Earth & Space Science — Final exam worked answers
Student exam paperAn independent assessment of the core chapters listed below, followed by corrections and discussion.
51 questions · 87 points · suggested 180 minutes
Student instructions
- Suggested time: 120 minutes; allow breaks or accommodations and record them.
- Work independently with a calculator, blank paper and the reference relationships printed in this paper. Grades 9, 11 and 12 may also use the course-linked NYSED reference tables. Use no lesson notes or answer key during an assessed attempt.
- Show reasoning and units for written tasks. All supplied datasets are illustrative; do not present them as measurements you collected.
- Objective items: 1 point each. Written items: 3 points each, one per criterion. A parent or teacher marks the written work; the app never grades an explanation automatically.
- Sample exam: try the whole paper before opening the worked key, then revisit the linked chapters. The sample and final are different papers; this is a course assessment, not an official Regents examination.
Reference relationships
| Relationship or tool | Conditions |
|---|---|
| Maps and budgets | Gradient=elevation change/horizontal distance; storage change=inputs−outputs. |
| Radioactive decay | Remaining parent fraction=(½)ⁿ; age=n×half-life under the stated dating assumptions. |
| Orbital ratios | For one dominant central mass, T²/a³ is constant; compare semimajor axes in the same units. |
| Spectra | Redshift z=(observed wavelength−rest wavelength)/rest wavelength. Match line patterns first. |
| Earth and Space reference tables | Use the linked 2024 NYSED tables: read title, units, legend and conditions; write the table evidence used. |
Coverage and marks
| Chapter | Questions | Points |
|---|---|---|
| Investigating Earth | 1, 2, 3, 4, 5 | 9 |
| Earth’s Interior & Plate Tectonics | 6, 7, 8, 9, 10, 11 | 10 |
| Rocks, Landscapes & Water | 12, 13, 14, 15, 16, 17 | 10 |
| Earth’s History | 18, 19, 20, 21, 22, 23 | 10 |
| Atmosphere & Weather | 24, 25, 26, 27, 28, 29 | 10 |
| Oceans, Carbon & Climate | 30, 31, 32, 33, 34, 35 | 10 |
| Earth, Moon & Solar System | 36, 37, 38, 39, 40, 41 | 10 |
| Stars & the Universe | 42, 43, 44, 45, 46 | 9 |
| Resources & Human Decisions | 47, 48, 49, 50, 51 | 9 |
Parent / teacher marking guide
- Mark objective answers after submission. Written marks remain pending until a parent or teacher applies the three-point criteria.
- Accept scientifically equivalent wording and valid alternative methods. Award stated method credit for a correct model or substitution even if later arithmetic fails.
- A raw percentage describes this paper only; it is not a validated course grade or a certification. Review chapter-level evidence and the learner’s independent explanations.
- Record support and accommodations, save corrections and reassess with different tasks. Do not count copied solutions as independent mastery.
Question 1 · 1 point
Three readings are 8, 10, and 12 mm. Find their mean.
Worked answer
10 mm
(8 + 10 + 12) ÷ 3 = 10.
1 point for the correct objective answer; no written-method marks for this item.
Question 2 · 1 point
Repeated measurements that agree closely with each other but differ from a known standard are
- accurate but imprecise
- precise but inaccurate
- both accurate and precise
- neither
Worked answer
precise but inaccurate
Agreement among repeats is precision; agreement with the standard is accuracy.
1 point for the correct objective answer; no written-method marks for this item.
Question 3 · 1 point
Contour lines drawn close together indicate
- a gentle slope
- a steep slope
- flat ground
- a lake
Worked answer
a steep slope
The same elevation change over a shorter horizontal distance is a steeper gradient.
1 point for the correct objective answer; no written-method marks for this item.
Question 4 · 3 points
A contour map rises from 240 m to 540 m over 6 km horizontally. Find gradient and state why a winding trail can have a different length.
Worked answer
50 m/km; trail length follows bends and need not equal horizontal map separation.
Rise=300 m; gradient=300/6.
Horizontal straight-line separation differs from the route along a trail.
Marking criteria
- 1 point: elevation difference.
- 1 point: gradient with units.
- 1 point: distinguish route length from horizontal separation.
Question 5 · 3 points
A gauge gives rainfall values 28, 30 and 32 mm. Find mean and range; explain why these readings do not rule out a calibration error.
Worked answer
Mean 30 mm, range 28–32 mm; compare with a calibrated reference to check accuracy.
Mean=90/3=30 mm; range 28–32 mm.
Repeated readings can share the same systematic offset.
