Momentum & Collisions — Practice · Grade 12 Science
Chapter: Work, Energy & MomentumWhat this practice covers
By the end of Momentum & Collisions you should be able to:
- I can calculate momentum with p = mv and apply the impulse-momentum relationship J = FΔt = Δp.
- I can use conservation of momentum to analyze elastic and inelastic collisions.
9 questions, numeric, multiple choice and written answer, each with a worked explanation.
Vocabulary used: momentum, impulse, conservation of momentum, elastic collision, inelastic collision.
Problem 1
Answer and explanation
2 kg·m/s
p = mv = 0.50 × 4.0 = 2.0 kg·m/s.
Problem 2
Answer and explanation
10 kg·m/s
Impulse equals the change in momentum: J = Δp = m(v_f − v_i) = 0.50 × (20 − 0) = 10 kg·m/s.
Problem 3
Answer and explanation
3 m/s
Conservation of momentum: 3.0 × 4.0 + 1.0 × 0 = (3.0 + 1.0)v′, so 12 = 4.0v′ and v′ = 3.0 m/s.
Problem 4
- Momentum only
- Kinetic energy only
- Both momentum and kinetic energy
- Neither momentum nor kinetic energy
Answer and explanation
Momentum only
Momentum is conserved in every collision with no external force. In an inelastic collision, some kinetic energy is converted to heat, sound, and deformation, so only momentum is conserved.
Problem 5
Answer and explanation
0.6 m/s
Total momentum starts at 0, so 50 × v + 2.0 × 15 = 0, giving 50v = −30 and v = −0.6 m/s. The astronaut recoils at 0.6 m/s in the opposite direction.
Problem 6
Hints
Initial KE=9 J and final KE=6 J; sticking need not conserve kinetic energy.
Answer and explanation
Initial momentum=4; final mass=4; velocity=1 m/s.
Problem 7
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Momentum is a vector; opposite directions contribute opposite signed components.
Problem 8
Answer and explanation
vf=ptotal/(mA+mB)=2/3≈+0.667 m/s.
An elastic collision conserves total kinetic energy as well as momentum in the isolated system. An inelastic collision has a kinetic-energy decrease into deformation, thermal changes or other forms; perfectly inelastic means the bodies remain together after impact. “Perfectly” does not mean all kinetic energy disappears. Use momentum first for a shared final velocity, then calculate kinetic energy before and after to determine the change.
vf=ptotal/(mA+mB)=2/3≈+0.667 m/s.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 9
Answer and explanation
Initial momentum=12 kg·m/s, so vf=3 m/s. Ki=24 J and Kf=18 J;6 J leaves the kinetic category through other energy forms.
Initial momentum=12 kg·m/s, so vf=3 m/s.
Ki=24 J and Kf=18 J;6 J leaves the kinetic category through other energy forms.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.