Dividing Polynomials & the Factor Theorem — Practice

Dividing polynomials is the long division you already know, and a remainder of zero names a factor.

What these questions cover

These questions use 7 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.

Problem 1

Find the remainder when f(x)=x2+3x-5 is divided by x-1.

Worked answer

-1

f(1)=1+3-5=-1

Problem 2

Find the remainder when f(x)=x3-2x+4 is divided by x-2.

Worked answer

8

f(2)=8-4+4=8

Problem 3

What value goes in the synthetic division box when dividing by x+5?

Worked answer

-5

x+5=0 gives x=-5

Problem 4

What value goes in the box when dividing by x-7?

Worked answer

7

x-7=0 gives x=7

Problem 5

If f(3)=0, which of these is a factor of f(x)?

  1. x-3
  2. x+3
  3. 3x
  4. x
Worked answer

x-3

A root at 3 means x-3 divides exactly

Problem 6

Divide x2+7x+12 by x+3.

Worked answer

x+4

x2 ÷ x = x

Multiply back and subtract to get 4x+12

4x ÷ x = 4, remainder 0

Problem 7

Divide x2-x-6 by x-3.

Worked answer

x+2

x2-x-6=(x-3)(x+2)

Problem 8

Divide 2x2+5x-3 by x+3.

Worked answer

2x-1

2x2 ÷ x = 2x

2x(x+3)=2x2+6x, subtract to get -x-3

-x ÷ x = -1, remainder 0

Problem 9

Is x-2 a factor of x3-3x2+4? Answer yes or no.

Worked answer

yes

f(2)=8-12+4=0

A zero remainder means yes

Problem 10

Is x+1 a factor of x3+2x2-5? Answer yes or no.

Worked answer

no

f(-1)=-1+2-5=-4

Not zero, so no

Problem 11

Divide x3-8 by x-2.

Worked answer

x^2+2x+4

Synthetic division with 2: 1, 2, 4, remainder 0

Problem 12

Factor x3-7x+6 completely. Give the three roots, smallest first, separated by commas.

Worked answer

-3,1,2

f(1)=1-7+6=0

Dividing gives x2+x-6=(x+3)(x-2)

Roots -3, 1, 2

Problem 13

One root of x3-4x2+x+6 is -1. Find the other two, smallest first.

Worked answer

2,3

Dividing gives x2-5x+6

(x-2)(x-3)

Problem 14

For what value of k is x-2 a factor of x3+kx-6?

Worked answer

-1

8+2k-6=0

2k=-2 so k=-1

Problem 15

Find the remainder when 2x3-3x2+x-5 is divided by x+1.

Worked answer

-11

2(-1)-3(1)+(-1)-5

=-2-3-1-5=-11

Problem 16

Which list contains every possible rational root of x3-2x2+x-6?

  1. ±1,±2,±3,±6
  2. ±1,±2
  3. ±1,±6
  4. ±2,±3
Worked answer

±1,±2,±3,±6

The constant is -6

Its divisors are 1, 2, 3, 6, positive and negative

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