer volume. Its material density stays the same; its whole-object average changes.

Read the visual model

Why can a solid steel piece sink while a steel boat floats?

Visual reasoning — after your attempt

The boat includes enclosed air and displaces enough water to balance its weight. Its whole-object average density can be lower than water, unlike the solid piece.

If water enters a hollow boat, its total mass increases and its effective average density can increase. A floating object settles until its upward buoyant force balances its weight; the fraction submerged depends on the amount of fluid displaced.

Pause and explain

Why can a solid steel piece sink while a steel boat floats?

Check your reasoning after answering

The boat includes enclosed air and displaces enough water to balance its weight. Its whole-object average density can be lower than water, unlike the solid piece.

Part 4 · Decide how confident a prediction should be

Measurements are estimates. Read a graduated cylinder at eye level and repeat mass and volume measurements. Compare densities using the fluid temperature and the same units. A value very close to the fluid density may not support a confident prediction because small measurement differences can change the comparison.

Repeat volume readings before judging a boundary caseRepeat volume readings before judging a boundary caseRepeated mass 24 g; volume readings vary slightly.Volume (cm³)7.588.5123Trial numberDensity range: 24/8.1 to 24/7.9 ≈ 2.96 to 3.04 g/cm³.
With a supplied mass of 24 g, repeated volume readings of 7.9, 8.0 and 8.1 cm³ lead to density estimates of about 3.04, 3.00 and 2.96 g/cm³. The dots are repeat readings, not a trend over time. A prediction close to a comparison-fluid density needs measurement uncertainty and the whole object’s average density considered.

Read the visual model

A repeat is another measurement under intended comparable conditions. Variation can come from the method or object. Report a reasonable range and ask whether it changes the prediction instead of selecting only the most convenient reading.

Would these results justify claiming an exact density of 3.0000 g/cm³? Explain how the graph helps.

Visual reasoning — after your attempt

No. The repeated volume readings vary, giving a density range of roughly 2.96–3.04 g/cm³. The graph makes that variation visible and discourages unsupported precision.

A measured density of 0.99 g/mL with uncertainty about 0.03 g/mL overlaps water near 1.00 g/mL. Record this uncertainty and improve the measurement rather than declaring certain floating from the central value alone.

Pause and explain

Why should near-equal measured densities be treated cautiously?

Check your reasoning after answering

The plausible density range can cross the fluid density. More precise measurements or a controlled observation are needed for a confident prediction.

Density as identification evidence

An unknown sample can be compared with reference densities, but one matching ratio is not always a unique identity.

Density is mass divided by volume. To investigate a sample, measure its mass with a suitable balance and its volume by dimensions or safe displacement. Displacement is the volume of liquid moved aside by an immersed object. Subtract the initial from the final vessel reading, use compatible units and make sure the object is fully immersed. A soluble or absorbent object can change during the test and needs another method.

Density as identification evidenceDensity as identification evidenceQuantity (g/cm³)Sample U: density2.7Reference A2.7Reference B7.9Reference C2.7Illustrative model • read the labels and caption
The supplied sample and reference bars show matching values for more than one reference. Bar lengths compare stated densities, not object masses. The matching A/C values demonstrate why density can support or rule out a candidate without uniquely identify every sample; actual reference conditions and uncertainty must also be checked.

A measurement has uncertainty from scale divisions, reading angle, trapped air, method and sample variation. Compare a result with references under appropriate temperature and composition conditions. A small numerical difference may not distinguish two materials if the uncertainty is larger. A porous or hollow object’s average density is not automatically its solid material density. Repeated matched measurements can show consistency but do not repair an unsuitable volume method.

Use density as one piece of identification evidence, alongside characteristic properties such as solubility, melting behavior or conductivity. Solubility describes how much of a substance can dissolve under stated conditions; it is not the speed of dissolving. Two different materials can have overlapping densities. State whether the evidence is consistent with an identity, rejects a proposed identity, or remains insufficient. Do not label a sample certain merely because one table number matches.

Explain and apply

An illustrative unknown has mass 54 g and displacement 20 cm³. References A/C are both 2.7 g/cm³ and B is 7.9. Argue which candidates remain and plan one additional property comparison.

  • Calculate with correct units.
  • Distinguish support from unique identification.
  • Choose relevant further evidence and controls.
Reasoning and marking guidance — after your attempt

Density is 54/20=2.7 g/cm³. A and C remain consistent while B is inconsistent under matched conditions and adequate measurement precision. Density alone cannot distinguish A from C; choose a safe characteristic-property comparison with supplied reference data, such as solubility for approved samples. Name uncertainty and whether the object is homogeneous.

Apply the whole unit · Two samples and a hollow design

Illustrative measurements: sample A has mass 54 g and displaces 20 mL; sample B has mass 16 g and volume 20 cm³. A hollow object made using A has total mass 54 g and sealed outer volume 90 cm³. Use water density 1.0 g/cm³.

Your task

Calculate all three densities, predict their behavior in water under the stated assumptions, and explain how changing shape can change whole-object density without changing material density. Name a measurement that needs checking.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

A is 54/20=2.7 g/cm³ and sinks in the simple model. B is 16/20=0.8 g/cm³ and can float. The sealed hollow object averages 54/90=0.6 g/cm³ and can float. Its material remains 2.7 g/cm³; added enclosed volume changes the average. Check sealing, actual outer volume, bubbles, and mass.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Use a mass/volume/density table before discussing boats. Rehearse 1 mL=1 cm³ and the displacement subtraction. Let the learner explain the hollow case with a labeled cross-section, then check with a different set of numbers. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation. The illustrated study “Density as identification evidence” is required curriculum content. Teach it before the associated application or distribute it over the assigned unit sessions; it is not an optional enrichment. Its practice/review/quiz response provides evidence of understanding. Model/data work must not be recorded as an actual physical experiment.

The key idea

Density is mass per volume. Floating depends on the object’s average density compared with the fluid.

Worked examples

Example 1

A sample has mass 36 g and volume 12 cm³. Will it sink in water of density 1 g/cm³?
  1. Density = 36 ÷ 12 = 3 g/cm³.
  2. 3 g/cm³ is greater than 1 g/cm³.
Answer: It sinks, assuming it does not dissolve or trap enough additional air to change its average density.

Example 2 · Worked application

Two blocks have masses 24 g and 72 g and volumes 8 cm³ and 24 cm³. Are their densities different?
  1. Calculate density for each, rather than comparing masses alone.
  2. 24/8=3 g/cm³; 72/24=3 g/cm³.
  3. Both have the same mass per equal volume, though the larger block has three times the mass.
Answer: Both densities are 3 g/cm³.
Check the reasoning

Multiply density by volume: 3×8=24 and 3×24=72, recovering the masses.

Example 3

A solid has mass 54 g and raises water from 20 mL to 40 mL. Find density and predict its behavior in water of density 1 g/mL.
  1. Displaced volume is 40−20=20 mL.
  2. Density is 54/20=2.7 g/mL, greater than water's density.
Answer: 2.7 g/mL; the solid sinks if fully wetted, without trapped air or other support.

Example 4 · Find and fix the mistake

Context: Two blocks have masses 24 g and 72 g and volumes 8 cm³ and 24 cm³. Are their densities different? A student claims: “The 72 g block must be denser because it is heavier.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Multiply density by volume: 3×8=24 and 3×24=72, recovering the masses.
  2. Density compares mass per volume. A larger sample can be heavier while having the same density.
Answer: Density compares mass per volume. A larger sample can be heavier while having the same density.
Check the reasoning

Multiply density by volume: 3×8=24 and 3×24=72, recovering the masses.