Marking criteria
- 1 point: correct mean.
- 1 point: correct range.
- 1 point: systematic-error explanation and valid check.
Question 6 · 1 point
Which is the thin, solid, outermost layer of the Earth, where we live?
- The crust
- The mantle
- The outer core
- The inner core
Worked answer
The crust
The crust is Earth's thin, rocky, solid outer layer. Below it lie the thick mantle and the metallic core.
1 point for the correct objective answer; no written-method marks for this item.
Question 7 · 1 point
The outer core is inferred to be liquid because
- it is the hottest layer
- S-waves do not pass through it
- it is closest to the surface
- it contains water
Worked answer
S-waves do not pass through it
S-waves cannot travel through liquid, producing a shadow zone.
1 point for the correct objective answer; no written-method marks for this item.
Question 8 · 1 point
New ocean floor is created at
- subduction zones
- mid-ocean ridges
- transform faults
- continental interiors
Worked answer
mid-ocean ridges
Magma rises at the ridge and solidifies as the plates separate.
1 point for the correct objective answer; no written-method marks for this item.
Question 9 · 1 point
Symmetrical magnetic stripes either side of a mid-ocean ridge are evidence of
- a static sea floor
- sea-floor spreading
- meteorite impacts
- ocean currents
Worked answer
sea-floor spreading
Each stripe records the field direction when that crust formed, mirrored as it spread both ways.
1 point for the correct objective answer; no written-method marks for this item.
Question 10 · 3 points
Ocean-floor rocks become older away from a ridge on both sides and have mirrored magnetic patterns. Explain the plate process and why combining evidence helps.
Worked answer
Seafloor spreading explains both patterns; agreement across independent observations strengthens the model.
New crust forms at the ridge and moves outward.
Symmetric age and magnetic records independently fit spreading.
Marking criteria
- 1 point: new crust at a divergent ridge.
- 1 point: outward movement explaining age pattern.
- 1 point: magnetic evidence and independent-evidence reasoning.
Question 11 · 3 points
Two towns have comparable earthquake shaking hazard but different building strength and population density. Explain risk differences and propose a mitigation with a limit.
Worked answer
The crowded town with weak buildings may have higher risk; reinforcing structures can reduce damage, while shaking hazard remains.
Risk includes exposure and vulnerability as well as hazard.
Reinforcement reduces vulnerability but does not prevent plate movement.
Marking criteria
- 1 point: distinguish hazard, exposure and vulnerability.
- 1 point: supported risk comparison.
- 1 point: mitigation linked to vulnerability and a valid limit.
Question 12 · 1 point
Which of these is NOT one of the five traits required for a substance to be classified as a mineral?
- Naturally occurring
- Made of living tissue
- A solid
- Definite chemical composition
Worked answer
Made of living tissue
Minerals must be inorganic — not created by living organisms; the other three are indeed required traits.
1 point for the correct objective answer; no written-method marks for this item.
Question 13 · 1 point
Streak is a more reliable identifier than colour because streak
- is easier to see
- is unaffected by most impurities
- changes with light
- measures hardness
Worked answer
is unaffected by most impurities
The powdered colour stays consistent while surface colour varies.
1 point for the correct objective answer; no written-method marks for this item.
Question 14 · 1 point
Large interlocking crystals in an igneous rock indicate the magma cooled
- rapidly at the surface
- slowly underground
- in water
- without minerals
Worked answer
slowly underground
Slow cooling gives crystals time to grow.
1 point for the correct objective answer; no written-method marks for this item.
Question 15 · 1 point
Breaking rock into smaller fragments speeds chemical weathering because it increases
- the mass
- the total surface area exposed
- the density
- the hardness
Worked answer
the total surface area exposed
More surface is in contact with water and air.
1 point for the correct objective answer; no written-method marks for this item.
Question 16 · 3 points
A basin receives 200 water units, loses 130 naturally and has 50 withdrawn. Calculate storage change; explain why high porosity alone does not prove rapid groundwater flow.
Worked answer
Storage rises by 20 units in the defined model; porous material can still have low permeability.
Output=130+50=180; change=200−180.
Flow depends on connected pores and fractures, or permeability.
Marking criteria
- 1 point: complete budget calculation.
- 1 point: storage increase with supplied units.
- 1 point: porosity/permeability distinction.
Question 17 · 3 points
A stream slows entering a lake and deposits coarse grains before fine grains. Explain the process and why color alone cannot identify a sampled rock.
Worked answer
Sorting and deposition fit the pattern; a unique rock name requires more than color.
