Kinetic & Potential Energy · Grade 8 Science

Chapter: Energy & Heat Transfer

Kinetic & Potential Energy

Learning goals

Readings for this unit

Before this unit

Square a number and distinguish speed from height.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in kinetic & potential energy?

Illustrative evidence case. Illustrative kinetic-energy records for a 2 kg cart at speeds 1, 2 and 3 m/s are 1, 4 and 9 J. A same-speed 4 kg cart has twice the corresponding energy.

Speed and kinetic energy are not linearSpeed and kinetic energy are not linearSpeed (m/s)Kinetic energy (J)000.752.51.552.257.5310Fixed mass: 2 kgIllustrative model • use the labels and stated assumptions
The plotted model uses a fixed 2 kg mass and kinetic energy ½mv². Doubling speed from 1 to 2 m/s quadruples energy from 1 to 4 J. Connecting measured model points does not make the curve linear; a separate fixed-speed comparison is needed to isolate the mass effect.

Notice and wonder

At 4 m/s, what does this model predict? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Describe and graph the separate speed and mass relationships. Explain why equal changes in speed do not give equal changes in kinetic energy. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

energy
The ability to do work or cause change, measured in joules (J).
kinetic energy
Energy of motion, calculated as KE = ½mv² (half times mass times speed squared).
potential energy
Stored energy due to an object's position, such as height above the ground.
joule (J)
The standard unit of energy.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

Energy is the ability to do work or cause change, and everything that happens — a ball flying, a light glowing, a muscle flexing — involves energy in some form. It's measured in joules (J). One of the most familiar forms is kinetic energy, the energy of motion: anything that's moving has it. Its formula is KE = ½mv², where m is mass and v is speed. Notice that the speed is squared, which has a dramatic consequence — doubling an object's speed doesn't just double its kinetic energy, it quadruples it.

That squared speed is a big reason car crashes grow so much more dangerous as speed climbs. A car going twice as fast doesn't carry twice the energy into a collision — it carries four times as much, and a car going three times as fast carries nine times as much. It's also why a small, light object like a hailstone or a fast pitch can do real damage despite its tiny mass: for kinetic energy, high speed counts for even more than heavy mass.

Mass and speed affect kinetic energy differentlyMass and speed affect kinetic energy differentlyKinetic energy (J)04801234Mass (kg)Kinetic energy (J)081601234Speed (m/s)Speed fixed: 2 m/sMass fixed: 2 kgDouble mass → double KE. Double speed → four times KE, under these conditions.
The left model holds speed at 2 m/s, so kinetic energy is 2 J per kg and rises linearly with mass. The right holds mass at 2 kg, so kinetic energy equals speed squared in the stated SI units. These are model predictions rather than collected collision data. A speed change and a mass change must be compared separately, with consistent units and the same frame of reference.

Potential energy is stored energy, waiting to be released. The kind you'll work with most here is gravitational potential energy — the energy an object has because of its height. Its formula is PE = mgh, where m is mass, g is gravity's acceleration (9.8 m/s² on Earth), and h is the height above some reference point like the ground. Lift an object higher, or choose a heavier object, and you store more potential energy in it, ready to convert the moment it's released.

Calculate the change in the object–Earth arrangementCalculate the change in the object–Earth arrangementHeight gain: 4 mMass 2 kg; g ≈ 10 N/kg; initial height 3 m, final 7 mGPE initial: 60 J. GPE final: 140 J. Change: +80 J.Changing the zero-height reference changes totals, not the height difference.
For the supplied 2 kg object with g rounded to 10 N/kg, gravitational energy relative to the chosen zero height is 60 J at 3 m and 140 J at 7 m. The change is 80 J for a 4 m rise. The picture’s boxes are schematic and do not set the numerical height scale; use the labels. The relevant gravitational store belongs to the interacting object–Earth system.

The real magic is that these two forms constantly trade back and forth. Picture a roller coaster car creeping over the very top of its first hill: it's barely moving, so its kinetic energy is nearly zero, but it's way up high, so its potential energy is at its maximum. As it plunges down, that stored potential energy pours into kinetic energy — and at the bottom of the drop the car is racing along at its fastest, with maximum kinetic energy and almost no potential energy left. Then it climbs the next hill and trades kinetic back into potential all over again.