Example 5 · Interpret the visual model

Measure an irregular object by displacementMeasure an irregular object by displacementBefore: 40 mLAfter: 58 mLObject volume = displaced liquid volume = 58 − 40 = 18 mL.1 mL = 1 cm³; read the scale and use complete submersion.
The two graduated-cylinder records show a rise from 40 to 58 mL when an object is fully submerged without trapped bubbles or spilled liquid. Its displaced volume is 18 mL, equivalent to 18 cm³. The cylinders are schematic: use the written readings rather than measuring the artwork, and do not confuse final total volume with object volume.
If the object has mass 54 g, what density follows from these readings?
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. First find the change in liquid reading; it is the volume of the submerged object. Then combine that volume with a separately measured mass. A water displacement of 18 mL does not mean the object itself has a mass of 18 g.
  3. Volume = 58−40 = 18 cm³; density = 54/18 = 3 g/cm³, subject to the supplied complete-submersion assumptions.
Answer: Volume = 58−40 = 18 cm³; density = 54/18 = 3 g/cm³, subject to the supplied complete-submersion assumptions.
Check the reasoning

Keep the model’s stated limits explicit: The two graduated-cylinder records show a rise from 40 to 58 mL when an object is fully submerged without trapped bubbles or spilled liquid. Its displaced volume is 18 mL, equivalent to 18 cm³. The cylinders are schematic: use the written readings rather than measuring the artwork, and do not confuse final total volume with object volume.

Avoid these mistakes

Check your understanding

A solid has mass 54 g and raises water from 20 mL to 40 mL. Find density and predict its behavior in water of density 1 g/mL.

Discuss the answer

2.7 g/mL; the solid sinks if fully wetted, without trapped air or other support.

Why can a steel ship float while a small solid steel piece sinks?

Discuss the answer

Density compares equal volumes: a cubic centimeter of a denser material has more mass. For a regular box, find volume by multiplying length, width and height. For an irregular solid that does not dissolve, measure the rise in water level after complete immersion. Floating depends on an object's average density compared with the fluid. A hollow steel boat can float because its enclosed air greatly increases volume without much added mass. The material's density and the whole object's average density are different quantities.

Return to the phenomenon

Illustrative block A has mass 24 g and volume 8 cm³; B has mass 48 g and volume 16 cm³. A separate hollow object has mass 48 g and enclosed volume 80 cm³. Calculate the three average densities and use modeled water density 1 g/cm³ to predict floating. Explain why mass alone does not rank floating behavior. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

A and B each have density 3 g/cm³; the hollow object averages 0.6 g/cm³. A and B tend to sink if no other supporting effect dominates; the hollow object can float if it keeps that effective enclosed volume and displaces sufficient water. Larger mass does not imply larger density, and a leak can change the hollow object’s average density.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

Illustrative block A has mass 24 g and volume 8 cm³; B has mass 48 g and volume 16 cm³. A separate hollow object has mass 48 g and enclosed volume 80 cm³. Calculate the three average densities and use modeled water density 1 g/cm³ to predict floating. Explain why mass alone does not rank floating behavior. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

A and B each have density 3 g/cm³; the hollow object averages 0.6 g/cm³. A and B tend to sink if no other supporting effect dominates; the hollow object can float if it keeps that effective enclosed volume and displaces sufficient water. Larger mass does not imply larger density, and a leak can change the hollow object’s average density.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

Why does B not have twice A’s density? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

Doubling both mass and volume leaves their ratio unchanged. The schematic boxes are not geometrically scaled to measured volumes, so calculate from their labels. Density describes mass per volume, whereas mass alone describes the amount in each sample.

Response guidance — discuss after your attempt

Its mass and volume both double, so 48/16 equals 24/8, or 3 g/cm³. Doubling both mass and volume leaves their ratio unchanged. The schematic boxes are not geometrically scaled to measured volumes, so calculate from their labels. Density describes mass per volume, whereas mass alone describes the amount in each sample.

Words to know

density
Mass divided by volume.
displacement
The fluid volume moved aside by a submerged object.
average density
Total mass divided by the total volume enclosed by an object.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

In the real world

Exit check

Why does B not have twice A’s density? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

Its mass and volume both double, so 48/16 equals 24/8, or 3 g/cm³. Doubling both mass and volume leaves their ratio unchanged. The schematic boxes are not geometrically scaled to measured volumes, so calculate from their labels. Density describes mass per volume, whereas mass alone describes the amount in each sample.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

The Periodic Table

Learning goals

Readings for this unit

Before this unit

Use proton count to identify elements.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in the periodic table?

Illustrative evidence case. Supplied records describe element A with atomic number 11 and outer-shell electron count 1, and B with atomic number 12 and outer-shell count 2. Both are main-group elements in period 3.

A main-group pattern in period 3A main-group pattern in period 3Na: 11 protons1 outer electronGroup 1Mg: 12 protons2 outer electronsGroup 2Al: 13 protons3 outer electronsGroup 13Atomic number increases →; selected elements only.Illustrative model • use the labels and stated assumptions
These selected main-group elements illustrate increasing proton count and outer-electron patterns. They are not the complete periodic table. The simple outer-electron pattern is useful for these elements, with qualifications for helium and transition elements; proton count defines the element.

Notice and wonder

What fixes the order shown? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Place the records in order by atomic number and explain which properties their position can suggest. State a limit of a shell drawing and of group rules. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

periodic table
A chart that organizes all known elements by increasing atomic number and by shared properties.
period
A horizontal row ordered by atomic number; in the introductory shell model, the period relates to the highest occupied principal shell.
group (family)
A vertical column showing related property patterns. Main-group elements often share an outer-electron count, with qualifications for helium and transition elements.
valence electron
An electron in an atom's outermost shell; it mostly determines how the atom bonds with others.
metalloid
An element with properties between metals and nonmetals, found along the zigzag line on the periodic table.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

The periodic table can look like an intimidating wall of boxes, but it's really one of the most brilliant organizing tools in all of science — a map that sorts every known element by its structure and behavior. The elements are laid out left to right and top to bottom in order of increasing atomic number (that's the number of protons), so each box holds exactly one more proton than the box before it. What makes the table 'periodic' is that similar properties keep showing up again and again at regular intervals, like a repeating pattern.

Read atomic number separately from average atomic massRead atomic number separately from average atomic mass11NaSodium22.99 u (average)Atomic number → protonsA common Na-23 atom has 11 protons and 12 neutrons; the decimal is an average.
This sodium element card separates atomic number 11 from average atomic mass about 22.99 u. The atomic number fixes proton count; a neutral sodium atom also has eleven electrons. A specified Na-23 isotope has twelve neutrons. The decimal average is not the neutron count, total charge or an exact number of particles in every atom.

Each horizontal row is a period, and each vertical column is a group (also called a family). These aren't just labels. Elements in the same period share the same number of electron shells, and — more importantly — elements in the same group behave alike chemically. Sodium and potassium sit in the same column and are both soft, silvery metals that react vigorously with water, even though one is considerably heavier than the other.

For main-group elements, similar outer-electron arrangements often explain similar chemical behavior within a group. The outer electrons participate in bonding. Lithium, sodium, and potassium each have one outer electron in the introductory shell model, but they are different elements with different measured properties. Hydrogen occupies a special position and should not be assumed to behave exactly like an alkali metal. Transition-element patterns require more detailed models than this simple shortcut.

A periodic-table column is a pattern, not one elementA periodic-table column is a pattern, not one element3LiLithium1 outer electron11NaSodium1 outer electron19KPotassium1 outer electronGroup 1: similar outer-electron pattern, different proton counts.Hydrogen shares the column but is a nonmetal with important differences.
Lithium, sodium and potassium are selected Group 1 metals. They have different atomic numbers and total electron counts but a comparable outer-electron pattern that helps explain related chemical behavior. Hydrogen is an important nonmetal exception in this column. The cards omit most elements and do not claim identical reaction rates or literal electron shells.

The table also sorts elements into three big regions. Metals — most of the table, filling the left and center — are typically shiny, bendable (malleable), and good conductors of heat and electricity. Nonmetals, clustered in the upper right, are usually dull, brittle when solid, and poor conductors. Squeezed along the zigzag staircase between them are the metalloids, in-betweeners like silicon that share a mix of metal and nonmetal traits — which is exactly what makes them so valuable in computer chips.

Finally, smooth patterns called periodic trends run across the table. Atomic size, for example, generally shrinks as you move left to right across a period, because each added proton tugs the electron cloud in a little tighter. The real payoff of all this organization is prediction: once you can read an element's position, you can make a confident guess about how it will behave — its reactivity, its bonding, even roughly its size — without ever running an experiment.