Reduced flow lowers sediment transport capacity.
Deposition depends on particle size, density and shape; rock identification needs texture and mineral evidence.
Marking criteria
- 1 point: erosion/transport versus deposition distinction.
- 1 point: flow and grain explanation with a relevant condition.
- 1 point: multiple-property identification reasoning.
Question 18 · 1 point
Which lists the units of the geologic time scale from LARGEST to smallest?
- Eon, era, period
- Period, era, eon
- Era, eon, period
- Period, eon, era
Worked answer
Eon, era, period
Eons are the biggest divisions, then eras, then periods — like books, chapters, and pages.
1 point for the correct objective answer; no written-method marks for this item.
Question 19 · 1 point
A fault that cuts through several rock layers must be
- older than all of them
- younger than the layers it cuts
- the same age
- undatable
Worked answer
younger than the layers it cuts
A feature must exist before it can be cut.
1 point for the correct objective answer; no written-method marks for this item.
Question 20 · 1 point
After three half-lives, the percentage of original parent isotope remaining is
- 33
- 25
- 12.5
- 6.25
Worked answer
12.5
100 → 50 → 25 → 12.5 percent.
1 point for the correct objective answer; no written-method marks for this item.
Question 21 · 1 point
The most useful index fossil comes from a species that was
- long-lived and local
- short-lived and widespread
- still alive today
- rare everywhere
Worked answer
short-lived and widespread
A narrow time range gives precision and wide distribution allows correlation.
1 point for the correct objective answer; no written-method marks for this item.
Question 22 · 3 points
Beds A, B and C lie bottom to top, an intrusion cuts all three and a fault cuts the intrusion. Order events and explain what an unconformity would indicate.
Worked answer
The fault is youngest; an unconformity represents missing time from erosion or nondeposition, not a known duration from order alone.
Use superposition and cross-cutting relationships.
A→B→C→intrusion→fault under undeformed-bed assumptions.
Marking criteria
- 1 point: bed order.
- 1 point: intrusion then fault.
- 1 point: unconformity and relative/numerical-age distinction.
Question 23 · 3 points
A closed mineral retains 12.5% of its original parent isotope. Half-life is 5 million years. Calculate age and state two dating assumptions.
Worked answer
15 million years; mineral crystallization age need not equal the deposition age of a later sediment containing it.
100→50→25→12.5 is three half-lives.
3×5=15 million years; require known initial conditions and retained relevant isotopes.
Marking criteria
- 1 point: three half-lives.
- 1 point: 15 million-year age.
- 1 point: two valid assumptions or dating-event limitations.
Question 24 · 1 point
Which process changes liquid water into water vapor, mostly from the surface of the ocean?
- Evaporation
- Condensation
- Precipitation
- Infiltration
Worked answer
Evaporation
The sun's energy heats liquid water until it evaporates into invisible water vapor.
1 point for the correct objective answer; no written-method marks for this item.
Question 25 · 1 point
Paving over a field most directly increases
- infiltration
- surface runoff
- transpiration
- groundwater recharge
Worked answer
surface runoff
Water cannot soak in, so more flows across the surface.
1 point for the correct objective answer; no written-method marks for this item.
Question 26 · 1 point
Closely spaced isobars on a weather map indicate
- light winds
- strong winds
- no wind
- high temperature
Worked answer
strong winds
A steep pressure gradient drives faster wind.
1 point for the correct objective answer; no written-method marks for this item.
Question 27 · 1 point
When air temperature equals the dew point, the relative humidity is
- 0 percent
- 50 percent
- 100 percent
- undefined
Worked answer
100 percent
The air is saturated, so condensation begins.
1 point for the correct objective answer; no written-method marks for this item.
Question 28 · 3 points
A front moves 240 km between maps 8 h apart. Find mean speed and explain why that alone does not give an exact later arrival time.
Worked answer
30 km/h over the observed interval; further observations are needed for a reliable arrival estimate.
Speed=240/8=30 km/h.
Later speed and direction can change; local weather and position also matter.
Marking criteria
- 1 point: speed method.
- 1 point: value with units.
- 1 point: valid extrapolation limitation.
Question 29 · 3 points
A dark and light surface warm differently in sunlight. Design a controlled comparison and explain why this small test does not fully explain global winds.
Worked answer
A repeated controlled surface test can isolate an albedo-related mechanism, while global circulation needs a larger model.
Match material, size, starting temperature, sunlight and measurement method.
Different absorption can change warming; global circulation also depends on rotation, geography and pressure gradients.
Marking criteria
- 1 point: fair controlled design.
