Describing Motion — Practice · Grade 12 Science
Chapter: Motion & KinematicsWhat this practice covers
By the end of Describing Motion you should be able to:
- I can describe an object's position relative to a chosen origin and reference frame.
- I can distinguish distance from displacement, and scalars from vectors, and calculate a resultant displacement.
- I can explain how the same motion looks different from different frames of reference.
10 questions, numeric, multiple choice and written answer, each with a worked explanation.
Vocabulary used: position, distance, displacement, scalar, vector, frame of reference.
Problem 1
Answer and explanation
13 km
Distance is total path length: 8 + 5 = 13 km.
Problem 2
Answer and explanation
3 km
Displacement combines opposite directions: 8 − 5 = 3 km east.
Problem 3
- displacement
- speed
- distance
- mass
Answer and explanation
displacement
Displacement has both magnitude and direction, making it a vector. Distance, speed, and mass are scalars.
Problem 4
- Its distance and displacement are both zero
- Its distance is zero but its displacement is large
- Its displacement is zero but its distance equals the track's length
- Its displacement equals the track's length
Answer and explanation
Its displacement is zero but its distance equals the track's length
Returning to the start makes the displacement zero, while the distance traveled equals the full length of the lap.
Problem 5
Answer and explanation
13 m
The legs are perpendicular, so displacement = √(12² + 5²) = √169 = 13 m.
Problem 6
Answer and explanation
Velocity is always measured relative to a frame of reference. In the train's frame, the seated passenger isn't moving, so her velocity is zero. In the platform's frame, she is carried along with the train at, say, 100 km/h. Both are correct within their own frame because there is no absolute resting point in the universe — motion is relative to whatever origin you measure from.
Problem 7
Hints
Final minus initial position should match the signed path sum.
Answer and explanation
Distance 400 m; displacement 0 m.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Coordinates depend on the chosen reference frame; changes can then be interpreted consistently.
Problem 9
Answer and explanation
No. It supplies totals and duration, not the full motion history between events.
An average rate divides a defined change or amount by elapsed time. Average speed is total distance divided by duration; average velocity is displacement divided by duration. The same 4-second journey can therefore have 2 m/s average speed but only +0.5 m/s average velocity. Averaging two segment speeds by ordinary arithmetic works only for equal segment times. For unequal times, use total distance and total duration or the appropriate time-weighted calculation.
No. It supplies totals and duration, not the full motion history between events.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
Distance=16 m and elapsed time=10 s, so average speed=1.6 m/s. Displacement=+8 m, so average velocity=+0.8 m/s. Do not average the segment speeds without time weighting.
Distance=16 m and elapsed time=10 s, so average speed=1.6 m/s.
Displacement=+8 m, so average velocity=+0.8 m/s.
Do not average the segment speeds without time weighting.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.