A period is a horizontal row; a group is a vertical column. Main-group elements in one group often have similar chemical behavior because their outer electron arrangements are similar. This pattern helps make predictions, but it does not make every member identical.

Metals generally conduct electricity and can be shaped; nonmetals show a wider range of properties. A material's actual use also depends on strength, density and reaction with its surroundings. Read the key supplied with a periodic table because colors and symbols vary between tables.

Use a table in a sequence: find the symbol, read atomic number, then look at group and period. Do not confuse atomic number with atomic mass. At this level, use recurring patterns as evidence for a prediction and check actual data before calling the prediction certain.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Read one element box carefully

A periodic-table box usually shows a symbol, an atomic number, and an atomic mass. Read the table key because formats differ. Atomic number counts protons and identifies the element. A symbol is a short name, not a chemical formula for every substance containing that element.

Read atomic number separately from average atomic massRead atomic number separately from average atomic mass11NaSodium22.99 u (average)Atomic number → protonsA common Na-23 atom has 11 protons and 12 neutrons; the decimal is an average.
This sodium element card separates atomic number 11 from average atomic mass about 22.99 u. The atomic number fixes proton count; a neutral sodium atom also has eleven electrons. A specified Na-23 isotope has twelve neutrons. The decimal average is not the neutron count, total charge or an exact number of particles in every atom.

Read the visual model

The unit u is an atomic-mass unit used for masses at the atomic scale. Mass number is a count, whereas the listed average mass is a measured average for an isotope mixture. Keep both distinct from atomic number.

How many protons and electrons does a neutral Na-23 atom have, and why is rounding 22.99 not a definition of every sodium isotope?

Visual reasoning — after your attempt

It has 11 protons and 11 electrons. Na-23 has 12 neutrons because its specified mass number is 23. The decimal table value is an isotope-weighted average, not an isotope definition.

For an element with atomic number 11, a neutral atom has 11 protons and 11 electrons. A decimal atomic mass is an isotope average; it should not be interpreted as a fractional number of protons or neutrons inside a single atom.

Pause and explain

Which entry should you read first to identify an element?

Check your reasoning after answering

Read its symbol and atomic number. The proton count determines element identity; the atomic mass is a different quantity.

Part 2 · Find recurring patterns in columns

A group is a vertical column and a period is a horizontal row. For main-group elements, similar outer-electron arrangements help explain recurring chemical behavior within a group. Similarity supports predictions; it does not mean group members have identical density, melting point, or reaction rate.

A periodic-table column is a pattern, not one elementA periodic-table column is a pattern, not one element3LiLithium1 outer electron11NaSodium1 outer electron19KPotassium1 outer electronGroup 1: similar outer-electron pattern, different proton counts.Hydrogen shares the column but is a nonmetal with important differences.
Lithium, sodium and potassium are selected Group 1 metals. They have different atomic numbers and total electron counts but a comparable outer-electron pattern that helps explain related chemical behavior. Hydrogen is an important nonmetal exception in this column. The cards omit most elements and do not claim identical reaction rates or literal electron shells.

Read the visual model

A group is a vertical column in the periodic table. An outer electron is one involved in the atom’s outer arrangement and often in chemical interactions. Use the pattern to form a prediction, then account for exceptions and evidence.

Why can Li and Na have related chemical behavior without being the same element?

Visual reasoning — after your attempt

They have comparable outer-electron arrangements but different proton counts: 3 for Li and 11 for Na. Related behavior is not identical identity.

Sodium and potassium belong to the same group and can show related reaction patterns. Hydrogen occupies a special position and should not be assumed to behave exactly like an alkali metal. Use actual data to test a table-based prediction.

A main-group pattern in period 3A main-group pattern in period 3Na: 11 protons1 outer electronGroup 1Mg: 12 protons2 outer electronsGroup 2Al: 13 protons3 outer electronsGroup 13Atomic number increases →; selected elements only.Illustrative model • use the labels and stated assumptions
These selected main-group elements illustrate increasing proton count and outer-electron patterns. They are not the complete periodic table. The simple outer-electron pattern is useful for these elements, with qualifications for helium and transition elements; proton count defines the element.

Pause and explain

Does being in the same group make two elements identical?

Check your reasoning after answering

No. It suggests related chemical behavior for many main-group elements, but the elements retain different proton counts and can differ strongly in other properties.

Part 3 · Use broad regions with exceptions in mind

Many metals conduct electricity and can be shaped; many nonmetals have quite different properties. Some elements have characteristics that do not fit a simple either-or division. The table organizes elements, while a real material may be a mixture, alloy, or compound whose properties need separate investigation.

Metals, metalloids and non-metalsBroad regions, with exceptions that mattermetalsmetalloidsnon-metalsHydrogen sits with the metals by position and behaves as a non-metal
The regions are a useful first approximation and the exceptions are where the chemistry gets interesting. Treating the boundary as a hard line, or forgetting hydrogen, is what the note is there to prevent.

Read the visual model

Why does sodium in table salt not make salt behave like sodium metal?

Visual reasoning — after your attempt

Bonding produces a compound with a different structure and properties. The presence of sodium atoms does not make the compound identical to elemental sodium.

A sodium atom belongs to a reactive metal element. Table salt is a compound of sodium and chlorine with properties unlike either element. Do not assign a compound the same properties as an isolated element just because the element is listed in its formula.

Pause and explain

Why does sodium in table salt not make salt behave like sodium metal?

Check your reasoning after answering

Bonding produces a compound with a different structure and properties. The presence of sodium atoms does not make the compound identical to elemental sodium.

Part 4 · Turn a pattern into a testable prediction

Use position to make a limited claim, then say what observation could test it. Comparisons should specify the property and conditions. A table prediction is a starting model rather than a substitute for data, and broad trends can have exceptions that become important in more advanced chemistry.

A periodic pattern makes a testable predictionA periodic pattern makes a testable predictionKnown AProtons: 31Model property: 30Predicted gapProtons: 32Model property: 80Known BProtons: 33Model property: 120A pattern suggests a prediction; the missing property is not yet measured.Compare new evidence with the prediction and revise if it disagrees.
This deliberately invented three-card dataset models how a gap in an organized pattern can suggest a property to test. The middle value is a proposed prediction, not a real melting point for a named element. Atomic number orders the cards, while comparison of properties informs the prediction; actual periodic patterns are not universally straight-line trends.

Read the visual model

A prediction goes beyond the records already collected. State what could confirm or challenge it. A periodic trend is useful because it guides that test, not because every real property changes by an equal amount across a row.

Which middle-card value is fixed by element identity, and which needs experimental evidence in this model?

Visual reasoning — after your attempt

The proton count 32 fixes identity. The proposed property value 80 is a prediction and needs an appropriate measurement; it is not established by the empty card.

If an unfamiliar main-group element lies below a familiar one, predict some related chemical behavior and check a reliable property table. Do not perform hazardous reaction tests at home to confirm the prediction; supplied data can test the reasoning.

Pause and explain

What makes a periodic-table prediction scientifically useful?

Check your reasoning after answering

It names a specific property or behavior and an observation that could support or challenge it, while recognizing the limits of the pattern.

Apply the whole unit · Use a small element data set

Illustrative reference records: A has atomic number 3, group 1, period 2; B has atomic number 11, group 1, period 3; C has atomic number 10, group 18, period 2. The supplied table identifies them as lithium, sodium, and neon.

Your task

Find neutral proton and electron counts; identify a same-group pair and a same-period pair. Predict which pair may have related chemical behavior and explain why similar placement cannot establish identical properties.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

A has 3 protons/electrons, B has 11, and C has 10. A and B share group 1; A and C share period 2. A and B have related outer-electron arrangements and chemical patterns, but are different elements. Same-period placement alone does not imply similar reactivity. Test a specified prediction with reliable property data.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Practice locating boxes before introducing trends. Restrict outer-electron shortcuts to appropriate main-group examples. Ask the learner to distinguish an element from a compound and a measured property from a predicted pattern. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation.

The key idea

The periodic table organizes elements by atomic number; elements in the same group share valence electrons and similar properties.