This constant give-and-take between motion and position shows up everywhere: a diving board flinging a swimmer upward, a drawn bowstring launching an arrow, a pendulum swinging back and forth. Understanding it lets engineers calculate how fast a falling object will be moving, how much energy a car's crumple zone must absorb to protect passengers in a crash, and how tall to build a coaster's first hill so the ride carries enough energy to finish the track.

Kinetic energy depends on mass and the square of speed: KE=½mv². Doubling mass at fixed speed doubles kinetic energy, while doubling speed at fixed mass makes kinetic energy four times as large. Write the square before multiplying.

Gravitational potential energy near Earth depends on mass, field strength and height above a chosen reference: GPE=mgh. Changing the zero-height reference changes the reported value but not the energy difference between two positions.

An object can have both kinetic and potential energy. A moving ball above the floor has both, while deformation can store elastic potential energy. Name the relevant system and reference, and remember that friction can transfer mechanical energy into thermal energy.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Choose the system and reference level

Kinetic energy describes energy associated with motion. Gravitational potential energy belongs to an interacting object-Earth system and depends on a chosen reference height. A reference level can be arbitrary for comparing height changes; state it consistently. Energy is measured in joules, not newtons or kilograms.

An energy value needs its system and referenceAn energy value needs its system and referenceObject + EarthGPE reference neededMoving objectKE depends on frameEnergy comparisons require a receiving system, reference level and conditions.A height zero and a motion reference are choices used to organize the account.
Gravitational energy is associated with the interacting object–Earth arrangement and is quoted relative to a chosen zero height. Kinetic energy describes motion relative to a chosen reference frame. The boxes organize which system/reference a number belongs to; they do not imply that energy is a material stored inside each box or that absolute values are meaningful without those choices.

Read the visual model

Reference means the agreed comparison used to quote a quantity. State it so two people calculate the same question. For changes, compare the same system and reference in both states rather than mixing unrelated totals.

Why can shifting the zero-height reference change a quoted GPE without changing a predicted energy gain during the same rise?

Visual reasoning — after your attempt

It changes both absolute values by the same reference offset, leaving the height difference and therefore the physical energy change unchanged.

A book on a shelf has gravitational potential energy relative to the floor. Moving the zero reference to the tabletop changes the reported reference value but not the energy difference between two fixed shelf heights. Use changes when explaining lifting.

Pause and explain

Why must a gravitational reference height be stated?

Check your reasoning after answering

The reported potential-energy value depends on the chosen zero. The energy change between two heights remains meaningful when the reference is used consistently.

Part 2 · Compare kinetic energy using the square of speed

For an ordinary nonrelativistic moving object, KE=½mv². Mass enters directly while speed is squared. Doubling mass at the same speed doubles KE; doubling speed at the same mass quadruples it. Use meters per second and kilograms for an answer in joules.

Mass and speed affect kinetic energy differentlyMass and speed affect kinetic energy differentlyKinetic energy (J)04801234Mass (kg)Kinetic energy (J)081601234Speed (m/s)Speed fixed: 2 m/sMass fixed: 2 kgDouble mass → double KE. Double speed → four times KE, under these conditions.
The left model holds speed at 2 m/s, so kinetic energy is 2 J per kg and rises linearly with mass. The right holds mass at 2 kg, so kinetic energy equals speed squared in the stated SI units. These are model predictions rather than collected collision data. A speed change and a mass change must be compared separately, with consistent units and the same frame of reference.

Read the visual model

Squared means multiplied by itself. The curve rises faster as speed increases. Read which variable is fixed before applying a pattern from one graph to a question about the other.

For the right-hand model, compare KE at 2 and 4 m/s. Why does a straight-line doubling prediction fail?

Visual reasoning — after your attempt

KE is 4 J at 2 m/s and 16 J at 4 m/s. Squaring the speed gives a fourfold increase, not a twofold increase.

A 2 kg cart at 3 m/s has KE=½×2×9=9 J. At 6 m/s it has 36 J, not 18 J. Write the squared speed as an intermediate step to avoid a common calculation error.

Speed and kinetic energy are not linearSpeed and kinetic energy are not linearSpeed (m/s)Kinetic energy (J)000.752.51.552.257.5310Fixed mass: 2 kgIllustrative model • use the labels and stated assumptions
The plotted model uses a fixed 2 kg mass and kinetic energy ½mv². Doubling speed from 1 to 2 m/s quadruples energy from 1 to 4 J. Connecting measured model points does not make the curve linear; a separate fixed-speed comparison is needed to isolate the mass effect.

Pause and explain

Why does doubling speed give four times the kinetic energy?