- 1 point: absorption/energy mechanism.
- 1 point: global-model limitation naming another factor.
Question 30 · 1 point
Which statement correctly describes the difference between weather and climate?
- Weather is day-to-day conditions; climate is the long-term average pattern.
- Weather and climate mean the same thing.
- Climate changes every hour; weather stays the same for decades.
- Weather only applies to storms; climate applies to sunny days.
Worked answer
Weather is day-to-day conditions; climate is the long-term average pattern.
Weather is short-term (today's conditions); climate is the long-term average over decades.
1 point for the correct objective answer; no written-method marks for this item.
Question 31 · 1 point
Greenhouse gases warm the surface because they
- block incoming sunlight
- absorb and re-emit outgoing infrared radiation
- cool the upper atmosphere only
- reflect sunlight
Worked answer
absorb and re-emit outgoing infrared radiation
They are largely transparent to sunlight but absorb the infrared Earth radiates.
1 point for the correct objective answer; no written-method marks for this item.
Question 32 · 1 point
Deep ocean circulation is driven mainly by differences in
- wave height
- temperature and salinity, and so density
- tides
- wind alone
Worked answer
temperature and salinity, and so density
Cold salty water is dense and sinks, driving the overturning.
1 point for the correct objective answer; no written-method marks for this item.
Question 33 · 1 point
Melting sea ice exposing darker ocean is an example of
- negative feedback
- positive feedback
- no feedback
- a carbon sink
Worked answer
positive feedback
Darker water absorbs more energy, causing further melting.
1 point for the correct objective answer; no written-method marks for this item.
Question 34 · 3 points
An annual mean is 15°C. Two graph baselines are 13°C and 14°C. Calculate both anomalies and explain why a baseline change does not change the measured temperature.
Worked answer
+2°C and +1°C respectively; the actual annual mean remains 15°C.
Subtract the stated baseline: 15−13 and 15−14.
A reference shift changes plotted differences, not underlying measurements.
Marking criteria
- 1 point: anomaly definition.
- 1 point: both values with units.
- 1 point: baseline versus underlying-measurement distinction.
Question 35 · 3 points
Warming reduces reflective ice cover and increases absorbed sunlight. Identify the feedback; explain why one cold local day does not test the whole climate trend.
Worked answer
A positive feedback; a cold day can coexist with a long-term warming pattern.
Ice loss lowers albedo and reinforces warming.
Long-term climate trends use many times and locations, not one weather event.
Marking criteria
- 1 point: correctly trace the albedo mechanism.
- 1 point: positive feedback means amplification.
- 1 point: weather/climate scale distinction.
Question 36 · 1 point
What actually causes the Moon's phases?
- Earth's shadow falls on the Moon
- Different amounts of the Moon's sunlit half face Earth as it orbits
- The Moon changes how much light it produces
- Clouds on Earth block our view of the Moon
Worked answer
Different amounts of the Moon's sunlit half face Earth as it orbits
Half the Moon is always lit by the Sun; phases come from how much of that lit half faces Earth as the Moon orbits us.
1 point for the correct objective answer; no written-method marks for this item.
Question 37 · 1 point
Moon phases are caused by
- Earth's shadow
- the changing angle from which we see the Moon's sunlit half
- clouds
- the Moon's own light
Worked answer
the changing angle from which we see the Moon's sunlit half
Half the Moon is always lit; the phase is how much of that half faces Earth.
1 point for the correct objective answer; no written-method marks for this item.
Question 38 · 1 point
Earth is closest to the Sun in early January. This shows that seasons are not caused mainly by
- axial tilt
- distance from the Sun
- day length
- sunlight angle
Worked answer
distance from the Sun
The northern hemisphere has winter then, so distance cannot be the cause.
1 point for the correct objective answer; no written-method marks for this item.
Question 39 · 1 point
Astronauts float on a space station because they and the station are
- beyond Earth's gravity
- falling freely around Earth together
- weightless objects
- shielded from gravity
Worked answer
falling freely around Earth together
Gravity is still strong in low orbit; continuous free fall produces the floating.
1 point for the correct objective answer; no written-method marks for this item.
Question 40 · 3 points
Explain why full moons are usually not eclipsed and why opposite hemispheres have opposite seasons.
Worked answer
Orbital tilt limits eclipses; Earth's tilt, rather than changing Sun distance, explains opposite seasons.
The lunar orbit's tilt usually prevents passage through Earth's shadow.
Earth's axial tilt changes day length and Sun angle in opposite hemispheres.
Marking criteria
- 1 point: phase/eclipse distinction.