Worked examples

Example 1

An element is in Group 1, Period 3. Name the element and predict two of its properties.
  1. Group 1, Period 3 locates the element as sodium (Na).
  2. Group 1 elements (alkali metals) have 1 valence electron.
  3. Alkali metals are soft, shiny metals that react strongly, especially with water.
Answer: Sodium (Na); soft, shiny, and highly reactive, especially with water

Example 2 · Worked application

A table places lithium and sodium in group 1, but sodium and magnesium in the same period. Which pair is more likely to have similar outer-electron patterns?
  1. Identify a group as a vertical column and a period as a row.
  2. Lithium and sodium share a main group, associated with similar valence-electron patterns.
  3. Predict some similar chemical behavior, without assuming identical rates or every property.
Answer: Lithium and sodium are the stronger prediction for similar outer-electron patterns.
Check the reasoning

Check the group labels; neighboring position alone is not the comparison rule.

Example 3

Element X has atomic number 12 and element Y has atomic number 20. Both are in group 2. What can you infer?
  1. Their proton counts are 12 and 20, so they are different elements.
  2. Their shared main group suggests similar outer-electron patterns and some similar reactions.
Answer: They are different elements with some similar chemical properties; the table alone does not give identical reaction rates.

Example 4 · Find and fix the mistake

Context: A table places lithium and sodium in group 1, but sodium and magnesium in the same period. Which pair is more likely to have similar outer-electron patterns? A student claims: “Elements beside each other always behave identically.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Check the group labels; neighboring position alone is not the comparison rule.
  2. A row includes changing outer-electron arrangements. Similarity is a pattern with limits, not identity of all properties.
Answer: A row includes changing outer-electron arrangements. Similarity is a pattern with limits, not identity of all properties.
Check the reasoning

Check the group labels; neighboring position alone is not the comparison rule.

Example 5 · Interpret the visual model

Read atomic number separately from average atomic massRead atomic number separately from average atomic mass11NaSodium22.99 u (average)Atomic number → protonsA common Na-23 atom has 11 protons and 12 neutrons; the decimal is an average.
This sodium element card separates atomic number 11 from average atomic mass about 22.99 u. The atomic number fixes proton count; a neutral sodium atom also has eleven electrons. A specified Na-23 isotope has twelve neutrons. The decimal average is not the neutron count, total charge or an exact number of particles in every atom.
How many protons and electrons does a neutral Na-23 atom have, and why is rounding 22.99 not a definition of every sodium isotope?
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. The unit u is an atomic-mass unit used for masses at the atomic scale. Mass number is a count, whereas the listed average mass is a measured average for an isotope mixture. Keep both distinct from atomic number.
  3. It has 11 protons and 11 electrons. Na-23 has 12 neutrons because its specified mass number is 23. The decimal table value is an isotope-weighted average, not an isotope definition.
Answer: It has 11 protons and 11 electrons. Na-23 has 12 neutrons because its specified mass number is 23. The decimal table value is an isotope-weighted average, not an isotope definition.
Check the reasoning

Keep the model’s stated limits explicit: This sodium element card separates atomic number 11 from average atomic mass about 22.99 u. The atomic number fixes proton count; a neutral sodium atom also has eleven electrons. A specified Na-23 isotope has twelve neutrons. The decimal average is not the neutron count, total charge or an exact number of particles in every atom.

Avoid these mistakes

Check your understanding

Element X has atomic number 12 and element Y has atomic number 20. Both are in group 2. What can you infer?

Discuss the answer

They are different elements with some similar chemical properties; the table alone does not give identical reaction rates.

Why is a group more useful than color on a table for predicting chemical similarities?

Discuss the answer

A period is a horizontal row; a group is a vertical column. Main-group elements in one group often have similar chemical behavior because their outer electron arrangements are similar. This pattern helps make predictions, but it does not make every member identical. Metals generally conduct electricity and can be shaped; nonmetals show a wider range of properties. A material's actual use also depends on strength, density and reaction with its surroundings. Read the key supplied with a periodic table because colors and symbols vary between tables.

Return to the phenomenon

Supplied records describe element A with atomic number 11 and outer-shell electron count 1, and B with atomic number 12 and outer-shell count 2. Both are main-group elements in period 3. Place the records in order by atomic number and explain which properties their position can suggest. State a limit of a shell drawing and of group rules. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

A precedes B because atomic number counts protons and 11 is less than 12. In these main-group examples, the outer electrons help explain characteristic bonding patterns. Period and group organize patterns, not a guarantee that all neighboring elements behave identically. Shell circles are a simplified electron-energy representation; transition elements and helium need qualifications to simple valence rules.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

Supplied records describe element A with atomic number 11 and outer-shell electron count 1, and B with atomic number 12 and outer-shell count 2. Both are main-group elements in period 3. Place the records in order by atomic number and explain which properties their position can suggest. State a limit of a shell drawing and of group rules. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

A precedes B because atomic number counts protons and 11 is less than 12. In these main-group examples, the outer electrons help explain characteristic bonding patterns. Period and group organize patterns, not a guarantee that all neighboring elements behave identically. Shell circles are a simplified electron-energy representation; transition elements and helium need qualifications to simple valence rules.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

What fixes the order shown? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

These selected main-group elements illustrate increasing proton count and outer-electron patterns. They are not the complete periodic table. The simple outer-electron pattern is useful for these elements, with qualifications for helium and transition elements; proton count defines the element.

Response guidance — discuss after your attempt

Atomic number, the proton count, orders Na 11, Mg 12 and Al 13. The display omits most elements and does not claim identical reactivity. These selected main-group elements illustrate increasing proton count and outer-electron patterns. They are not the complete periodic table. The simple outer-electron pattern is useful for these elements, with qualifications for helium and transition elements; proton count defines the element.

Words to know

periodic table
A chart that organizes all known elements by increasing atomic number and by shared properties.
period
A horizontal row ordered by atomic number; in the introductory shell model, the period relates to the highest occupied principal shell.
group (family)
A vertical column showing related property patterns. Main-group elements often share an outer-electron count, with qualifications for helium and transition elements.
valence electron
An electron in an atom's outermost shell; it mostly determines how the atom bonds with others.
metalloid
An element with properties between metals and nonmetals, found along the zigzag line on the periodic table.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

How Mendeleev predicted elements that didn't exist yet

When Dmitri Mendeleev arranged the known elements by properties in 1869, he did something bold: he left empty gaps where the pattern demanded an element that hadn't been discovered. He even predicted the properties of these missing elements. When gallium and germanium were later found and matched his predictions almost exactly, the periodic table went from a clever chart to one of science's most powerful predictive tools.

Reading the table: periods and groups

The table isn't just a list — its shape is the information. Each row (period) tells you how many electron shells an atom has: period 3 elements have 3 shells. Each column (group) shares the same number of valence (outer) electrons, which is why they behave alike. Group 1 metals all have 1 valence electron and all react violently with water; Group 18 (noble gases) all have full outer shells, which is why they barely react at all.

The families you should know

Alkali metals (Group 1) are so reactive they're stored in oil so they don't react with air. Halogens (Group 17) are one electron short of full, so they're 'hungry' and grab electrons — great at forming salts (sodium + chlorine → table salt). Noble gases (Group 18) are the loners with full shells: stable, unreactive, and used where you need something that won't react, like argon in lightbulbs. Transition metals in the middle (iron, copper, gold) are the everyday metals — good conductors, strong, and often colorful in compounds.

Why the table predicts reactivity

Atoms 'want' a full outer shell (usually 8 electrons — the octet rule). An element's spot on the table tells you how it will get there. Sodium (1 valence electron) easily loses that electron; chlorine (7 valence electrons) easily gains one. Put them together and sodium hands its electron to chlorine — that transfer is a chemical reaction, and it's completely predictable from their positions. This is the bridge from the periodic table into the next unit on chemical reactions.

Metals, nonmetals, and the staircase

A zig-zag 'staircase' line on the right side of the table separates metals (left, most of the table — shiny, conductive, bendable) from nonmetals (right — dull, brittle, poor conductors). The elements hugging that line, like silicon and germanium, are metalloids: they act in-between, which is exactly what makes them perfect semiconductors for the computer chips in every phone and laptop.