Check your reasoning after answering

The formula contains speed squared. Replacing v by 2v makes the squared term 4v² while mass is unchanged.

Part 3 · Calculate gravitational energy changes

Near Earth with approximately constant g, change in gravitational potential energy=mg×height change. This model uses vertical height change, not the length of a sloping path. A heavy object or a larger rise produces a larger change; the same height change gives the same ideal result regardless of route.

Calculate the change in the object–Earth arrangementCalculate the change in the object–Earth arrangementHeight gain: 4 mMass 2 kg; g ≈ 10 N/kg; initial height 3 m, final 7 mGPE initial: 60 J. GPE final: 140 J. Change: +80 J.Changing the zero-height reference changes totals, not the height difference.
For the supplied 2 kg object with g rounded to 10 N/kg, gravitational energy relative to the chosen zero height is 60 J at 3 m and 140 J at 7 m. The change is 80 J for a 4 m rise. The picture’s boxes are schematic and do not set the numerical height scale; use the labels. The relevant gravitational store belongs to the interacting object–Earth system.

Read the visual model

Choose the reference before quoting an absolute gravitational-energy number. A comparison between two states depends on their height difference. Travel along a longer winding path does not automatically change that final height difference.

If a new zero-height reference is chosen at 3 m, what are initial and final gravitational energies and their difference?

Visual reasoning — after your attempt

Initial is 0 J, final is 80 J and the difference remains +80 J. The constant reference shift does not change the physical height increase.

With mass 2 kg, g=10 N/kg, and a rise of 0.5 m, the increase is 10 J. Traveling along a 2 m ramp to that height still gives 10 J of gravitational increase, though real input work can be larger because of resistance.

Pause and explain

Why use rise rather than ramp length for gravitational potential energy?

Check your reasoning after answering

Gravity depends on the vertical change in this model. A longer route to the same final height does not increase the gravitational energy difference.

Part 4 · Trace conversion without assuming perfection

During a fall or descent, gravitational potential energy can decrease while kinetic energy increases. Air resistance, friction, sound, and deformation can transfer energy into other stores. A prediction that all gravitational energy becomes kinetic energy needs explicit assumptions about these effects.

Kinetic and potential energy during a throwTwo stores, traded back and forththrowtopcatchkineticgravitational potentialIgnoring air resistance, the two bars always add to the same total
The bars are the useful part: at every point the two add to the same total, so the trade is visible rather than asserted. Air resistance removes a little from that total at each stage, which is why a real ball returns slightly slower.

Read the visual model

What does a smaller kinetic-energy gain than gravitational loss suggest?

Visual reasoning — after your attempt

Other energy transfers or stores matter. Account for them, and check measurement uncertainty, before claiming energy has disappeared.

If a cart-Earth system loses 20 J of gravitational potential energy and gains 15 J of kinetic energy, account for the remaining 5 J. It can be transferred to thermal stores and other effects rather than being destroyed.

OpenSciEd sketch of a wire coil facing a separate magnet across a gap; the diagram is a template for adding the two interaction-force arrows.
In the original OpenSciEd interaction template, changing a magnet/coil arrangement can change the system’s stored energy. A drawing alone does not give a numerical potential energy. Explain the work needed to change a specified attracting or repelling arrangement and the other stores that could change when released. Coil and magnet before force arrows are added · OpenSciEd · 8.3 Forces at a Distance, Lesson 2, source, CC BY 4.0. Figure excerpt rendered from the PDF and resized for the web.

Pause and explain

What does a smaller kinetic-energy gain than gravitational loss suggest?

Check your reasoning after answering

Other energy transfers or stores matter. Account for them, and check measurement uncertainty, before claiming energy has disappeared.

Apply the whole unit · Compare two cart descents

Illustrative case: two 2 kg carts descend through 1 m near Earth; use g=10 N/kg and assume both start at rest. At the bottom A moves at 4 m/s and B at 3 m/s.

Your task

Calculate gravitational energy decrease and final kinetic energy for each cart, identify the remaining energy account, and explain why these results alone do not identify the exact resistance mechanism.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

Each loses 20 J of gravitational potential energy. A has KE=16 J and B=9 J. The remaining amounts are 4 J and 11 J in other stores/transfers or measurement differences. The data suggest different non-kinetic outcomes but do not uniquely identify friction, air drag, or deformation. Check routes, wheels, and measurement uncertainty.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Use an energy bar chart alongside calculations. Rehearse squared speed and consistent units. Ask the learner to explain the system and reference before treating potential energy as belonging to an isolated object. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation.

