Physical Science: Chemistry — Sample exam worked answers

Student exam paper

A rehearsal paper with separate worked solutions; use it before the final.

24 questions · 48 points · suggested 90 minutes

Student instructions

  1. Suggested time: 90 minutes; allow breaks or accommodations and record them.
  2. Work independently with a calculator, blank paper and the reference relationships printed in this paper. Grades 9, 11 and 12 may also use the course-linked NYSED reference tables. Use no lesson notes or answer key during an assessed attempt.
  3. Show reasoning and units for written tasks. All supplied datasets are illustrative; do not present them as measurements you collected.
  4. Objective items: 1 point each. Written items: 3 points each, one per criterion. A parent or teacher marks the written work; the app never grades an explanation automatically.
  5. Sample exam: try the whole paper before opening the worked key, then revisit the linked chapters. The sample and final are different papers; this is a course assessment, not an official Regents examination.

Reference relationships

Relationship, constant or referenceUse / conditions
Densityρ=m/V; Mass and volume in consistent units
Amountn=m/Mm; N=nNA; Mm is molar mass, not molarity
ConcentrationM=n/V; M₁V₁=M₂V₂; Solution liters; dilution without reaction or loss
Ideal gasPV=nRT; Kelvin and absolute pressure; R matched to units
Heatingq=mcΔT; qphase=mL; One phase versus phase change
Reaction heatqreaction≈−qsurroundings; Include apparatus/loss terms when needed
Free energyΔG=ΔH−TΔS; Kelvin and matching energy units; not reaction rate
EquilibriumQ, K=products/reactants with powers; Omit pure phases in the school approximation
AciditypH≈−log[H₃O⁺]; Concentration approximation; neutral near 7 at 25°C
BufferpH≈pKa+log([A⁻]/[HA]); Both conjugate species appreciable
Cell potentialE°cell=E°cathode−E°anode; Both table values are reduction potentials
Radioactive parentN=N₀(½)^(t/thalf); Closed parent accounting; statistical model
NA=6.022×10²³ mol⁻¹Avogadro constant, rounded for school calculations
h=6.626×10⁻³⁴ J·sPlanck constant, rounded
c=3.00×10⁸ m/sVacuum light speed, rounded
e=1.602×10⁻¹⁹ CElementary charge magnitude; 1 eV=1.602×10⁻¹⁹ J
g=9.8 m/s²Typical near-surface Earth approximation; use a supplied local value if given
R=8.314 J/(mol·K)Use SI pressure Pa and volume m³
R=0.0821 L·atm/(mol·K)Use atmosphere pressure and liter volume
F≈96485 C/mol electronsFaraday constant
1 u·c²≈931.5 MeVMass-energy conversion for consistent nuclear mass accounting
T(K)=T(°C)+273.15Use 273 only when a question specifies that rounded convention
1 L=1000 mL; 1 mL=1 cm³Volume conversions
1 kWh=3.60×10⁶ JEnergy conversion
cwater≈4.18 J/(g·°C)Approximate liquid-water specific heat in ordinary conditions
Lf,water≈334 J/g; Lv,water≈2260 J/gWater fusion and vaporization near ordinary-pressure transition conditions
H1.008 g/mol
C12.01 g/mol
N14.01 g/mol
O16.00 g/mol
Na22.99 g/mol
Mg24.31 g/mol
Al26.98 g/mol
P30.97 g/mol
S32.06 g/mol
Cl35.45 g/mol
K39.10 g/mol
Ca40.08 g/mol
Fe55.85 g/mol
Cu63.55 g/mol
Zn65.38 g/mol
Ag107.87 g/mol
NH₄⁺ / OH⁻ / NO₃⁻Ammonium +1; hydroxide −1; nitrate −1
CO₃²⁻ / SO₄²⁻ / PO₄³⁻Carbonate −2; sulfate −2; phosphate −3

Coverage and marks

ChapterQuestionsPoints
Investigating Matter1, 24
Atoms, Electrons & Periodicity3, 44
Bonding, Formulas & Molecular Structure5, 64
Reactions, Moles & Composition7, 84
Stoichiometry & Yield9, 104
States of Matter & Gases11, 124
Solutions & Dissolved Particles13, 144
Acids, Bases & Titration15, 164
Chemical Energy & Thermodynamics17, 184
Rates & Equilibrium19, 204
Redox, Cells & Nuclear Chemistry21, 224
Organic Chemistry & Material Design23, 244

Parent / teacher marking guide

Question 1 · 1 point

A 18.0 g sample occupies 6.00 mL. Find density.

Worked answer

3 g/mL

18.0/6.00=3.00.

1 point for the correct objective answer; no written-method marks for this item.

Question 2 · 3 points

Recover dry sand and salt from their mixture.

Worked answer

Separate by solubility, filtration, and evaporation.

Add water to dissolve salt.

Filter and dry sand.

Allow the filtrate to evaporate safely in a shallow dish.

Marking criteria

Question 3 · 1 point

Which particle has a mass roughly 1/1836 that of a proton?

  1. nucleus
  2. alpha particle
  3. neutron
  4. electron

Worked answer

electron

Electrons are almost weightless compared with protons and neutrons, so they contribute almost nothing to atomic mass.

1 point for the correct objective answer; no written-method marks for this item.

Question 4 · 3 points

A supplied level diagram has states at 0, 2, and 5 energy units. List downward differences.

Worked answer

Possible differences: 2, 3, and 5 units.

5→2 releases 3 units.

5→0 releases 5; 2→0 releases 2.

Marking criteria

Question 5 · 1 point

When a chlorine atom gains one electron, the ion it forms is called…

  1. a molecule
  2. a cation
  3. an anion
  4. a proton

Worked answer

an anion

Gaining an electron gives the atom a negative charge, making it an anion (Cl⁻).

