Life Science: Biology — Sample exam worked answers

Student exam paper

A rehearsal paper with separate worked solutions; use it before the final.

16 questions · 32 points · suggested 90 minutes

Student instructions

  1. Suggested time: 90 minutes; allow breaks or accommodations and record them.
  2. Work independently with a calculator, blank paper and the reference relationships printed in this paper. Grades 9, 11 and 12 may also use the course-linked NYSED reference tables. Use no lesson notes or answer key during an assessed attempt.
  3. Show reasoning and units for written tasks. All supplied datasets are illustrative; do not present them as measurements you collected.
  4. Objective items: 1 point each. Written items: 3 points each, one per criterion. A parent or teacher marks the written work; the app never grades an explanation automatically.
  5. Sample exam: try the whole paper before opening the worked key, then revisit the linked chapters. The sample and final are different papers; this is a course assessment, not an official Regents examination.

Reference relationships

Relationship or toolConditions
Cell geometryCube area=6L², volume=L³, area/volume=6/L. A geometry model simplifies actual shapes.
Genetic probabilitiesSpecify genotypes and the inheritance model. Each offspring is a probability event; ratios are not guaranteed small-family counts.
Population accountingNew population=old+births+immigration−deaths−emigration.
Energy transferNext-level production=available production×the supplied efficiency, not a universal fixed 10%.
Molecular pathwaysReplication copies DNA; transcription makes RNA; translation makes polypeptide. Track matter and energy separately.

Coverage and marks

ChapterQuestionsPoints
Investigating the Chemistry of Life1, 24
Cells, Membranes & Exchange3, 44
Body Systems, Signals & Homeostasis5, 64
Matter & Energy in Living Systems7, 84
Cell Division, Reproduction & Development9, 104
DNA, Inheritance & Gene Expression11, 124
Evolution, Ancestry & Biodiversity13, 144
Ecosystems & Conservation Decisions15, 164

Parent / teacher marking guide

Question 1 · 1 point

To test temperature alone, which factor should also be kept comparable?

  1. Enzyme amount
  2. The measured reaction rate
  3. The graph height
  4. The conclusion

Worked answer

Enzyme amount

Changing enzyme amount would introduce another potential cause.

1 point for the correct objective answer; no written-method marks for this item.

Question 2 · 3 points

Explain why saying ATP provides energy because its bond is broken is incomplete.

Worked answer

Energy availability comes from the whole reaction and coupling mechanism, not bond breaking by itself.

Bond breaking requires an input of energy.

The full reaction forms new interactions and products; its overall free-energy change can be favorable and coupled to work.

Marking criteria

Question 3 · 1 point

A researcher wants to see individual ribosomes, which are about 20 nanometers across. Why won't the best light microscope work?

  1. Its resolution limit (~200 nm) is far larger than a ribosome, so it cannot separate that fine detail no matter how much it magnifies
  2. Light microscopes cannot magnify past 100×
  3. Ribosomes are too large to fit in the field of view
  4. Light microscopes only work on living cells

Worked answer

Its resolution limit (~200 nm) is far larger than a ribosome, so it cannot separate that fine detail no matter how much it magnifies

Magnification and resolution are different. A light microscope's resolution stalls near 200 nm, so a 20 nm ribosome stays a blur; an electron microscope is needed.

1 point for the correct objective answer; no written-method marks for this item.

Question 4 · 3 points

Compare area/volume ratios for cubes of side 1 mm and 2 mm.

Worked answer

The larger cube has half the area per unit volume.

At 1 mm, area=6 and volume=1, ratio=6 mm⁻¹.

At 2 mm, area=24 and volume=8, ratio=3 mm⁻¹.

Marking criteria

Question 5 · 1 point

Homeostasis is best described as

  1. maintaining a stable internal environment despite changes outside
  2. the total lack of any internal change
  3. the process of a cell dividing
  4. the buildup of waste inside a cell

Worked answer

maintaining a stable internal environment despite changes outside

Homeostasis is the active maintenance of stable internal conditions (temperature, pH, glucose, water) even as the outside world changes.