The key idea

Kinetic energy (KE = ½mv²) is energy of motion; potential energy (PE = mgh) is stored energy due to position — height and speed constantly trade off.

Kinetic Energy

KE = ½mv²

m is mass in kg; v is speed in m/s; KE comes out in joules (J).

Gravitational Potential Energy

PE = mgh

m is mass in kg; g = 9.8 m/s² on Earth; h is height in meters; PE comes out in joules (J).

Worked examples

Example 1

Find the kinetic energy of a 2 kg ball moving at 3 m/s.
  1. Use KE = ½mv².
  2. KE = ½ × 2 × 3².
  3. = ½ × 2 × 9 = 9.
Answer: 9 J

Example 2 · Worked application

Compare a 2 kg cart at 3 m/s with the same cart at 6 m/s using KE=½mv².
  1. First KE=½×2×3²=9 J.
  2. Second KE=½×2×6²=36 J.
  3. Doubling speed makes kinetic energy four times as large at fixed mass.
Answer: 9 J and 36 J; a fourfold increase.
Check the reasoning

Square the speed before multiplying.

Example 3

Find the gravitational potential energy of a 5 kg box lifted 4 m above the ground. (Use g = 9.8 m/s².)
  1. Use PE = mgh.
  2. PE = 5 × 9.8 × 4.
  3. = 196.
Answer: 196 J

Example 4

Using g=10 N/kg, find the potential-energy gain of a 2 kg book raised 1.5 m.
  1. Use change in GPE=mgh.
  2. Substitute 2×10×1.5=30 J.
Answer: The book–Earth system gains 30 J of gravitational potential energy.

Example 5 · Find and fix the mistake

Context: Compare a 2 kg cart at 3 m/s with the same cart at 6 m/s using KE=½mv². A student claims: “Doubling speed only doubles kinetic energy.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Square the speed before multiplying.
  2. Kinetic energy depends on v². At unchanged mass, twice the speed gives four times the energy.
Answer: Kinetic energy depends on v². At unchanged mass, twice the speed gives four times the energy.
Check the reasoning

Square the speed before multiplying.

Example 6 · Interpret the visual model

An energy value needs its system and referenceAn energy value needs its system and referenceObject + EarthGPE reference neededMoving objectKE depends on frameEnergy comparisons require a receiving system, reference level and conditions.A height zero and a motion reference are choices used to organize the account.
Gravitational energy is associated with the interacting object–Earth arrangement and is quoted relative to a chosen zero height. Kinetic energy describes motion relative to a chosen reference frame. The boxes organize which system/reference a number belongs to; they do not imply that energy is a material stored inside each box or that absolute values are meaningful without those choices.
Why can shifting the zero-height reference change a quoted GPE without changing a predicted energy gain during the same rise?
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. Reference means the agreed comparison used to quote a quantity. State it so two people calculate the same question. For changes, compare the same system and reference in both states rather than mixing unrelated totals.
  3. It changes both absolute values by the same reference offset, leaving the height difference and therefore the physical energy change unchanged.
Answer: It changes both absolute values by the same reference offset, leaving the height difference and therefore the physical energy change unchanged.
Check the reasoning

Keep the model’s stated limits explicit: Gravitational energy is associated with the interacting object–Earth arrangement and is quoted relative to a chosen zero height. Kinetic energy describes motion relative to a chosen reference frame. The boxes organize which system/reference a number belongs to; they do not imply that energy is a material stored inside each box or that absolute values are meaningful without those choices.

Avoid these mistakes

Check your understanding

Using g=10 N/kg, find the potential-energy gain of a 2 kg book raised 1.5 m.

Discuss the answer

The book–Earth system gains 30 J of gravitational potential energy.

Why can two correct potential-energy values differ if they use different reference heights?

Discuss the answer

Kinetic energy depends on mass and the square of speed: KE=½mv². Doubling mass at fixed speed doubles kinetic energy, while doubling speed at fixed mass makes kinetic energy four times as large. Write the square before multiplying. Gravitational potential energy near Earth depends on mass, field strength and height above a chosen reference: GPE=mgh. Changing the zero-height reference changes the reported value but not the energy difference between two positions.