1 point for the correct objective answer; no written-method marks for this item.

Question 6 · 3 points

Count valence electrons in CO₃²⁻.

Worked answer

24 valence electrons.

C contributes 4 and three O contribute 18.

Add 2 for the negative charge.

Marking criteria

Question 7 · 1 point

Which equation represents a combustion reaction?

  1. CaCO₃ → CaO + CO₂
  2. CH₄ + 2O₂ → CO₂ + 2H₂O
  3. AgNO₃ + NaCl → AgCl + NaNO₃
  4. 2Na + Cl₂ → 2NaCl

Worked answer

CH₄ + 2O₂ → CO₂ + 2H₂O

A fuel (methane) reacting with oxygen to give carbon dioxide and water is complete combustion.

1 point for the correct objective answer; no written-method marks for this item.

Question 8 · 3 points

Would mixing aqueous NaNO₃ and KCl create a precipitate in the usual dilute model?

Worked answer

No net precipitation reaction.

Both possible products KNO₃ and NaCl are soluble.

All ions remain dissolved.

Marking criteria

Question 9 · 1 point

For 2H₂ + O₂ → 2H₂O, how many moles of water form from 4.0 mol of hydrogen reacting with excess oxygen?

Worked answer

4 mol

The mole ratio of H₂O to H₂ is 2 : 2 = 1 : 1, so 4.0 mol H₂ → 4.0 mol H₂O.

1 point for the correct objective answer; no written-method marks for this item.

Question 10 · 3 points

Mix .010 mol HCl and .006 mol NaOH. Find acid excess.

Worked answer

0.004 mol HCl equivalent remains.

Ratio is 1:1.

NaOH limits and consumes .006 mol acid.

Subtract .010−.006.

Marking criteria

Question 11 · 1 point

In the ideal-gas particle model, which state has particles far apart with intermolecular forces treated as negligible?

  1. solid
  2. liquid
  3. gas
  4. they are identical in all states

Worked answer

gas

In a gas, kinetic energy dominates: particles spread far apart and move quickly with almost no attraction between them.

1 point for the correct objective answer; no written-method marks for this item.

Question 12 · 3 points

Why does boiling water not keep warming under fixed pressure?

Worked answer

Phase-change energy increases internal energy without a comparable temperature rise.

Energy is still being transferred.

It largely separates molecules into gas during phase coexistence.

Marking criteria

Question 13 · 1 point

A solution that contains the maximum amount of dissolved solute at a given temperature is described as…

  1. nonpolar
  2. unsaturated
  3. saturated
  4. dilute

Worked answer

saturated

A saturated solution holds all the solute it can at that temperature.

1 point for the correct objective answer; no written-method marks for this item.

Question 14 · 3 points

Compare equal molality NaCl and sugar ideally.

Worked answer

NaCl gives roughly twice the depression in the ideal dilute model.

Sugar gives one particle per molecule.

NaCl gives about two ions per formula unit.

Use ΔTf proportional to i.

Marking criteria

Question 15 · 1 point

In the Brønsted-Lowry model, a base is defined as a…

  1. proton donor
  2. proton acceptor
  3. electron donor
  4. hydroxide crystal

Worked answer

proton acceptor

A Brønsted-Lowry base accepts a proton (H⁺).

1 point for the correct objective answer; no written-method marks for this item.

Question 16 · 3 points

Buffer pKa=4.76 and [A⁻]/[HA]=10. Estimate pH.

Worked answer

5.76

Use pH=pKa+log ratio.

log 10(10)=1.

Marking criteria

Question 17 · 1 point

How much heat (in J) is absorbed when 50.0 g of water is warmed from 15.0°C to 35.0°C? (c = 4.18 J/g°C)

Worked answer

4180 J

ΔT = 35.0 − 15.0 = 20.0°C, so q = mcΔT = 50 × 4.18 × 20 = 4180 J.

1 point for the correct objective answer; no written-method marks for this item.

Question 18 · 3 points

ΔH=40kJ/mol and ΔS=.080kJ/mol·K. Find crossover.

Worked answer

500 K, with the constant-value assumption.

At ΔG=0, T=ΔH/ΔS.

40/.080.

Marking criteria

Question 19 · 1 point

According to collision theory, an effective collision requires…

  1. enough energy and the correct orientation
  2. that a catalyst be present
  3. that the reaction be exothermic
  4. only that the particles touch

Worked answer

enough energy and the correct orientation

A collision only produces a reaction if the particles collide with at least the activation energy and are properly oriented.

1 point for the correct objective answer; no written-method marks for this item.

Question 20 · 3 points

For K=4, current Q=.5, predict direction.

Worked answer

Net forward adjustment.

Compare .5 with 4.

Products are low relative to equilibrium ratio.

Marking criteria

Question 21 · 1 point

Find carbon oxidation number in CO₂ using O=−2.

Worked answer

4

x−4=0, x=+4.

1 point for the correct objective answer; no written-method marks for this item.

Question 22 · 3 points

Write the daughter counts for alpha decay of 238U with Z=92.

Worked answer

234Th plus an alpha particle.

Mass number 238−4=234.

Atomic number 92−2=90.

Marking criteria

Question 23 · 1 point

Find hydrogen count for a simple acyclic alkane with seven carbon atoms.

Worked answer

16 H atoms

2×7+2=16.

1 point for the correct objective answer; no written-method marks for this item.

Question 24 · 3 points

Reusable cup production impact is 500 units; disposable impact 10/use, reusable washing 2/use. Find break-even.

Worked answer

At 63 uses the modeled reusable impact is lower.

500+2n=10n.

500=8n; n=62.5.

Use whole completed uses.

Marking criteria

Revisit the covered chapters

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