1 point for the correct objective answer; no written-method marks for this item.

Question 6 · 3 points

A bacterial population contains rare resistant variants before treatment. Explain a possible population change after treatment.

Worked answer

Selection can increase resistance frequency; the drug need not intentionally create the useful variant.

Susceptible bacteria are reduced by the treatment.

Resistant survivors can reproduce, increasing the resistant proportion.

Marking criteria

Question 7 · 1 point

What is the main difference between ATP and ADP?

  1. ATP contains DNA while ADP does not
  2. They are identical molecules with different names
  3. ATP has three phosphate groups and ADP has two
  4. ATP has two phosphate groups and ADP has three

Worked answer

ATP has three phosphate groups and ADP has two

ATP has three phosphate groups; ADP has two. Hydrolysis forms ADP and inorganic phosphate.

1 point for the correct objective answer; no written-method marks for this item.

Question 8 · 3 points

Why can a green plant consume oxygen in darkness?

Worked answer

Respiration continues even when light-dependent photosynthesis stops.

Cells still need ATP for maintenance and work.

Aerobic respiration can continue using stored organic molecules when photosynthesis is not occurring.

Marking criteria

Question 9 · 1 point

Which is the correct order of the phases of mitosis?

  1. Anaphase, Metaphase, Prophase, Telophase
  2. Prophase, Metaphase, Anaphase, Telophase
  3. Metaphase, Prophase, Anaphase, Telophase
  4. Telophase, Anaphase, Metaphase, Prophase

Worked answer

Prophase, Metaphase, Anaphase, Telophase

The order is Prophase, Metaphase, Anaphase, Telophase — remembered as PMAT.

1 point for the correct objective answer; no written-method marks for this item.

Question 10 · 3 points

Why does a multicellular embryo need cell signaling as well as cell division?

Worked answer

Signaling organizes specialized tissues rather than only a larger pile of cells.

Division increases cell number.

Signals help coordinate which cells differentiate, move or grow in particular locations.

Marking criteria

Question 11 · 1 point

Which best describes the overall shape of a DNA molecule?

  1. A double helix — a twisted ladder
  2. A single straight line
  3. A flat triangle
  4. A solid sphere

Worked answer

A double helix — a twisted ladder

Two strands wind around each other to form the double-helix, or twisted-ladder, shape.

1 point for the correct objective answer; no written-method marks for this item.

Question 12 · 3 points

A liver cell increases transcription after a hormone signal without changing DNA sequence. Is this a mutation?

Worked answer

No; it is regulation of expression in the supplied scenario.

The described change is in gene use.

A mutation would require a sequence change, which the prompt excludes.

Marking criteria

Question 13 · 1 point

In evolutionary biology, an individual's 'fitness' is best measured by its

  1. physical strength
  2. body size
  3. lifespan
  4. number of surviving, fertile offspring

Worked answer

number of surviving, fertile offspring

Fitness means reproductive success — how many surviving, fertile offspring an individual leaves relative to others — not strength, size, or longevity.

1 point for the correct objective answer; no written-method marks for this item.

Question 14 · 3 points

In a tree, A and B share a recent node; C joins their branch at an older node. Which pair is most closely related?

Worked answer

A and B are the closest pair in the supplied tree.

Trace the shared ancestors rather than the page spacing.

A and B share the most recent node.

Marking criteria

Question 15 · 1 point

A bacterial colony starts with 200 cells and doubles every hour. Growing exponentially, how many cells are there after 4 hours?

Worked answer

3200 cells

N = 200 × 2⁴ = 200 × 16 = 3,200 cells.

1 point for the correct objective answer; no written-method marks for this item.

Question 16 · 3 points

Site A yields 12 species in 1 h; B yields 18 in 4 h. Can you confidently rank their richness?

Worked answer

No confident ranking follows from these counts alone.

Sampling effort differs and rare species need time to detect.

Use comparable effort or a method that accounts for detection before ranking.

Marking criteria

Revisit the covered chapters

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