- 1 point: lunar-orbit tilt.
- 1 point: season mechanism involving axial tilt and illumination.
Question 41 · 3 points
For one star, planet B has semimajor axis 9 times planet A's. Find the period ratio using T²∝a³ and explain why gravity does not cancel in a circular orbit.
Worked answer
27 times the period; net inward force is needed, not canceled by a real outward force in an inertial model.
Period ratio=√(9³)=27.
Gravity supplies inward acceleration that changes velocity direction.
Marking criteria
- 1 point: Kepler ratio setup.
- 1 point: ratio 27 and same-star condition.
- 1 point: inward acceleration/velocity-direction explanation.
Question 42 · 1 point
The Sun’s main energy source is…
- coal combustion
- nuclear fusion
- reflected moonlight
- friction with air
Worked answer
nuclear fusion
Hydrogen fusion supplies energy in its core.
1 point for the correct objective answer; no written-method marks for this item.
Question 43 · 1 point
Elements heavier than iron are formed mainly
- in ordinary main-sequence fusion
- in supernovae and similar extreme events
- in planets
- in comets
Worked answer
in supernovae and similar extreme events
Fusion beyond iron absorbs energy, so extreme conditions are required.
1 point for the correct objective answer; no written-method marks for this item.
Question 44 · 1 point
That more distant galaxies show greater redshift is evidence for
- Earth at the centre
- an expanding universe
- a static universe
- measurement error
Worked answer
an expanding universe
Every observer in a uniformly expanding space sees the same pattern.
1 point for the correct objective answer; no written-method marks for this item.
Question 45 · 3 points
A known spectral line at 600 nm appears at 612 nm. Calculate z and explain why several matching lines are useful.
Worked answer
z=0.02; multiple lines reduce ambiguous identification. This alone is not a complete cosmological history.
z=(612−600)/600=0.02.
A matched line pattern tests identification and shift consistency.
Marking criteria
- 1 point: redshift formula.
- 1 point: correct dimensionless value.
- 1 point: line-pattern evidence and stated limitation.
Question 46 · 3 points
A star is cooler than another but much more luminous. Explain what this suggests about size and why apparent brightness alone cannot settle the comparison.
Worked answer
The cool luminous star likely has a larger radiating surface; luminosity requires distance-aware evidence.
Lower surface temperature means lower emission per area in the model.
High total output needs greater emitting area; apparent brightness also depends on distance.
Marking criteria
- 1 point: luminosity versus apparent brightness.
- 1 point: surface-temperature/emitting-area reasoning.
- 1 point: role of distance or H–R diagram evidence.
Question 47 · 1 point
Which of these is a renewable resource?
- Coal
- Wind
- Natural gas
- Copper ore
Worked answer
Wind
Wind is continuously produced by uneven heating of Earth's atmosphere, so it's renewable on a human timescale.
1 point for the correct objective answer; no written-method marks for this item.
Question 48 · 1 point
A renewable resource can still be depleted if it is
- used at all
- used faster than it is replenished
- stored
- labelled renewable
Worked answer
used faster than it is replenished
Fish stocks and aquifers renew but can be exhausted by overuse.
1 point for the correct objective answer; no written-method marks for this item.
Question 49 · 1 point
The strongest evidence that a conservation measure worked is a recovery measured against
- public opinion
- a baseline and an untreated comparison site
- the project's cost
- the number of volunteers
Worked answer
a baseline and an untreated comparison site
Only a baseline and a control separate the measure's effect from background change.
1 point for the correct objective answer; no written-method marks for this item.
Question 50 · 3 points
A renewable forest gains 15 wood units yearly and loses 22 to harvest. Find stock change and explain why renewable does not mean unlimited.
Worked answer
The stock falls by 7 units/year despite ongoing regrowth.
Change=15−22=−7 units/year.
Replacement is slower than use in the supplied model.
Marking criteria
- 1 point: budget method.
- 1 point: −7 units/year.
- 1 point: timescale-based renewable/depletion explanation.
Question 51 · 3 points
Runoff design A reduces modeled flow from 200 to 150 mL; B reduces it to 120 mL. Compare percentages and recommend additional evidence before adopting B.
Worked answer
B reduces more runoff in this model, but adoption requires broader evidence and monitoring.
A reduction=50/200=25%; B=80/200=40%.
Compare costs, habitat, maintenance and scaling to real storms under equivalent conditions.
Marking criteria
- 1 point: both percentage reductions.
- 1 point: equivalent-condition model comparison.
- 1 point: at least two relevant additional criteria or limits.