In the real world

Chemists use the periodic table's patterns to predict how newly created or rarely-seen elements will behave, even before testing them.

Exit check

What fixes the order shown? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

Atomic number, the proton count, orders Na 11, Mg 12 and Al 13. The display omits most elements and does not claim identical reactivity. These selected main-group elements illustrate increasing proton count and outer-electron patterns. They are not the complete periodic table. The simple outer-electron pattern is useful for these elements, with qualifications for helium and transition elements; proton count defines the element.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Materials: Properties, Uses & Impacts

Learning goals

Readings for this unit

Before this unit

Compare measurable properties and identify a design constraint.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in materials: properties, uses & impacts?

Illustrative evidence case. Illustrative container trials give material A 0 leaks in 3 tests but only 2 successful reuse cycles; B 1 leak in 3 tests and 20 reuse cycles. Costs and manufacturing impacts are unknown.

A material choice has a whole lifeA material choice has a whole lifeResourceObtain raw materialMeasure impactsProduction / useEnergy and changesReuse and repairAfter useRecycle or disposeFurther impactsIllustrative model • use the labels and stated assumptions
A life-cycle model asks about resources, processing, use and what happens afterward. Arrows represent stages to investigate rather than equal impact amounts. A material can perform well in a leak test without that test establishing its entire environmental impact.

Notice and wonder

Which stage is measured by a one-minute leak test? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Choose a provisional material for one stated use. Compare water resistance and reuse, and specify a missing measurement instead of declaring a universal winner. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

synthetic material
A material made through human-directed processing, often involving chemical reactions.
constraint
A limit that a design must satisfy.
trade-off
A benefit gained at the cost of another desirable feature.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

A material is useful because of its properties. A raincoat needs to resist water and bend; a cooking pan should transfer thermal energy and keep its shape. There is no single “best” material. A choice depends on the task, the evidence, and limits such as cost, mass, or durability.

Choosing a material for a stated jobDefine the job before choosing the materialState the jobList requirementsCompare materialsTest and revisewhat must it do,for how longstrength, mass,cost, conductivityon the samemeasurementsagainst the statedrequirements“The strongest material” is not an answer until strong in what sense is stated
Materials have no ranking independent of a purpose. Steel beats aluminium on stiffness and loses on mass per unit strength, so the requirement decides, which is why the job has to be written down first.

People make synthetic materials by processing resources and, often, using chemical reactions to create substances with different properties. Many plastics start with chemicals obtained from petroleum or natural gas. Some are made from plant-derived resources. “Synthetic” describes how a material is made; it does not by itself tell us whether the material is harmful or helpful.

Evaluate the whole use: where the resources come from, energy used in production, useful lifetime, and what happens afterward. A reusable container may reduce waste if it is used many times. A material that lasts a long time can be useful in a building yet create a disposal problem when discarded. Support comparisons with evidence and identify information you still need.

Material arrangement affects how energy crosses a containerMaterial arrangement affects how energy crosses a containerSingle wallTwo walls + air gapA gap can reduce one conduction pathway; it does not stop all transfers.Structure changes a mechanism. Test the resulting temperature and other criteria.
The two schematics distinguish a single wall from an arrangement with two walls and an air gap. A gap can reduce some conduction pathways, while radiation, air movement and contact bridges can still transfer energy. The model predicts a mechanism, not a guaranteed performance ranking without comparable measurements. Wall thickness, sealing, material amount and cost also matter.

Start a material choice by naming the job and constraints. A raincoat must keep water out and allow movement; a bridge cable needs strength under tension. Rank the important properties before comparing materials, because one useful property may come with an unwanted trade-off.

Use measurements rather than labels such as natural or synthetic as a substitute for evidence. Record how many times a material can be reused, how much mass is needed and how it behaves in the intended environment. Production methods can change the properties of materials made from similar resources.

A life-cycle comparison includes resource extraction, manufacture, use and disposal. Compare equivalent jobs, such as carrying the same groceries for a year. A durable product used only once may lose the benefit of durability. State missing evidence and explain how it could change the decision.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Define the job before choosing a material

A material is useful when its properties match a job. Begin with criteria such as strength, flexibility, insulation, or water resistance. Constraints are limits such as cost or total mass. A material that succeeds in one job can fail in another, so the word best needs a stated purpose.

Choosing a material for a stated jobDefine the job before choosing the materialState the jobList requirementsCompare materialsTest and revisewhat must it do,for how longstrength, mass,cost, conductivityon the samemeasurementsagainst the statedrequirements“The strongest material” is not an answer until strong in what sense is stated
Materials have no ranking independent of a purpose. Steel beats aluminium on stiffness and loses on mass per unit strength, so the requirement decides, which is why the job has to be written down first.

Read the visual model

What is the difference between a criterion and a constraint?

Visual reasoning — after your attempt

A criterion is a desired performance, such as preventing leaks. A constraint is a limit, such as a maximum mass or budget, that a proposed solution must meet.

A food container may need to resist leaks and repeated washing. A window must transmit visible light. List must-have requirements separately from desirable features before reading a comparison table; otherwise a convenient feature can hide a failure of the main job.

Pause and explain

What is the difference between a criterion and a constraint?

Check your reasoning after answering

A criterion is a desired performance, such as preventing leaks. A constraint is a limit, such as a maximum mass or budget, that a proposed solution must meet.

Part 2 · Link structure and processing to properties

Materials may come directly from resources or be processed into new forms. Synthetic describes manufacture, not an automatic judgment about safety or usefulness. Processing, composition, and structure can affect flexibility, strength, or durability, so materials from a similar resource need not behave the same way.

Material arrangement affects how energy crosses a containerMaterial arrangement affects how energy crosses a containerSingle wallTwo walls + air gapA gap can reduce one conduction pathway; it does not stop all transfers.Structure changes a mechanism. Test the resulting temperature and other criteria.
The two schematics distinguish a single wall from an arrangement with two walls and an air gap. A gap can reduce some conduction pathways, while radiation, air movement and contact bridges can still transfer energy. The model predicts a mechanism, not a guaranteed performance ranking without comparable measurements. Wall thickness, sealing, material amount and cost also matter.

Read the visual model

Structure describes how materials are arranged; a property describes their measured response under conditions. Processing and assembly can change the arrangement. A useful design explanation connects the feature to a particular mechanism and a measurable outcome.

Why is “two walls means no heat can enter” not supported? Name a remaining pathway and a relevant test.

Visual reasoning — after your attempt

Radiation or conduction through contacts can remain, and moving air may contribute. Compare matched temperature-versus-time records and other design criteria instead of claiming all energy transfer stops.

A rigid plastic container and a flexible plastic film can serve different jobs. The label plastic alone does not identify a single property set. Compare measurements for the actual product and its intended temperature and use conditions.

OpenSciEd magnified cross-section of a mirror showing glass, a continuous metal coating and a protective layer, with incoming light rays.
The OpenSciEd magnification model shows glass and a continuous reflective layer in an ordinary mirror. A material’s structure can change its response to light. It is a schematic cross-section rather than a microscope photograph, and it does not by itself measure a coating’s environmental impact or prove that every ray is reflected. Continuous coating on an ordinary mirror · OpenSciEd · 6.1 Light & Matter, Lesson 4, source, CC BY 4.0. Figure excerpt rendered from the PDF and resized for the web.
OpenSciEd magnified cross-section of a one-way mirror showing separated reflective patches on transparent glass, with incoming light rays.
OpenSciEd uses this simplified transparent/reflective-region drawing to model a one-way mirror. The model helps compare material structure with reflection and transmission. Real thin coatings have more detailed optical behavior; these schematic patches should not be mistaken for a literal photograph of every manufactured film. Partial coating on a one-way mirror · OpenSciEd · 6.1 Light & Matter, Lesson 4, source, CC BY 4.0. Figure excerpt rendered from the PDF and resized for the web.

Pause and explain

Why is natural versus synthetic insufficient for choosing a container?

Check your reasoning after answering

Those labels do not supply evidence of leakage, durability, safety in intended use, or disposal impacts. The actual material properties and use conditions matter.

