Probability of Simple Events — Practice

Probability is a fraction: what you want over everything that could happen — as long as every outcome is equally likely.

What these questions cover

These questions use 2 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.

Problem 1

A fair 6-sided die is rolled. Find P(rolling a 5).

Worked answer

1/6

P = 16

Problem 2

A fair 6-sided die is rolled. Find P(even).

Worked answer

1/2

Even faces: 2, 4, 6 — that is 3 of them

36 = 12

Problem 3

A bag holds 3 red and 5 blue marbles. Find P(red).

Worked answer

3/8

3 + 5 = 8 marbles

P(red) = 38

Problem 4

For the same bag (3 red, 5 blue), find P(not red).

Worked answer

5/8

1 - 38 = 58

Same as counting the 5 blue marbles directly.

Problem 5

A spinner has 8 equal sections, 3 of them green. Find P(green).

Worked answer

3/8

P = 38

Problem 6

A bag holds 4 red, 6 blue and 10 green marbles. Find P(not blue).

Worked answer

7/10

Total: 4 + 6 + 10 = 20

Not blue: 4 + 10 = 14

1420 = 710

Problem 7

A spinner has 40 equal sections and P(win) = 15. How many sections are winners?

Worked answer

8

w40 = 15

w = 40 ÷ 5 = 8

Problem 8

A number from 1 to 20 is chosen at random. Find P(multiple of 3).

Worked answer

3/10

Multiples of 3 up to 20: 3, 6, 9, 12, 15, 18 — six of them

620 = 310

Problem 9

Two fair coins are flipped. Find P(exactly one head).

Worked answer

1/2

Sample space: HH, HT, TH, TT — four equally likely outcomes

Exactly one head: HT and TH, so two of them

24 = 12 — not 13, because "one of each" happens two ways.

Problem 10

A spinner is spun 60 times and lands on red 21 times. What is the experimental probability of red, as a decimal?

Worked answer

0.35

2160 = 0.35

Problem 11

If P(A) = 0.35, find P(not A).

Worked answer

0.65

1 - 0.35 = 0.65

Problem 12

A bag has only red and blue marbles, 30 in all, and P(red) = 25. How many are blue?

Worked answer

18

Red: 25 × 30 = 12

Blue: 30 - 12 = 18

Problem 13

Three fair coins are flipped. Find P(at least one head).

Worked answer

7/8

The opposite is no heads at all: TTT

There are 23 = 8 equally likely outcomes, so P(TTT) = 18

1 - 18 = 78

Problem 14

A number from 1 to 30 is chosen at random. Find P(multiple of 4 or 5).

Worked answer

2/5

Multiples of 4: 4, 8, 12, 16, 20, 24, 28 — seven

Multiples of 5: 5, 10, 15, 20, 25, 30 — six

20 is in both lists, so subtract it once: 7 + 6 - 1 = 12

1230 = 25

Problem 15

A bag has 5 red and 7 blue marbles. How many red marbles must be added so that P(red) = 12?

Worked answer

2

5 + x12 + x = 12

Cross-multiply: 10 + 2x = 12 + x

x = 2

Check: 7 red and 7 blue ✓

Problem 16

A spinner is half red and a quarter blue; the rest is split evenly between green and yellow. Find P(green).

Worked answer

1/8

Red and blue take 12 + 14 = 34

That leaves 14 for green and yellow

Split evenly: 14 ÷ 2 = 18

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