Return to the phenomenon

Illustrative kinetic-energy records for a 2 kg cart at speeds 1, 2 and 3 m/s are 1, 4 and 9 J. A same-speed 4 kg cart has twice the corresponding energy. Describe and graph the separate speed and mass relationships. Explain why equal changes in speed do not give equal changes in kinetic energy. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

For fixed mass, kinetic energy grows with speed squared: the record 1,4,9 is nonlinear. For fixed speed, doubling mass doubles kinetic energy. Plot separately and label units; do not change mass and speed together and call that an isolated test. Equal speed increments add different energy amounts because the square changes differently.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

Illustrative kinetic-energy records for a 2 kg cart at speeds 1, 2 and 3 m/s are 1, 4 and 9 J. A same-speed 4 kg cart has twice the corresponding energy. Describe and graph the separate speed and mass relationships. Explain why equal changes in speed do not give equal changes in kinetic energy. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

For fixed mass, kinetic energy grows with speed squared: the record 1,4,9 is nonlinear. For fixed speed, doubling mass doubles kinetic energy. Plot separately and label units; do not change mass and speed together and call that an isolated test. Equal speed increments add different energy amounts because the square changes differently.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

At 4 m/s, what does this model predict? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

The plotted model uses a fixed 2 kg mass and kinetic energy ½mv². Doubling speed from 1 to 2 m/s quadruples energy from 1 to 4 J. Connecting measured model points does not make the curve linear; a separate fixed-speed comparison is needed to isolate the mass effect.

Response guidance — discuss after your attempt

16 J for the same 2 kg mass. The prediction uses the squared-speed model rather than extending the last straight segment indefinitely. The plotted model uses a fixed 2 kg mass and kinetic energy ½mv². Doubling speed from 1 to 2 m/s quadruples energy from 1 to 4 J. Connecting measured model points does not make the curve linear; a separate fixed-speed comparison is needed to isolate the mass effect.

Words to know

energy
The ability to do work or cause change, measured in joules (J).
kinetic energy
Energy of motion, calculated as KE = ½mv² (half times mass times speed squared).
potential energy
Stored energy due to an object's position, such as height above the ground.
joule (J)
The standard unit of energy.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

Émilie du Châtelet and the squared-speed clue

In the early 1700s, scientists were arguing about how to measure a moving object's 'force of motion' — some said it should depend on speed, others on speed squared. French natural philosopher Émilie du Châtelet helped settle the debate by analyzing experiments where brass balls were dropped into soft clay from different heights: the depth of the dent turned out to be proportional to the square of the impact speed, not the speed itself. Her work helped confirm the relationship we now write as KE = ½mv², and she also produced the standard French translation of Newton's Principia, still used by scholars today.

Why speed limits matter so much: energy scales with the square

Because kinetic energy depends on v², doubling an object's speed doesn't just double its kinetic energy — it quadruples it. A car traveling at 60 mph doesn't have twice the crash energy of one traveling at 30 mph; it has four times the energy that needs to be absorbed in a collision. This single mathematical fact is a major reason why speed limits drop sharply near schools and why even a small increase in driving speed makes crashes dramatically more dangerous, not just a little worse.

Potential energy has more forms than just height

Gravitational potential energy (PE = mgh) is just one flavor of stored energy. Stretch a rubber band or compress a spring and you store elastic potential energy, ready to snap back the moment you let go. The bonds holding atoms together in food, gasoline, and batteries store chemical potential energy, released when those bonds break during a reaction. Even the nucleus of an atom stores enormous potential energy in the forces holding protons and neutrons together — the same reservoir tapped by nuclear power plants and the Sun.

Turning potential energy into useful work: pile drivers

Construction crews use a machine called a pile driver that lifts a massive weight high into the air and then drops it onto a support beam (a 'pile'), pounding it deep into the ground to anchor a building's foundation. It's kinetic and potential energy put to direct practical use: the higher the weight is raised, the more gravitational potential energy it stores, and the more kinetic energy — and driving force — it delivers the instant it slams down. The same basic physics that describes a roller coaster's first hill is quite literally holding up skyscrapers.

In the real world

Engineers calculate kinetic energy to design safer car crumple zones, and potential energy to design thrilling but safe roller coasters.

Exit check

At 4 m/s, what does this model predict? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

16 J for the same 2 kg mass. The prediction uses the squared-speed model rather than extending the last straight segment indefinitely. The plotted model uses a fixed 2 kg mass and kinetic energy ½mv². Doubling speed from 1 to 2 m/s quadruples energy from 1 to 4 J. Connecting measured model points does not make the curve linear; a separate fixed-speed comparison is needed to isolate the mass effect.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

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