Part 3 · Compare an equivalent amount of service

A life-cycle comparison considers extraction, manufacture, transport, use, and disposal. Choose a common service before comparing totals, such as carrying the same load for 100 trips. A reusable product needs enough reuse to realize its advantages; repair, cleaning, and replacement can affect the comparison.

The same materials on two criteriaComparing on an equal basisstrengthmass for the same strengthSteelAluminiumWoodPlasticIllustrative values. Steel is strongest and aluminium is lighter for the same strength —so which wins depends entirely on whether mass matters
Illustrative figures, not measured data. The point is the reversal: a ranking that looks decisive on one criterion can invert on another, which is why a comparison has to state which property it is comparing.

Read the visual model

Why compare 50 trips rather than one container of each kind?

Visual reasoning — after your attempt

One container of each may deliver different amounts of service. Comparing the same number of trips makes the performance and resource comparison meaningful.

If one container lasts 50 trips and another lasts 5, compare the number needed for the same 50 trips. Their masses and production demands may differ, and mass discarded is only one environmental measure, not a complete impact score.

A material choice has a whole lifeA material choice has a whole lifeResourceObtain raw materialMeasure impactsProduction / useEnergy and changesReuse and repairAfter useRecycle or disposeFurther impactsIllustrative model • use the labels and stated assumptions
A life-cycle model asks about resources, processing, use and what happens afterward. Arrows represent stages to investigate rather than equal impact amounts. A material can perform well in a leak test without that test establishing its entire environmental impact.
OpenSciEd three labeled setup photographs comparing light-sensor placement for incoming, reflected and transmitted light around a cup; the fixed positions make the comparison meaningful.
The original OpenSciEd setup fixes sensor positions for incoming, reflected and transmitted light. A fair comparison depends on the method as well as material choice. These are equipment/setup photographs, not performance results; use the labeled positions to explain what each measurement would represent. Light-sensor positions for incoming, reflected and transmitted light · OpenSciEd · 6.2 Thermal Energy, Lesson 8, source, CC BY 4.0. Figure excerpt rendered from the PDF and resized for the web.

Pause and explain

Why compare 50 trips rather than one container of each kind?

Check your reasoning after answering

One container of each may deliver different amounts of service. Comparing the same number of trips makes the performance and resource comparison meaningful.

Part 4 · Revise a design from measured evidence

Test relevant properties using a repeatable method and a safe sample. Keep load, exposure, and test time comparable. Record failures as well as successes. Select a design that satisfies required criteria, then explain the trade-off and a missing measurement that could change the choice.

Revise a design feature, then measure its performanceRevise a design feature, then measure its performanceWater leaked (mL)024680123Time (min)A: unsealed seamB: revised seamSame water volume, temperature and test duration; illustrative records.
The supplied prototype records compare water leaked through an original seam (A) and a revised seam (B) during a three-minute test. B loses less water under matched conditions. That supports this particular leak-performance claim, not a conclusion about all lifetime environmental impacts, costs or every future trial.

Read the visual model

A design criterion is a requirement for success; a constraint is a limit such as cost or size. Use the graph to evaluate the stated leak criterion, then test whether the same revision still meets the other requirements.

At three minutes, how much less water has B leaked? What further check is needed before claiming the improvement is reliable?

Visual reasoning — after your attempt

A leaked 6 mL and B 1.5 mL, a difference of 4.5 mL. Repeat matched tests and consider variation; a single modeled comparison does not establish all design criteria.

For a leak test, use the same water volume and observation interval. For repeated-use data, record how many trials each sample survives. One successful test supports only that tested condition; it does not prove unlimited durability.

Pause and explain

How could an unequal test load make a comparison misleading?

Check your reasoning after answering

A weaker load may make one material appear more durable. Comparable loads and methods are needed to attribute a difference to the material or design.

Natural resources and different plastics

A flexible film and a rigid plastic container can both be called plastic yet serve very different purposes.

A natural resource is material or energy obtained from the environment, such as petroleum, natural gas, minerals or plant matter. Synthetic means made through human processing, often with chemical changes. The distinction describes origin and manufacture, not an automatic judgment that natural is safe or synthetic is harmful. A processed natural resource can become a new material with properties suited to a task.

Natural resources and different plasticsNatural resources and different plasticsNatural resourcePetroleum / plantsMaterial feedstockProcessingChange combinationsMake polymer materialProperties / impactActual performanceUse and disposalIllustrative model • read the labels and caption
The original process model links resources, manufacture and evaluated use. It does not claim that all plastics share one resource, structure or impact. A molecular chain picture is explanatory, while performance and impact require actual evidence from appropriate sources and conditions.

Many plastics are polymers, materials containing long molecular chains. Chain composition, arrangement, branching, interactions and additives can change strength, flexibility and response to warming. An additive is an ingredient included to alter performance or processing. We do not need to memorize every plastic code to understand why all plastics are not equivalent. Some soften enough to reshape on warming, while others have networks that resist such reshaping; neither group should be heated or burned in a home identification test.

Evaluate a material using more than one source and the same useful service. A manufacturer’s durability claim, a measured reuse record and a disposal guide answer different questions. Ask who produced each source, which conditions it tested, what evidence it provides and what it omits. Include benefits such as clean-water delivery or durable equipment as well as concerns about resource use, production, waste and exposure. A balanced explanation assesses evidence and affected people, not whether the learner prefers a brand.

Evidence to interpret

Illustrative sourceRecordLimit
Performance trialFilm: 1 service; rigid container: 30 servicesMatched task; production energy not measured
Disposal information cardDifferent products need different collection/processingLocal acceptance must be verified; not a durability test

Explain and apply

Use the supplied two source records to explain one benefit, one concern and a needed follow-up for a film/container choice. Do not treat a resource label as a full safety or impact rating.

  • Connect a synthetic material to a resource and processing.
  • Use two different source records.
  • Assess benefits, concerns and missing evidence fairly.
Reasoning and marking guidance — after your attempt

The reuse record supports longer tested service for the rigid container, while the disposal record warns that acceptance depends on product and local processing. Resource origin alone does not establish total impacts. Compare the same task, include cleaning and replacement, and obtain specific production/disposal information. Describe chains and processing as a plausible property explanation rather than proof from the label plastic.

Apply the whole unit · Choose a container for repeated use

Illustrative product data: A has mass 20 g, survives 5 trips, and passes the leak test; B has mass 60 g, survives 30 trips, and passes the same test; C has mass 35 g, survives 30 trips, but leaks. The job requires 30 trips without leaks.

Your task

Choose a qualifying design, calculate the material mass needed to provide 30 trips for A and B, and discuss why this calculation alone cannot establish the environmentally best option. Propose a useful follow-up test.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

C fails the required leak criterion. A needs 6 containers totaling 120 g; B needs 1 totaling 60 g under the stated lifetimes. B uses less supplied product mass for this service. Manufacturing energy, cleaning, transport, disposal, and variation in lifetime are missing, so this is not a complete environmental ranking. Repeat leak and durability tests under the intended conditions.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Have the learner mark disqualifying criteria first, then calculate equivalent service. Separate a supported choice for this job from a claim about all environmental impacts. The application uses supplied data; physical testing is optional and should use safe containers. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation. The illustrated study “Natural resources and different plastics” is required curriculum content. Teach it before the associated application or distribute it over the assigned unit sessions; it is not an optional enrichment. Its practice/review/quiz response provides evidence of understanding. Model/data work must not be recorded as an actual physical experiment.

The key idea

Choose materials using properties and evidence, and consider benefits and environmental trade-offs.

Worked examples

Example 1

A lid must be lightweight and resist water. Cardboard absorbs 8 g of water; a plastic sample of equal area absorbs 0.2 g. Which is supported for this task?
  1. Compare a property relevant to the task: water absorption.
  2. The plastic sample absorbs less water under the same test conditions.
  3. Choose it for water resistance; investigate reuse and disposal separately.
Answer: The plastic has better evidence for water resistance; these data alone do not establish the best overall environmental choice.

