Conservation of Mass — Practice · Grade 8 Science
Chapter: ChemistryWhat this practice covers
By the end of Conservation of Mass you should be able to:
- I can state the law of conservation of mass.
- I can use conservation of mass to calculate an unknown mass of a reactant or product.
10 questions, numeric, multiple choice and written answer, each with a worked explanation.
Vocabulary used: law of conservation of mass, closed system, model, evidence, system boundary, assumption.
Problem 1
Answer and explanation
44 g
By conservation of mass: 12 g + 32 g = 44 g of carbon dioxide.
Problem 2
Answer and explanation
35 g
60 g (products) − 25 g (reactant A) = 35 g of reactant B.
Problem 3
- mass can be created but not destroyed
- the total mass of the reactants equals the total mass of the products
- products always weigh less than the reactants
- atoms are destroyed and new ones form
Answer and explanation
the total mass of the reactants equals the total mass of the products
Conservation of mass means reactant mass and product mass are always equal in a closed system.
Problem 4
Answer and explanation
Atoms are only rearranged into new combinations (different molecules); no atoms are created or destroyed, so the total mass before and after the reaction stays the same.
Problem 5
Answer and explanation
3.3 g
Oxygen used = 8.3 g (product) − 5.0 g (magnesium) = 3.3 g.
Problem 6
Answer and explanation
3 g of gas; remaining material plus gas still totals 80 g.
Use initial mass=remaining mass+escaped mass.
Subtract 80−77=3 g.
Response criteria
- Use the stated conditions.
- Show the evidence or calculation.
- Explain the conclusion and any stated limitation.
Problem 7
Hints
Count all products, including invisible gas.
Answer and explanation
92−87=5 g; remaining material plus escaped gas totals 92 g.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Check balance uncertainty and calibration, then leaks or spills and whether the same container parts were included. A measurement mismatch requires investigation.
Problem 9
Answer and explanation
The product molecules have a different composition/combination from the reactant molecules, while each element’s atom count stays four H and two O.
A reactant is a starting substance and a product is a resulting substance. Different combinations can give different characteristic properties. The drawing is an explanation for an already specified reaction, not proof that every visible bubble is a new substance.
The product molecules have a different composition/combination from the reactant molecules, while each element’s atom count stays four H and two O.
Response criteria
- Use the named labels, directions or supplied quantities accurately.
- Connect the visual evidence to the scientific mechanism or calculation.
- State the relevant model conditions or limitation.
Problem 10
Answer and explanation
5 g of incoming gas, so 9+5 = 14 g. The increase concerns matter crossing the measured boundary rather than matter being created.
Subtract the initial solid mass from product mass.
Identify the initially omitted matter source.
5 g of incoming gas, so 9+5 = 14 g. The increase concerns matter crossing the measured boundary rather than matter being created.
Response criteria
- Use the named labels, directions or supplied quantities accurately.
- Connect the visual evidence to the scientific mechanism or calculation.
- State the relevant model conditions or limitation.