Example 2 · Worked application

For 60 shopping trips, bag A lasts 3 trips and uses 15 g of material; bag B lasts 30 trips and uses 90 g. Compare material demand.
  1. Find bags needed: 60/3=20 for A and 60/30=2 for B.
  2. Total material is 20×15=300 g and 2×90=180 g.
  3. State the boundary: this counts material only, assuming the stated lifetimes and no lost bags.
Answer: B uses 180 g versus A's 300 g for the same 60-trip task.
Check the reasoning

Equivalent trips must be compared; weight of one unused bag is insufficient.

Example 3

Bag A survives 2 trips and uses 20 g of material; bag B survives 20 trips and uses 100 g. Compare material per trip, ignoring other impacts.
  1. Divide each bag's material by its number of trips: 20/2 and 100/20.
  2. Compare 10 g/trip with 5 g/trip, while noting that energy, cleaning and disposal are not included.
Answer: B uses 5 g/trip versus A's 10 g/trip in this model; the model alone does not settle total environmental impact.

Example 4 · Find and fix the mistake

Context: For 60 shopping trips, bag A lasts 3 trips and uses 15 g of material; bag B lasts 30 trips and uses 90 g. Compare material demand. A student claims: “The lighter bag must have the smaller environmental impact.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Equivalent trips must be compared; weight of one unused bag is insufficient.
  2. A lighter item may need more replacements. Energy, washing, disposal and actual reuse also affect total impact.
Answer: A lighter item may need more replacements. Energy, washing, disposal and actual reuse also affect total impact.
Check the reasoning

Equivalent trips must be compared; weight of one unused bag is insufficient.

Example 5 · Interpret the visual model

Material arrangement affects how energy crosses a containerMaterial arrangement affects how energy crosses a containerSingle wallTwo walls + air gapA gap can reduce one conduction pathway; it does not stop all transfers.Structure changes a mechanism. Test the resulting temperature and other criteria.
The two schematics distinguish a single wall from an arrangement with two walls and an air gap. A gap can reduce some conduction pathways, while radiation, air movement and contact bridges can still transfer energy. The model predicts a mechanism, not a guaranteed performance ranking without comparable measurements. Wall thickness, sealing, material amount and cost also matter.
Why is “two walls means no heat can enter” not supported? Name a remaining pathway and a relevant test.
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. Structure describes how materials are arranged; a property describes their measured response under conditions. Processing and assembly can change the arrangement. A useful design explanation connects the feature to a particular mechanism and a measurable outcome.
  3. Radiation or conduction through contacts can remain, and moving air may contribute. Compare matched temperature-versus-time records and other design criteria instead of claiming all energy transfer stops.
Answer: Radiation or conduction through contacts can remain, and moving air may contribute. Compare matched temperature-versus-time records and other design criteria instead of claiming all energy transfer stops.
Check the reasoning

Keep the model’s stated limits explicit: The two schematics distinguish a single wall from an arrangement with two walls and an air gap. A gap can reduce some conduction pathways, while radiation, air movement and contact bridges can still transfer energy. The model predicts a mechanism, not a guaranteed performance ranking without comparable measurements. Wall thickness, sealing, material amount and cost also matter.

Avoid these mistakes

Check your understanding

Bag A survives 2 trips and uses 20 g of material; bag B survives 20 trips and uses 100 g. Compare material per trip, ignoring other impacts.

Discuss the answer

B uses 5 g/trip versus A's 10 g/trip in this model; the model alone does not settle total environmental impact.

Why must two material designs be compared for an equivalent task?

Discuss the answer

Start a material choice by naming the job and constraints. A raincoat must keep water out and allow movement; a bridge cable needs strength under tension. Rank the important properties before comparing materials, because one useful property may come with an unwanted trade-off. Use measurements rather than labels such as natural or synthetic as a substitute for evidence. Record how many times a material can be reused, how much mass is needed and how it behaves in the intended environment. Production methods can change the properties of materials made from similar resources.

Return to the phenomenon

Illustrative container trials give material A 0 leaks in 3 tests but only 2 successful reuse cycles; B 1 leak in 3 tests and 20 reuse cycles. Costs and manufacturing impacts are unknown. Choose a provisional material for one stated use. Compare water resistance and reuse, and specify a missing measurement instead of declaring a universal winner. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

For a leak-sensitive one-time model test, A’s observed leak record is favorable. For repeated use, B’s larger tested lifetime matters, but one observed leak requires improvement or further testing. Cost and full environmental impacts remain unknown. A recommendation must identify the intended criterion and hard constraints rather than combine unlike measures without a rule.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

Illustrative container trials give material A 0 leaks in 3 tests but only 2 successful reuse cycles; B 1 leak in 3 tests and 20 reuse cycles. Costs and manufacturing impacts are unknown. Choose a provisional material for one stated use. Compare water resistance and reuse, and specify a missing measurement instead of declaring a universal winner. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

For a leak-sensitive one-time model test, A’s observed leak record is favorable. For repeated use, B’s larger tested lifetime matters, but one observed leak requires improvement or further testing. Cost and full environmental impacts remain unknown. A recommendation must identify the intended criterion and hard constraints rather than combine unlike measures without a rule.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

Which stage is measured by a one-minute leak test? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

A life-cycle model asks about resources, processing, use and what happens afterward. Arrows represent stages to investigate rather than equal impact amounts. A material can perform well in a leak test without that test establishing its entire environmental impact.

Response guidance — discuss after your attempt

One use-performance feature. It does not measure extraction, manufacturing energy, lifetime reuse or disposal impacts. A life-cycle model asks about resources, processing, use and what happens afterward. Arrows represent stages to investigate rather than equal impact amounts. A material can perform well in a leak test without that test establishing its entire environmental impact.

Words to know

synthetic material
A material made through human-directed processing, often involving chemical reactions.
constraint
A limit that a design must satisfy.
trade-off
A benefit gained at the cost of another desirable feature.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

In the real world

Exit check

Which stage is measured by a one-minute leak test? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

One use-performance feature. It does not measure extraction, manufacturing energy, lifetime reuse or disposal impacts. A life-cycle model asks about resources, processing, use and what happens afterward. Arrows represent stages to investigate rather than equal impact amounts. A material can perform well in a leak test without that test establishing its entire environmental impact.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Problem 1

A particle has eight protons and ten electrons. Is it oxygen, and is it neutral?
Answer and explanation

It is oxygen because it has eight protons. It has two excess negative charges, so it is an ion with charge −2, not a neutral atom.

It is oxygen because it has eight protons. It has two excess negative charges, so it is an ion with charge −2, not a neutral atom.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 2

If only electrons rise to 10, what entries change?
Answer and explanation

The charge becomes −2 while atomic number 8, mass number 16 and oxygen identity remain unchanged.

The charge becomes −2 while atomic number 8, mass number 16 and oxygen identity remain unchanged.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 3

Draw two water molecules and a larger repeating salt patch. Compare total atom counts with a formula ratio, and explain why a two-ball salt molecule is an incomplete crystal model.
Hints

Use the illustrated study titled Molecules and extended structures. Keep the observations, model and conditions separate.

Answer and explanation

Two water molecules contain four H and two O atoms. A salt patch represents part of an extended arrangement; its bulk Na:Cl ratio is one-to-one rather than a claim that the crystal is a collection of separate NaCl molecules. Retain element/ion labels and note that colors, bonding lines and distances are conventions.

Two water molecules contain four H and two O atoms. A salt patch represents part of an extended arrangement; its bulk Na:Cl ratio is one-to-one rather than a claim that the crystal is a collection of separate NaCl molecules. Retain element/ion labels and note that colors, bonding lines and distances are conventions.

Response criteria

  • Distinguish molecule from extended arrangement.
  • Count water atoms correctly.
  • Explain formula ratio and a model limit.

Problem 4

Visual-model chapter review: An atom has 12 protons, 13 neutrons and 10 electrons. State atomic number, mass number and net charge, and explain whether losing electrons changed its element.
Answer and explanation

Atomic number 12; mass number 25; charge +2 in elementary-charge units. Electron loss changes charge, while the 12 protons still determine the element.

Read proton count for atomic number.

Add 12+13 for mass number; compare 12 positive with 10 negative charges.

Atomic number 12; mass number 25; charge +2 in elementary-charge units. Electron loss changes charge, while the 12 protons still determine the element.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

Problem 5

Why is reversibility alone an unreliable rule?
Answer and explanation

Some physical changes are hard to undo, such as breaking glass, and some chemical reactions can be reversed under appropriate conditions. Chemical identity is the deciding idea.

Some physical changes are hard to undo, such as breaking glass, and some chemical reactions can be reversed under appropriate conditions. Chemical identity is the deciding idea.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 6

Which case changes substance identity?
Answer and explanation

Rusting forms different substances; melting retains water identity. Appearance alone cannot establish the classification.

Rusting forms different substances; melting retains water identity. Appearance alone cannot establish the classification.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 7

Plan and, if safe materials are available, conduct the sand/salt comparison. Use the supplied recovery record to argue whether it is consistent with a physical mixture, and explain why a mass shortfall is not automatically a reaction.
Hints

Use the illustrated study titled Mixtures and physical separation. Keep the observations, model and conditions separate.

Answer and explanation

The separate-component tests and recovery of sand and salt are consistent with a physical combination. The illustrative recovered masses are 4.8+2.9=7.7 g versus 8.0 g originally added, leaving 0.3 g unaccounted for in that collection. Transfer residues, remaining dissolved salt or reading uncertainty can explain a shortfall. Better rinsing, complete collection and repeated matched tests can improve the account; the data do not establish a new compound.

The separate-component tests and recovery of sand and salt are consistent with a physical combination. The illustrative recovered masses are 4.8+2.9=7.7 g versus 8.0 g originally added, leaving 0.3 g unaccounted for in that collection. Transfer residues, remaining dissolved salt or reading uncertainty can explain a shortfall. Better rinsing, complete collection and repeated matched tests can improve the account; the data do not establish a new compound.

Response criteria

  • Specify components and a property-based method.
  • Use recovered identity and mass evidence.
  • Explain a limitation or controlled improvement.

Problem 8

Visual-model chapter review: Two colorless samples have the same density but melt at different temperatures under comparable conditions. Does matching density establish identical substance identity? Explain the role of a second property.
Answer and explanation

No. Their distinct melting behavior provides another characteristic-property comparison. One matching density is not unique identification.

Compare multiple characteristic properties under stated conditions.

Separate an observed property from an inference of identity.

No. Their distinct melting behavior provides another characteristic-property comparison. One matching density is not unique identification.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

Problem 9

What error comes from using 42 mL as the object volume?
Answer and explanation

It includes the original water volume. The object displaced only 12 mL; using 42 mL would underestimate its density.

It includes the original water volume. The object displaced only 12 mL; using 42 mL would underestimate its density.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 10

Why does B not have twice A’s density?
Answer and explanation

Its mass and volume both double, so 48/16 equals 24/8, or 3 g/cm³.

Its mass and volume both double, so 48/16 equals 24/8, or 3 g/cm³.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 11

An illustrative unknown has mass 54 g and displacement 20 cm³. References A/C are both 2.7 g/cm³ and B is 7.9. Argue which candidates remain and plan one additional property comparison.
Hints

Use the illustrated study titled Density as identification evidence. Keep the observations, model and conditions separate.

Answer and explanation

Density is 54/20=2.7 g/cm³. A and C remain consistent while B is inconsistent under matched conditions and adequate measurement precision. Density alone cannot distinguish A from C; choose a safe characteristic-property comparison with supplied reference data, such as solubility for approved samples. Name uncertainty and whether the object is homogeneous.

Density is 54/20=2.7 g/cm³. A and C remain consistent while B is inconsistent under matched conditions and adequate measurement precision. Density alone cannot distinguish A from C; choose a safe characteristic-property comparison with supplied reference data, such as solubility for approved samples. Name uncertainty and whether the object is homogeneous.

Response criteria

  • Calculate with correct units.
  • Distinguish support from unique identification.
  • Choose relevant further evidence and controls.

Problem 12

Visual-model chapter review: A completely submerged object raises a cylinder reading from 35 to 47 mL and has mass 30 g. Calculate density, state the volume assumptions and distinguish this from claiming an exact substance identity.
Answer and explanation

Volume 12 cm³; density 30/12 = 2.5 g/cm³. Assume no trapped bubbles, spill or incomplete submersion. Density alone does not uniquely identify the substance.

Use the change 47−35, not the final reading.

Divide the independently measured mass by that volume.

Volume 12 cm³; density 30/12 = 2.5 g/cm³. Assume no trapped bubbles, spill or incomplete submersion. Density alone does not uniquely identify the substance.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

Problem 13

Does being in the same group make two elements identical?
Answer and explanation

No. It suggests related chemical behavior for many main-group elements, but the elements retain different proton counts and can differ strongly in other properties.

No. It suggests related chemical behavior for many main-group elements, but the elements retain different proton counts and can differ strongly in other properties.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 14

What fixes the order shown?
Answer and explanation

Atomic number, the proton count, orders Na 11, Mg 12 and Al 13. The display omits most elements and does not claim identical reactivity.

Atomic number, the proton count, orders Na 11, Mg 12 and Al 13. The display omits most elements and does not claim identical reactivity.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 15

Visual-model chapter review: A learner reads atomic number 17 and average atomic mass about 35.45 from a chlorine card and reports 18.45 neutrons in one atom. Correct the interpretation for a specified chlorine-37 atom.
Answer and explanation

Chlorine-37 has 17 protons and 37−17 = 20 neutrons. The decimal 35.45 is an isotope-average mass, not one atom’s particle count.

Use the specified isotope mass number, not the decimal average.

Subtract atomic number from mass number.

Chlorine-37 has 17 protons and 37−17 = 20 neutrons. The decimal 35.45 is an isotope-average mass, not one atom’s particle count.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

Problem 16

Why is natural versus synthetic insufficient for choosing a container?
Answer and explanation

Those labels do not supply evidence of leakage, durability, safety in intended use, or disposal impacts. The actual material properties and use conditions matter.

Those labels do not supply evidence of leakage, durability, safety in intended use, or disposal impacts. The actual material properties and use conditions matter.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 17

Which stage is measured by a one-minute leak test?
Answer and explanation

One use-performance feature. It does not measure extraction, manufacturing energy, lifetime reuse or disposal impacts.

One use-performance feature. It does not measure extraction, manufacturing energy, lifetime reuse or disposal impacts.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 18

Use the supplied two source records to explain one benefit, one concern and a needed follow-up for a film/container choice. Do not treat a resource label as a full safety or impact rating.
Hints

Use the illustrated study titled Natural resources and different plastics. Keep the observations, model and conditions separate.

Answer and explanation

The reuse record supports longer tested service for the rigid container, while the disposal record warns that acceptance depends on product and local processing. Resource origin alone does not establish total impacts. Compare the same task, include cleaning and replacement, and obtain specific production/disposal information. Describe chains and processing as a plausible property explanation rather than proof from the label plastic.

The reuse record supports longer tested service for the rigid container, while the disposal record warns that acceptance depends on product and local processing. Resource origin alone does not establish total impacts. Compare the same task, include cleaning and replacement, and obtain specific production/disposal information. Describe chains and processing as a plausible property explanation rather than proof from the label plastic.

Response criteria

  • Connect a synthetic material to a resource and processing.
  • Use two different source records.
  • Assess benefits, concerns and missing evidence fairly.

Problem 19

Visual-model chapter review: Cup A can be used 20 times and needs 8 material-units per cup; B is single-use and needs 2 units each time. Compare raw material for 20 uses, then name two omitted impacts before declaring an environmental winner.
Answer and explanation

A uses 8 initial material-units; B uses 40 for 20 cups. Cleaning energy/water, production, transport, disposal and actual lifetime are omitted, so initial material alone is not a complete impact ranking.

Compare the same amount of service.

Keep the measured raw-material comparison separate from the full life cycle.

A uses 8 initial material-units; B uses 40 for 20 cups. Cleaning energy/water, production, transport, disposal and actual lifetime are omitted, so initial material alone is not a complete impact ranking.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

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